Problem 11
Question
Thorium series. The following decays make up the thorium decay series (the \(X\) 's are unknowns for you to identify): $$^{232} \mathrm{Th} \stackrel{\alpha}{\longrightarrow} X_{1}, \quad^{228} \mathrm{Ra} \stackrel{\beta^{-}}{\longrightarrow}^{228} \mathrm{Ac}, \quad X_{2} \stackrel{\beta^{-}}{\longrightarrow}^{228} \mathrm{Th}$$ $$^{228} \mathrm{Th} \stackrel{x_{3}}{\longrightarrow}^{224} \mathrm{Ra}, \quad^{224} \mathrm{Ra} \stackrel{\alpha}{\longrightarrow}^{220} \mathrm{Rn}, \quad^{220} \mathrm{Rn} \stackrel{\alpha}{\longrightarrow} X_{4}$$ \(X_{5} \stackrel{\alpha}{\longrightarrow}^{212} \mathrm{Pb},\) and \(^{212 \mathrm{Pb}} \stackrel{x_{6}}{\longrightarrow}^{212} \mathrm{Bi} .\) The \(^{212} \mathrm{Bi}\) then decays by an \(\alpha\) decay and a \(\beta^{-}\) decay, which can occur in either order \((\alpha\) followed by \(\beta\) or \(\beta\) followed by \(\alpha)\) . (a) Identify each of the six unknowns \((X_{1}, X_{2},\) etc. \()\) by nucleon number, atomic number, neutron number, and name. (b) Write out the decays of \(^{212} \mathrm{Bi}\) and indicate the end product of this series. (For some guidance, see the discussion under "Decay Series" in Section \(30.3 . )(\mathrm{c})\) Draw a Segre chart for the thorium series, similar to the one shown in Figure \(30.5 .\)
Step-by-Step Solution
VerifiedKey Concepts
Alpha Decay
In the thorium decay series, several steps involve alpha decay, such as the transition from \[^{232} \text{Th} \rightarrow ^{228} \text{Ra}\] and \[^{224} \text{Ra} \rightarrow ^{220} \text{Rn}\]. To identify the new element formed, you can think of it like shedding small parts of the nucleus, leaving you with a slightly lighter and less positively charged core. The beauty of alpha decay lies in its predictability as the nucleus steadily shifts backwards to a stable state, like our end product of lead (Pb).
Beta Decay
Within the thorium decay series, beta decay contributes to transitions such as \[^{228} \text{Ra} \rightarrow ^{228} \text{Ac}\]and \[^{212} \text{Pb} \rightarrow ^{212} \text{Bi}\].In these processes, the elements are effectively increasing their proton count to become new elements. Think about beta decay as a domino effect, where a neutron's change directly impacts the identity of the atom, nudging it closer to stability.
Nuclear Chemistry
Understanding nuclear chemistry allows us to predict the behavior of unstable isotopes and to harness nuclear processes for various applications, such as energy generation. This part of chemistry uniquely combines aspects of physics and chemistry to explain phenomena at an atomic level, providing insights not only into decay processes but also into the forces that stabilize a nucleus.
Transmutation
For example, during alpha decay, the emission of an alpha particle results in a reduction in both atomic and mass numbers, effectively changing the element into another. Similarly, beta decay increases the atomic number, leading to a different element. Through transmutation, radioactive series gradually lead elements towards a stable form. Transmutation is fascinating because it blurs the rigid boundaries of the periodic table, allowing elements to shift identities and stabilize over time.
Radioactive Decay Series
Throughout this series, isotopes systematically release particles, decreasing in energy and gradually transforming into different elements. Each decay chain offers a roadmap of the elemental transition, providing insights into nuclear stability and transformations over time. These series are not just theoretical constructs but also guide us in real-life applications such as nuclear medicine, radiometric dating, and understanding natural radioactive decay occurring on Earth.