Problem 11
Question
Use the method of substitution to calculate the indefinite integrals. $$ \int 16 x\left(x^{2}+1\right)^{7} d x $$
Step-by-Step Solution
Verified Answer
The integral is \( (x^2+1)^8 + C \).
1Step 1: Choice of Substitution
The given integral is \( \int 16x(x^2+1)^7 \, dx \). We notice that \( x^2+1 \) is a composite function, so it's suitable for substitution. Let's set \( u = x^2 + 1 \).
2Step 2: Compute the Derivative (du)
To find \( du \), differentiate \( u = x^2 + 1 \) with respect to \( x \). This gives \( du = 2x \, dx \). For substitution, we need \( 16x \, dx \), so let's express this in terms of \( du \): \( 16x \, dx = 8 \, du \).
3Step 3: Substitute and Change Limits
Using the substitution, the integral becomes \( \int 8(u)^7 \, du \) after replacing \( 16x \, dx \) with \( 8 \, du \) and \( (x^2+1)^7 \) with \( u^7 \).
4Step 4: Integrate with respect to u
Now integrate \( 8 \int u^7 \, du \). Use the power rule for integration: \( \int u^n \, du = \frac{u^{n+1}}{n+1} + C \). Applying this, we get \( 8 \times \frac{u^8}{8} + C = u^8 + C \).
5Step 5: Substitute Back to Original Variable
Replace \( u \) with \( x^2 + 1 \) to express the integral in terms of \( x \): \( (x^2 + 1)^8 + C \).
6Step 6: Final Answer
The indefinite integral \( \int 16x(x^2+1)^7 \, dx \) is \( (x^2+1)^8 + C \).
Key Concepts
Method of SubstitutionIntegration by SubstitutionComposite Function
Method of Substitution
The method of substitution is a powerful technique in calculus, which helps to simplify the process of finding indefinite integrals, especially when dealing with composite functions. At its core, the substitution method involves changing variables to make integration more manageable. This is akin to solving a maze by transforming it into a straight line.
When you encounter an integral that looks complicated, such as \( \int 16x(x^2+1)^7 \, dx \), start by identifying parts of the integral that might fit together as a single expression. Here, the expression \( x^2 + 1 \) appears repeatedly, so we choose it for substitution. We set \( u = x^2 + 1 \), and this simplifies our work by reducing the complex integral into an easier form.
When you encounter an integral that looks complicated, such as \( \int 16x(x^2+1)^7 \, dx \), start by identifying parts of the integral that might fit together as a single expression. Here, the expression \( x^2 + 1 \) appears repeatedly, so we choose it for substitution. We set \( u = x^2 + 1 \), and this simplifies our work by reducing the complex integral into an easier form.
- Pick a substitution that simplifies the integral.
- Find the derivative \( du \) to replace \( dx \).
- Express the entire integral in terms of \( u \) and \( du \).
Integration by Substitution
Integration by substitution joins the realms of integration and differentiation elegantly. It's particularly effective when you deal with composite functions, where one function is inside another. This technique can simplify the integral by transforming it into a basic form.
For the integral \( \int 16x(x^2+1)^7 \, dx \), after setting \( u = x^2 + 1 \), you find that \( du = 2x \, dx \). You notice the original integral needs \( 16x \, dx \), but \( du \) only gives you \( 2x \, dx \). So, a small rearrangement is required: multiply \( du \) by 8 to match \( 16x \, dx \). Thus, \( 16x \, dx = 8 \, du \).
For the integral \( \int 16x(x^2+1)^7 \, dx \), after setting \( u = x^2 + 1 \), you find that \( du = 2x \, dx \). You notice the original integral needs \( 16x \, dx \), but \( du \) only gives you \( 2x \, dx \). So, a small rearrangement is required: multiply \( du \) by 8 to match \( 16x \, dx \). Thus, \( 16x \, dx = 8 \, du \).
- The resulting integral of simple form becomes \( \int 8u^7 \, du \).
- Use basic integration rules, like the power rule, to solve.
Composite Function
A composite function, in essence, is a combination of two functions where one function is applied inside another. Think of it as a function within a function. These functions are especially common in calculus and can appear daunting at first, but with the right techniques, they become much easier to handle.
In the exercise, \( x^2 + 1 \) represents the inner function embedded within the larger power, creating another function. This makes \( (x^2 + 1)^7 \) a composite function. Resolving such a function requires identifying the inner and outer layers, which is essential for substitution.
In the exercise, \( x^2 + 1 \) represents the inner function embedded within the larger power, creating another function. This makes \( (x^2 + 1)^7 \) a composite function. Resolving such a function requires identifying the inner and outer layers, which is essential for substitution.
- Identify the inner "core" function you can differentiate: \( u = x^2 + 1 \).
- Place this function as your substitution utility.
- Replace occurrences in the integral to rewrite in simpler terms.
Other exercises in this chapter
Problem 10
P In Exercises \(1-10\), write out the sum, and perform the addition. $$ \sum_{j=0}^{4} 1 /(2 j-3) $$
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A function \(f\) is defined on a specified interval \(I=[a, b] .\) Calculate the area of the region that lies between the vertical lines \(x=a\) and \(x=b\) and
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Suppose that \(\int_{1}^{4} f(x) / 3 d x=2 .\) Evaluate \(\int_{4}^{1} 3 f(x) d x\).
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In Exercises \(11-20,\) calculate \(F(x)=\int_{a}^{x} f(t) d t\) $$ f(t)=3 t^{2}+1 \quad a=-1 $$
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