Problem 11
Question
Solve the equation. $$\frac{3+5 x}{5}=\frac{4-x}{7}$$
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{-1}{40}\).
1Step 1: Eliminate the Fractions
To eliminate the fractions, find a common denominator and multiply both sides of the equation by it. The denominators are 5 and 7, so the least common multiple is 35. Multiply both sides by 35:\[35 \cdot \left(\frac{3 + 5x}{5}\right) = 35 \cdot \left(\frac{4 - x}{7}\right)\]This simplifies to:\[7(3 + 5x) = 5(4 - x)\]
2Step 2: Distribute on Both Sides
Distribute the numbers on both sides of the equation:\[7 \cdot 3 + 7 \cdot 5x = 5 \cdot 4 - 5 \cdot x\]Simplifying gives:\[21 + 35x = 20 - 5x\]
3Step 3: Move Variable Terms to One Side
Add \(5x\) to both sides to move all terms containing \(x\) to one side:\[21 + 35x + 5x = 20 - 5x + 5x\]This simplifies to:\[21 + 40x = 20\]
4Step 4: Isolate the Variable Term
Subtract 21 from both sides to isolate the term with \(x\):\[40x = 20 - 21\]This simplifies to:\[40x = -1\]
5Step 5: Solve for x
Divide both sides by 40 to solve for \(x\):\[x = \frac{-1}{40}\]
6Step 6: Verify the Solution
Substitute \(x = \frac{-1}{40}\) back into the original equation to verify. Plug back into:\[\frac{3 + 5\left(\frac{-1}{40}\right)}{5} = \frac{4 - \left(\frac{-1}{40}\right)}{7}\]Verify if both sides are equal:\[\frac{3 - \frac{5}{40}}{5} = \frac{4 + \frac{1}{40}}{7}\]Calculate both sides to ensure they are equal.
Key Concepts
Least Common MultipleDistributive PropertyVariable IsolationFractions in Equations
Least Common Multiple
When you solve rational equations, it is crucial to first eliminate the fractions. One efficient way to do this is by using the Least Common Multiple (LCM) of the denominators. The LCM is the smallest number that both denominators can evenly divide into.
In our problem, the denominators are 5 and 7. The least common multiple of 5 and 7 is 35. By multiplying each term of the equation by 35, you effectively "clear out" the denominators.
In our problem, the denominators are 5 and 7. The least common multiple of 5 and 7 is 35. By multiplying each term of the equation by 35, you effectively "clear out" the denominators.
- Multiply both sides of the equation by 35.
- This removes the denominators and allows for simpler equation solving.
Distributive Property
The distributive property is a key concept not only in solving rational equations, but in algebra in general. This property allows you to apply multiplication across terms inside parentheses.
In our example, after eliminating fractions, we have the equation: \[7(3 + 5x) = 5(4 - x)\]
To simplify:
In our example, after eliminating fractions, we have the equation: \[7(3 + 5x) = 5(4 - x)\]
To simplify:
- Multiply 7 by each term inside the parentheses: \(7 \cdot 3 + 7 \cdot 5x\)
- Similarly, multiply 5 by each term in the parentheses on the other side: \(5 \cdot 4 - 5 \cdot x\)
- The equation simplifies to \(21 + 35x = 20 - 5x\)
Variable Isolation
Variable isolation is a technique that focuses on getting the variable, often represented by \(x\), alone on one side of the equation. This process involves moving terms strategically.
In our equation, the balance achieves this:
In our equation, the balance achieves this:
- Start by adding \(5x\) to both sides to gather all \(x\) terms on one side.
- You then have \(21 + 40x = 20\).
- Subtract 21 from both sides to further isolate \(x\) terms: \(40x = -1\)
Fractions in Equations
Fractions can complicate equations, but they are nothing to fear! They can be systematically managed and solved. In our exercise, fractions are present from the start.
- Fractions are eliminated by using the least common multiple, simplifying the equation.
- This technique converts a fraction equation into a linear equation without fractions, as demonstrated previously.
- By solving equations without fractions, we verify that the solution holds true when plugged back in.
Other exercises in this chapter
Problem 10
Exer. 1-14: Solve the equation by factoring. $$ 4 x^{2}-72 x+324=0 $$
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Six hundred people attended the premiere of a motion picture. Adult tickets cost \(\$ 9\), and children were admitted for \(\$ 6\). If box office receipts total
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Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ 6 x-8>x^{2} $$
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Exer. 3-12: Express the inequality as an interval, and sketch its graph. $$ 5>x \geq-2 $$
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