Problem 11
Question
Use the identities $$ \begin{aligned} \sinh (x+y) &=\sinh x \cosh y+\cosh x \sinh y \\ \cosh (x+y) &=\cosh x \cosh y+\sinh x \sinh y \end{aligned} $$ to show that a. \(\sinh 2 x=2 \sinh x \cosh x\) b. \(\cosh 2 x=\cosh ^{2} x+\sinh ^{2} x\)
Step-by-Step Solution
Verified Answer
a. \(sinh(2x) = 2sinh(x)\cosh(x)\). b. \(cosh(2x) = cosh^2(x) + sinh^2(x)\).
1Step 1: Use the Identity for Sinh
To show the result for part (a), use the identity for hyperbolic sine: \[sinh(x+y) = sinh(x)\cosh(y) + cosh(x)\sinh(y) \]Set \( y = x \) to find \( sinh(2x) \). The identity becomes:\[sinh(2x) = sinh(x)\cosh(x) + cosh(x)\sinh(x) \]
2Step 2: Simplify the Expression for Sinh
Combine the terms from the identity:\[sinh(2x) = sinh(x)\cosh(x) + cosh(x)\sinh(x) = 2sinh(x)\cosh(x) \]This shows the desired expression for \( sinh(2x) \).
3Step 3: Use the Identity for Cosh
To show the result for part (b), use the identity for hyperbolic cosine:\[cosh(x+y) = cosh(x)\cosh(y) + sinh(x)\sinh(y) \]Set \( y = x \) to find \( cosh(2x) \). The identity becomes:\[cosh(2x) = cosh(x)\cosh(x) + sinh(x)\sinh(x) \]
4Step 4: Simplify the Expression for Cosh
Combine the terms from the identity:\[cosh(2x) = cosh^2(x) + sinh^2(x) \]This shows the desired expression for \( cosh(2x) \).
Key Concepts
Hyperbolic IdentitiesSinh FunctionCosh Function
Hyperbolic Identities
Hyperbolic identities are essential tools when dealing with hyperbolic functions. They are analogous to trigonometric identities.
These identities help in simplifying complex expressions involving hyperbolic sine (\sinh) and hyperbolic cosine (\cosh) functions. Two vital hyperbolic identities given are:
By using these identities, complex hyperbolic expressions can be rewritten in simpler forms, just like the step-by-step solution for the problems showed for \(\sinh 2x\) and \(\cosh 2x\). This simplification is essentially achieved through substitution and basic algebraic manipulation.
These identities help in simplifying complex expressions involving hyperbolic sine (\sinh) and hyperbolic cosine (\cosh) functions. Two vital hyperbolic identities given are:
- \( \sinh(x+y) = \sinh x \cosh y + \cosh x \sinh y \)
- \( \cosh(x+y) = \cosh x \cosh y + \sinh x \sinh y \)
By using these identities, complex hyperbolic expressions can be rewritten in simpler forms, just like the step-by-step solution for the problems showed for \(\sinh 2x\) and \(\cosh 2x\). This simplification is essentially achieved through substitution and basic algebraic manipulation.
Sinh Function
The \(\sinh\) function, short for hyperbolic sine, is an analogy to the trigonometric sine function but within the realm of hyperbolas.
The definition of the \(\sinh\) function is given by:
In the specific exercise, using the identity \(\sinh(x+y)\), when we set \(y = x\), the identity becomes \(\sinh 2x = 2 \sinh x \cosh x\).
This shows how the \(\sinh\) function behaves when its input is doubled. By recognizing the repetition of the term \(\sinh x \cosh x\), the solution becomes elegant and clear.
The definition of the \(\sinh\) function is given by:
- \(\sinh x = \frac{e^x - e^{-x}}{2}\)
In the specific exercise, using the identity \(\sinh(x+y)\), when we set \(y = x\), the identity becomes \(\sinh 2x = 2 \sinh x \cosh x\).
This shows how the \(\sinh\) function behaves when its input is doubled. By recognizing the repetition of the term \(\sinh x \cosh x\), the solution becomes elegant and clear.
Cosh Function
The \( \cosh \) function, known as hyperbolic cosine, parallels the trigonometric cosine function but relates to hyperbolas.
Defined as:
In the problem context, setting \( y = x \) in the identity \( \cosh(x + y) \), we discover that \( \cosh 2x = \cosh^2 x + \sinh^2 x \).
This formulation neatly illustrates the inherent properties of the \( \cosh \) function and how it ties with its counterpart, the \( \sinh \) function. This identity also shows us a peek into why hyperbolic functions appear similar yet distinctly different from their trigonometric counterparts.
Defined as:
- \( \cosh x = \frac{e^x + e^{-x}}{2} \)
In the problem context, setting \( y = x \) in the identity \( \cosh(x + y) \), we discover that \( \cosh 2x = \cosh^2 x + \sinh^2 x \).
This formulation neatly illustrates the inherent properties of the \( \cosh \) function and how it ties with its counterpart, the \( \sinh \) function. This identity also shows us a peek into why hyperbolic functions appear similar yet distinctly different from their trigonometric counterparts.
Other exercises in this chapter
Problem 10
In Exercises \(5-36,\) find the derivative of \(y\) with respect to \(x, t,\) or \(\theta,\) as appropriate. $$ y=\ln \frac{10}{x} $$
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