Problem 11
Question
The Cannizzaro reaction is a disproportionation that takes place in strongly basic solution and converts aromatic aldehydes to the corresponding benzyl alcohol and sodium benzoate. $$ 2 \mathrm{ArCH}=\mathrm{O}+\mathrm{NaOH} \longrightarrow \mathrm{ArCH}_{2} \mathrm{OH}+\mathrm{ArCO}_{2} \mathrm{Na} $$ Several mechanisms, all of which involve a hydride transfer as a key step, have been postulated. On the basis of the following information, formulate one or more mechanisms that would be consistent with all the data provided. Indicate the significance of each observation with respect to the mechanism(s) you postulate. 1\. When the reaction is carried out in \(\mathrm{D}_{2} \mathrm{O}\), the benzyl alcohol contains no deuterium in the methylene group. 2\. When the reaction is carried out in \(\mathrm{H}_{2}{\underline{\phantom{xx}}}^{18} \mathrm{O}\), both the benzyl alcohol and sodium benzoate contain \({ }^{18} \mathrm{O}\). 3\. The overall reaction rate is given by the expression $$ \text { Rate }=k_{\mathrm{obs}}[\mathrm{Ph} \mathrm{CH}=\mathrm{O}]^{2}\left[{ }^{-} \mathrm{OH}\right] $$ 4\. The rates of substituted benzaldehydes are correlated by a Hammet LFER with \(\rho=+3.76\) 5\. The solvent isotope effect \(k_{\mathrm{D} 2 \mathrm{O}} / k_{\mathrm{H} 2 O}=1.90\)
Step-by-Step Solution
VerifiedKey Concepts
Disproportionation
The aldehyde acts as both an electron donor and an electron acceptor. One aldehyde molecule gets reduced to benzyl alcohol, while the other is oxidized to sodium benzoate. The term "disproportionation" highlights that both the oxidation and reduction processes occur within the same molecular setting, transforming the reactant into two different products.
This type of reaction requires all of the following:
- A high pH environment, typically provided by a strong base such as sodium hydroxide (NaOH).
- Inert reaction conditions that prevent side reactions.
- Careful management of temperature to maintain reaction efficiency and yield.
Hydride Transfer
What makes this reaction unique is the involvement of the solvent molecules. From the given observations:
- Observation 1 shows no deuterium incorporation when the reaction is in D₂O, suggesting hydride transfer doesn't involve solvent hydrogen atoms.
Understanding hydride transfer's role in reactions like the Cannizzaro is crucial as it points to a single, important transformation step rather than a multistep sequence, streamlining the mechanism and clarifying solvent involvement.
Reaction Mechanism
- Observation 3, where the reaction's rate law shows dependence on the square of the aldehyde concentration:
Rate = k_{\text{obs}}{[\mathrm{PhCH}=\mathrm{O}]^2}[\mathrm{OH}^-].A logical mechanism involves several phases:
- Initially, a nucleophilic hydroxide ion attacks the carbonyl group of the aldehyde, leading to the formation of a tetrahedral intermediate.
- This intermediate facilitates the hydride transfer to another aldehyde molecule.
- The transition state of this reaction might exhibit a significant charge build-up, supported by the Hammet correlation with a positive \(\rho=+3.76\), indicating electron withdrawal.
Hammet Correlation
In the Cannizzaro reaction, a positive \(\rho\) value of +3.76 denotes a substantial sensitivity to electron-withdrawing groups. Here's what this means:
- Such a high \(\rho\) value indicates considerable negative charge development on the aromatic ring in the transition state.
- The reaction proceeds faster when the aromatic ring has substituents that withdraw electrons, stabilizing the intermediate.