Problem 11
Question
The least value of the product \(x y z\) for which the determinant \(\left|\begin{array}{ccc}x & 1 & 1 \\ 1 & y & 1 \\ 1 & 1 & z\end{array}\right|\) is non-negative, is: [Online April 10, 2015] (a) \(-2 \sqrt{2}\) (b) \(-1\) (c) \(-16 \sqrt{2}\) (d) \(-8\)
Step-by-Step Solution
Verified Answer
The least value of the product \(xyz\) is \(-8\).
1Step 1: Understand the Problem
We are given a determinant of a 3x3 matrix \( \begin{pmatrix} x & 1 & 1 \ 1 & y & 1 \ 1 & 1 & z \end{pmatrix} \). We need to find the least value of the product \( xyz \) such that the determinant is non-negative.
2Step 2: Write the Determinant Expression
Calculate the determinant of the matrix:\[ \left| \begin{array}{ccc} x & 1 & 1 \ 1 & y & 1 \ 1 & 1 & z \end{array} \right| = x(yz - 1) - 1(z - 1) + 1(1-y) \].
3Step 3: Simplify the Determinant Formula
Substitute the expansions in place in the determinant formula:\[ = xyz - x - z + 1 + 1 - y \]\[ = xyz - x - y - z + 2 \].
4Step 4: Set Inequality for Non-Negativity
Set the equation to be greater than or equal to zero for the determinant to remain non-negative:\[ xyz - x - y - z + 2 \geq 0 \].
5Step 5: Analyze Via Substitution
Try substituting small integer values for \(x, y,\) and \(z\) that minimize the product \(xyz\), ensuring that the inequality is satisfied. Testing \(x = y = z = -2\) makes the product \(xyz = -2 \times -2 \times -2 = -8\) and satisfies the inequality since\[ -8 - (-2) - (-2) - (-2) + 2 = 0 \] which is non-negative.
Key Concepts
3x3 MatrixNon-negative DeterminantMatrix AlgebraProduct Minimization
3x3 Matrix
A 3x3 matrix is a simple concept from linear algebra. It consists of three rows and three columns.This gives nine elements in total. Mathematicians and scientists often use these matrices to solve linear equations and model real-world phenomena.
In this case, we are working with a specific 3x3 matrix:
To solve problems involving matrices, it's essential to become familiar with this type of arrangement and practice calculating their determinants.
In this case, we are working with a specific 3x3 matrix:
- First row: \( x, 1, 1 \)
- Second row: \( 1, y, 1 \)
- Third row: \( 1, 1, z \)
To solve problems involving matrices, it's essential to become familiar with this type of arrangement and practice calculating their determinants.
Non-negative Determinant
A determinant is a special number calculated from a square matrix. It reflects certain properties of the matrix, such as invertibility.When we talk about a non-negative determinant, we mean that the determinant value is either zero or a positive number.
For matrices, non-negative determinants are significant because:
For matrices, non-negative determinants are significant because:
- They imply the system of equations represented by the matrix has solutions.
- They help determine if a matrix is invertible or singular (non-invertible).
Matrix Algebra
Matrix algebra deals with operations on matrices, including addition, multiplication, and calculating determinants.These operations play a crucial role in various fields, from computer science to engineering.
To find the least product \( x y z \) in the given challenge, the steps involve:
To find the least product \( x y z \) in the given challenge, the steps involve:
- Understanding and computing the determinant of the matrix.
- Ensuring that the result of operations like multiplication and subtraction maintains the required conditions (e.g., non-negativity).
Product Minimization
Minimizing a product like \( x y z \) involves finding the smallest possible value subject to given constraints.These constraints are typically derived from algebraic conditions, as in our example with the non-negative determinant.
The key steps for product minimization in this context are:
The key steps for product minimization in this context are:
- Establishing an inequality based on the determinant condition.
- Substituting values thoughtfully to test which combinations yield the smallest acceptable product.
Other exercises in this chapter
Problem 8
If \(\mathrm{S}=\left\\{\mathrm{x} \in[0,2 \pi]:\left|\begin{array}{ccc}0 & \cos x & -\sin x \\ \sin x & 0 & \cos x \\ \cos x & \sin x & 0\end{array}\right|=0\r
View solution Problem 10
if \(\left|\begin{array}{ccc}x^{2}+x & x+1 & x-2 \\ 2 x^{2}+3 x-1 & 3 x & 3 x-3 \\ x^{2}+2 x+3 & 2 x-1 & 2 x-1\end{array}\right|=a x-12\), then ' \(a\) ' is equ
View solution Problem 12
If \(\mathrm{f}(\theta)=\left|\begin{array}{ccc}1 & \cos \theta & 1 \\ -\sin \theta & 1 & -\cos \theta \\ -1 & \sin \theta & 1\end{array}\right|\) and \(\mathrm
View solution Problem 13
If \(\mathrm{B}\) is a \(3 \times 3\) matrix such that \(\mathrm{B}^{2}=0\), then det. \(\left[(\mathrm{I}+\mathrm{B})^{50}-50 \mathrm{~B}\right]\) is equal to:
View solution