Problem 11
Question
Use algebra to find the inverse of the given one-to-one function. $$f(x)=5 x-4$$
Step-by-Step Solution
Verified Answer
Question: Find the inverse of the one-to-one function $$f(x) = 5x - 4$$.
Answer: The inverse function of $$f(x) = 5x - 4$$ is $$f^{-1}(x) = \frac{x + 4}{5}$$.
1Step 1: Replace function notation with a variable
Instead of using function notation (f(x)), we will use a variable, y, to represent the function's output. So the equation becomes:
$$y = 5x - 4$$
2Step 2: Swap the roles of x and y
We are going to replace y with x and x with y to obtain the inverse function. This gives us the equation:
$$x = 5y - 4$$
3Step 3: Solve for y to obtain the inverse function
Now we need to solve for y in terms of x. Follow these steps:
1. Add 4 to both sides of the equation:
$$x + 4 = 5y$$
2. Divide both sides of the equation by 5:
$$\frac{x + 4}{5} = y$$
So the inverse function is:
$$f^{-1}(x) = \frac{x + 4}{5}$$
Key Concepts
One-to-One FunctionAlgebraic ManipulationFunction Notation
One-to-One Function
In the world of mathematics, a **One-to-One Function** is a function where exactly one x-value corresponds to exactly one y-value. This is important because only one-to-one functions have inverses that are also functions.Identifying whether a function is one-to-one can be done using the horizontal line test:- If any horizontal line intersects the graph of the function more than once, the function is not one-to-one.Understanding that the function \(f(x) = 5x - 4\) is one-to-one exposes a critical element: its inverse \(f^{-1}(x)\) is also a function. When you are given such a function, and you're asked to find its inverse, rest assured, you’re dealing with numbers that consistently follow this single-pair relationship.
Algebraic Manipulation
Algebraic Manipulation is a process that essentially involves rearranging an equation to solve for one of its variables. In finding the inverse of a function, algebraic manipulation is used to isolate one variable from the function.Let's break down the process in finding the inverse of \(f(x) = 5x - 4\):- **Step 1**: Replace \(f(x)\) with \(y\) to ease manipulation. The equation becomes \(y = 5x - 4\).
- **Step 2**: Swap \(x\) and \(y\). This is where you switch their places to set the foundation for the inverse: \(x = 5y - 4\).
- **Step 3**: Solve for \(y\) using algebraic rearrangements: - Add 4 to each side: \(x + 4 = 5y\). - Divide every term by 5 to isolate \(y\): \(y = \frac{x + 4}{5}\).
These steps uncover the inverse function, expressing how effectively algebraic rules can be used to find solutions.
- **Step 2**: Swap \(x\) and \(y\). This is where you switch their places to set the foundation for the inverse: \(x = 5y - 4\).
- **Step 3**: Solve for \(y\) using algebraic rearrangements: - Add 4 to each side: \(x + 4 = 5y\). - Divide every term by 5 to isolate \(y\): \(y = \frac{x + 4}{5}\).
These steps uncover the inverse function, expressing how effectively algebraic rules can be used to find solutions.
Function Notation
**Function Notation** provides a way to represent functions and their inversions without ambiguity. Rather than writing cumbersome equations, function notation communicates mathematical ideas succinctly.For example, in the function \(f(x) = 5x - 4\), \(f(x)\) signifies the output of the function when input \(x\) is applied.
When finding an inverse, the goal is to reverse this process. The inverse function notation, \(f^{-1}(x)\), provides a clear indication that we’re discussing the reverse operation. The derived expression \(f^{-1}(x) = \frac{x+4}{5}\) conveys that if \(x\) is plugged into the inverse function, the original input for \(f(x)\) is retrieved.**Key Points to Remember:**- Function notation simplifies the relationship between \(x\) and \(f(x)\).- It ensures clarity when discussing functions and their inverses, crucial when performing operations such as differentiation or integration.
When finding an inverse, the goal is to reverse this process. The inverse function notation, \(f^{-1}(x)\), provides a clear indication that we’re discussing the reverse operation. The derived expression \(f^{-1}(x) = \frac{x+4}{5}\) conveys that if \(x\) is plugged into the inverse function, the original input for \(f(x)\) is retrieved.**Key Points to Remember:**- Function notation simplifies the relationship between \(x\) and \(f(x)\).- It ensures clarity when discussing functions and their inverses, crucial when performing operations such as differentiation or integration.
Other exercises in this chapter
Problem 10
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Find the average rate of change of the function f over the given interval. $$f(x)=3+x^{3} \text { from } x=0 \text { to } x=2$$
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Fill in the entries in the following table. If it is impossible to fill in an entry, put an X in it. $$\begin{array}{|c|c|c|c|c|}\hline t & f(t) & g(t)=f(t)-3 &
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