Problem 11
Question
$$ \text { For Problems 1-32, solve each equation. (Objective 1) } $$ $$ \frac{x}{x-4}-\frac{2 x}{x+4}=-1 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = \frac{4}{3} \).
1Step 1: Identify the Common Denominator
The given equation is \( \frac{x}{x-4} - \frac{2x}{x+4} = -1 \). To solve this, we first need to find a common denominator to combine the fractions. The denominators are \( x-4 \) and \( x+4 \). Therefore, the common denominator is \( (x-4)(x+4) \).
2Step 2: Rewrite Each Fraction
Rewrite each fraction with the common denominator: \( \frac{x(x+4)}{(x-4)(x+4)} - \frac{2x(x-4)}{(x-4)(x+4)} \).
3Step 3: Combine the Fractions
Since both fractions now have the same denominator, we can combine them: \( \frac{x(x+4) - 2x(x-4)}{(x-4)(x+4)} = -1 \).
4Step 4: Simplify the Numerator
Distribute and simplify the numerator: \( x^2 + 4x - (2x^2 - 8x) = x^2 + 4x - 2x^2 + 8x = -x^2 + 12x \). So the equation becomes \( \frac{-x^2 + 12x}{(x-4)(x+4)} = -1 \).
5Step 5: Eliminate the Denominator
To eliminate the denominator, multiply both sides of the equation by \( (x-4)(x+4) \) to get \( -x^2 + 12x = - (x-4)(x+4) \).
6Step 6: Apply the Difference of Squares
Use the difference of squares formula: \( (x-4)(x+4) = x^2 - 16 \). Substitute in to get \( -x^2 + 12x = -x^2 + 16 \).
7Step 7: Solve for x
Set the equation to zero and solve: \( -x^2 + 12x + x^2 - 16 = 0 \), simplifying to \( 12x - 16 = 0 \). Solve for \( x \) by adding 16 to both sides, yielding \( 12x = 16 \), then divide by 12 to find \( x = \frac{4}{3} \).
8Step 8: Verify the Solution
Verify that \( x = \frac{4}{3} \) is not an extraneous solution by checking it doesn't make any denominator zero: \( x-4 eq 0 \) and \( x+4 eq 0 \) for \( x = \frac{4}{3} \).
Key Concepts
Common DenominatorDifference of SquaresSimplifying Expressions
Common Denominator
When solving equations that involve fractions, finding a common denominator is essential. In simple terms, a common denominator allows different fractions to be expressed over the same base, making addition or subtraction possible.
To illustrate, consider this equation: \( \frac{x}{x-4} - \frac{2x}{x+4} = -1 \). Here, the denominators are \( x-4 \) and \( x+4 \).
Identifying the common denominator involves:
Once you've rewritten each term to have the common denominator, simplification can begin. This makes solving such algebraic equations simpler and more straightforward.
To illustrate, consider this equation: \( \frac{x}{x-4} - \frac{2x}{x+4} = -1 \). Here, the denominators are \( x-4 \) and \( x+4 \).
Identifying the common denominator involves:
- Taking both denominators \( (x-4) \) and \( (x+4) \)
- Multiplying them together to get \( (x-4)(x+4) \)
Once you've rewritten each term to have the common denominator, simplification can begin. This makes solving such algebraic equations simpler and more straightforward.
Difference of Squares
The difference of squares is a fundamental algebraic identity that is often used to simplify expressions. It is expressed as \( a^2 - b^2 = (a-b)(a+b) \).
In our specific problem, we see the expression \( (x-4)(x+4) \) appear, which is a textbook example of the difference of squares:
Understanding this helps students to both recognize patterns and solve more intricate algebraic equations quickly.
In our specific problem, we see the expression \( (x-4)(x+4) \) appear, which is a textbook example of the difference of squares:
- Here, \( a = x \) and \( b = 4 \).
- Using the identity, \( x^2 - 16 \) simplifies to \( (x-4)(x+4) \).
Understanding this helps students to both recognize patterns and solve more intricate algebraic equations quickly.
Simplifying Expressions
Simplifying an algebraic expression is a skill that involves condensing it to its simplest form. This process makes the evaluation of equations more straightforward, as fewer terms are involved.
For example, in our initial problem, after finding a common denominator and applying the difference of squares, the expression becomes \( \frac{-x^2 + 12x}{(x-4)(x+4)} = -1 \). To simplify further, tackle the numerator first:
Remember, simplification involves:
For example, in our initial problem, after finding a common denominator and applying the difference of squares, the expression becomes \( \frac{-x^2 + 12x}{(x-4)(x+4)} = -1 \). To simplify further, tackle the numerator first:
- Distribute and combine like terms: \( x^2 + 4x - 2x^2 + 8x = -x^2 + 12x \).
Remember, simplification involves:
- Combining like terms
- Reducing the number of operations
- Making the expression easy to solve or comprehend
Other exercises in this chapter
Problem 11
Simplify each algebraic fraction. $$\frac{32 x y^{2} z^{3}}{72 y z^{4}}$$
View solution Problem 11
For Problems 1-40, perform the indicated operations and express answers in simplest form. $$ \frac{3}{x^{2}-16}+\frac{5}{x+4} $$
View solution Problem 11
\(\frac{x-4}{8}-\frac{x+5}{4}=3\)
View solution Problem 12
Perform the indicated multiplications and divisions and express your answers in simplest form. $$\frac{4 x}{11 y} \div \frac{12 x}{33}$$
View solution