Problem 11
Question
Solve the system by the method of elimination. Label each line with its equation. $$\left\\{\begin{aligned} x-y &=2 \\ -2 x+2 y &=5 \end{aligned}\right.$$
Step-by-Step Solution
Verified Answer
The system of equations has no solutions.
1Step 1: Balance the Coefficients
Multiply the first equation by 2, which results in \(2x - 2y = 4\). So, now we have two equivalent equations with matching coefficients on x. Now they are: \(2x - 2y = 4\) and \(-2x + 2y = 5\).
2Step 2: Eliminate x by Adding the Equations
Add the two equations \(2x - 2y + (-2x + 2y) = 4 + 5\). The left side simplifies to 0x and the right to 9, resulting in \(0x = 9\). Here, the solution seems impossible as 0 doesn't equal to 9. Hence, this system of equations has no solutions.
3Step 3: Check the Results
As no x or y can satisfy both equations simultaneously, the system of equations is inconsistent and thus, there are no solutions.
Key Concepts
Understanding Systems of EquationsIdentifying Inconsistent SystemsBasics of Linear Equations
Understanding Systems of Equations
Systems of equations are sets of two or more equations where we are tasked with finding values for the variables that will satisfy all equations simultaneously. These are crucial when tackling problems with several dependent variables. Here we focus on a system of two linear equations:
- \( x - y = 2 \)
- \( -2x + 2y = 5 \)
Identifying Inconsistent Systems
An inconsistent system of equations occurs when there are no possible solutions that satisfy all equations simultaneously. Essentially, this happens because the equations represent parallel lines that never intersect on a graph. Let's take a closer look at our example:
- We multiplied the first equation by 2, leading to \(2x - 2y = 4\).
- The second equation is \(-2x + 2y = 5\).
Basics of Linear Equations
Linear equations are the cornerstone of high school algebra. These equations express relationships in a linear manner, forming straight lines when graphed. Each equation typically involves constants and variables, like \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants.
Solving linear equations is about finding the values of \(x\) and \(y\) that make the equation true. In systems of linear equations, as in our problem, each equation describes a line, and we are ultimately looking for a point (or points) where these lines intersect, revealing the solution(s).
However, as we've seen in this exercise, sometimes these lines don't intersect, leading to an inconsistent system. Whether consistent or not, understanding how to manipulate and interpret linear equations is essential for solving real-world problems using algebra.
Solving linear equations is about finding the values of \(x\) and \(y\) that make the equation true. In systems of linear equations, as in our problem, each equation describes a line, and we are ultimately looking for a point (or points) where these lines intersect, revealing the solution(s).
However, as we've seen in this exercise, sometimes these lines don't intersect, leading to an inconsistent system. Whether consistent or not, understanding how to manipulate and interpret linear equations is essential for solving real-world problems using algebra.
Other exercises in this chapter
Problem 11
Determine the dimension of the matrix. $$\left[\begin{array}{rr} 33 & 45 \\ -9 & 20 \end{array}\right]$$
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Solve the system by the method of substitution. Check your solution graphically. $$\left\\{\begin{array}{c} 2 x+y=6 \\ -x+y=0 \end{array}\right.$$
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Equality of Matrices Find \(x\) and \(y\) or \(x, y,\) and \(z.\) $$\left[\begin{array}{rrr} 4 & 5 & 4 \\ 13 & 15 & 3 y \\ 2 & 2 z-6 & 0 \end{array}\right]=\lef
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Determine whether each ordered triple is a solution of the system of equations. \(\left\\{\begin{array}{rr}4 x+y-z= & 0 \\ -8 x-6 y+z= & -\frac{7}{4} \\ 3 x-y &
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