Problem 11
Question
Use the Generalized Power Rule to find the derivative of each function. $$ f(x)=\left(x^{2}+1\right)^{3} $$
Step-by-Step Solution
Verified Answer
The derivative of \( f(x) = (x^2 + 1)^3 \) is \( 6x(x^2 + 1)^2 \).
1Step 1: Identify the Composition Function
The function is given as \( f(x) = (x^2 + 1)^3 \). This is a composition of the outer function \( u^3 \) and the inner function \( u = x^2 + 1 \).
2Step 2: Apply the Generalized Power Rule
Using the generalized power rule \( \frac{d}{dx}[u^n] = n \, u^{n-1} \, \frac{du}{dx} \), identify \( n = 3 \) and \( u = x^2 + 1 \).
3Step 3: Differentiate the Inner Function
Find the derivative of \( u = x^2 + 1 \). The derivative, \( \frac{du}{dx} = 2x \).
4Step 4: Derive Using the Chain Rule
Apply the chain rule: \( \frac{d}{dx}[(x^2 + 1)^3] = 3 \cdot (x^2 + 1)^{3-1} \cdot \frac{d}{dx}(x^2 + 1) \).
5Step 5: Complete the Derivative Calculation
Substitute \( \frac{du}{dx} = 2x \) into the equation: \( 3 \cdot (x^2 + 1)^{2} \cdot 2x = 6x(x^2 + 1)^{2} \). This is the derivative of \( f(x) \).
Key Concepts
Chain RuleComposition FunctionCalculus Derivative
Chain Rule
The chain rule is a formula used to find the derivative of composite functions. A composite function, as we'll discuss, involves one function inside another. In essence, the chain rule helps you "chain" derivatives together in a sequence.
When applying the chain rule, you differentiate the outer function and then multiply it by the derivative of the inner function. This method is crucial for differentiating functions where one function is nested within another. It simplifies the process, making it possible to handle even the most complex compositions.
For example, in the function \(f(x) = (x^2 + 1)^3\), the chain rule allows us to differentiate smoothly by dealing first with the power, then the base function. The goal is to link them correctly using their derivatives.
When applying the chain rule, you differentiate the outer function and then multiply it by the derivative of the inner function. This method is crucial for differentiating functions where one function is nested within another. It simplifies the process, making it possible to handle even the most complex compositions.
For example, in the function \(f(x) = (x^2 + 1)^3\), the chain rule allows us to differentiate smoothly by dealing first with the power, then the base function. The goal is to link them correctly using their derivatives.
Composition Function
A composition function involves two or more functions combined into one. Think of it as a function formed by substituting another function into it. It is fundamental because it transforms how complex equations are solved in calculus.
Taking the exercise's function \(f(x) = (x^2 + 1)^3\), we recognize this as a composition of:
Taking the exercise's function \(f(x) = (x^2 + 1)^3\), we recognize this as a composition of:
- Inner function: \(u = x^2 + 1\)
- Outer function: \(u^3\)
Calculus Derivative
In calculus, a derivative measures how a function changes as its input changes—in simpler terms, how much a specific function "moves" or "slopes." Derivatives are the backbone of understanding changes and rates in a multitude of scientific and engineering applications.
For the function from the exercise, finding the derivative involves determining how \(f(x) = (x^2 + 1)^3\) changes. By using rules such as the generalized power rule and chain rule, we extract the expression \(6x(x^2 + 1)^2\). This represents the rate of change for the function across different values of \(x\).
Derivatives give insight into how functions behave, predict trajectories, optimize solutions, and solve physical problems, making them essential in calculus.
For the function from the exercise, finding the derivative involves determining how \(f(x) = (x^2 + 1)^3\) changes. By using rules such as the generalized power rule and chain rule, we extract the expression \(6x(x^2 + 1)^2\). This represents the rate of change for the function across different values of \(x\).
Derivatives give insight into how functions behave, predict trajectories, optimize solutions, and solve physical problems, making them essential in calculus.
Other exercises in this chapter
Problem 10
Find each limit by graphing the function and using TRACE or TABLE to examine the graph near the indicated \(x\) -value. \(\lim _{x \rightarrow 1.5} \frac{2 x^{2
View solution Problem 10
Find the derivative of each function by using the Product Rule. Simplify your answers. $$ f(x)=6 \sqrt[3]{x}(2 x+1) $$
View solution Problem 11
Find the average rate of change of the given function between the following pairs of \(x\) -values. [Hint: See pages 95-96.] a. \(x=2\) and \(x=4\) b. \(x=2\) a
View solution Problem 11
For each function, find: a. \(f^{\prime \prime}(x)\) and b. \(f^{\prime \prime}(3)\). $$ f(x)=\frac{1}{6 x^{2}} $$
View solution