Problem 11
Question
Use Green's Theorem to evaluate the indicated line integral. \(\oint_{C} \mathbf{F} \cdot d \mathbf{r},\) where \(\mathbf{F}=\left\langle x^{3}-y, x+y^{3}\right\rangle\) and \(C\) is formed by \(y=x^{2}\) and \(y=x\)
Step-by-Step Solution
Verified Answer
To solve this exercise, two approaches were used: direct computation of the line integral over both curves and application of Green's Theorem which gives a double integral over the region bounded by the curves. After calculating both forms, validating the result can be achieved by comparing these two values. If they match, the exercise is solved correctly.
1Step 1: Parameterize the curves
First, parameterize the curves that form the boundary C of the region. The curve \(C_1: y=x\) from (0,0) to (1,1) can be parameterized as \(r_1(t) = \langle t,t \rangle\) with \(t \in [0, 1]\) and the curve \(C_2: y=x^2\) from (1,1) to (0,0) can be parameterized as \(r_2(t) = \langle t,t^2 \rangle\) with \(t \in [1, 0]\).
2Step 2: Compute the integrals for C1 and C2
Use the definition of line integral to compute \(\oint_{C1} \mathbf{F} \cdot r_1'(t) dt\) and \(\oint_{C2} \mathbf{F} \cdot r_2'(t)\). This gives \(\int_0^1 (t^3 - t)\cdot 1 + (t+t^3) \cdot 1 dt \) for \(C1\) and \(\int_1^0 (t^3 - t^2)\cdot 1 + (t+t^3) \cdot 2t dt\) for \(C2\).
3Step 3: Simplification
After solving the integrals individually, add both results together, obtaining the value of the line integral over the curve C.
4Step 4: Apply Green's Theorem
Alternatively, apply Green's Theorem \(\oint_C F \cdot dr = \iint_D (Q_x - P_y) \cdot dA\) where \(F = \langle P, Q \rangle\), and \(\langle P, Q \rangle\) can be written as \( \int_0^1 \int_{x}^{x^2} (3x^2 - 1 - 1 - 3y^2)\, dy\, dx \).
5Step 5: Compare and Validate
Compare the results obtained directly and using Green's theorem. If they match, the calculations are correct.
Key Concepts
Line IntegralCurve ParameterizationMultivariable CalculusVector Fields
Line Integral
In multivariable calculus, a line integral extends the idea of definite integrals to functions of two or more variables. It allows us to integrate functions along a curve. Imagine walking along a path and evaluating a function at each point on that path, then summing those evaluations. In the context of vector fields, the line integral combines the vector field's influence along a path, taking into account both magnitude and direction.
- Notation: Often represented as \( \oint_C \mathbf{F} \cdot d \mathbf{r} \), where \(C\) is the curve.
- Purpose: Used to calculate work done by a force field in moving an object along a path.
Curve Parameterization
Parameterization is a technique used to represent a curve or surface in terms of independent parameters. It translates a curve into a vector function, where each output vector corresponds to a point on the curve. For Green's Theorem, parameterizing the boundary of the region is crucial.
- Basic Idea: Convert curves into a set of equations dependent on a parameter, often \(t\).
Multivariable Calculus
Multivariable calculus extends calculus concepts to functions of several variables. It's the backbone for understanding many real-world phenomena where multiple factors interact. Core elements include partial differentiation, multiple integration, and theorems like Green's.
- Function Complexity: Deals with functions like \(f(x, y)\) or \(f(x, y, z)\).
- Applications: Describes physical phenomena like electromagnetism, fluid dynamics, and more.
Vector Fields
Vector fields assign a vector to every point in a region of space, representing things like fluid flow or electromagnetic fields. They help describe physical phenomena involving both direction and magnitude at every point in space.
- Example: \(\mathbf{F} = \langle x^3 - y, x + y^3 \rangle\), where each point \( (x,y) \) receives a vector.
- Components: Typically split into \(\langle P, Q \rangle \) in two dimensions or \(\langle P, Q, R \rangle \) in three dimensions.
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