Problem 11

Question

Solve each equation. $$ 2 x^{2}+18=0 $$

Step-by-Step Solution

Verified
Answer
The solutions are \(3i\) and \(-3i\).
1Step 1: Move the Constant Term
Firstly, subtract 18 from both sides of the equation to isolate the term with the variable.\[2x^2 = -18\]
2Step 2: Divide by the Coefficient
To simplify the equation, divide both sides by 2.\[x^2 = -9\]
3Step 3: Take the Square Root
Take the square root of both sides. Don't forget that taking the square root of a negative number introduces the imaginary unit \(i\), where \(i = \sqrt{-1}\).\[x = \pm \sqrt{-9} = \pm 3i\]
4Step 4: Write the Solutions
The solutions to the equation are the complex numbers.\[x = 3i \quad \text{or} \quad x = -3i\]

Key Concepts

Imaginary UnitQuadratic EquationsSquare Root of Negative Number
Imaginary Unit
In mathematics, particularly in the field of complex numbers, we encounter the concept of the imaginary unit, denoted by \( i \). The imaginary unit is defined as the square root of \( -1 \). This concept might seem a bit abstract at first, but it becomes very useful, especially when dealing with complex numbers.
  • The imaginary unit \( i \) allows us to express complex numbers in the form \( a + bi \), where \( a \) and \( b \) are real numbers.
  • It helps in solving equations that do not have real solutions. For instance, the equation \( x^2 + 1 = 0 \) can't be solved using real numbers. However, using the imaginary unit, the solution is \( x = \pm i \).
Remember, \( i^2 = -1 \), which is a fundamental property used in various mathematical operations involving imaginary numbers.
Quadratic Equations
Quadratic equations are polynomial equations of the second degree, typically in the form \( ax^2 + bx + c = 0 \). These equations appear frequently in algebra and have different methods for solving them, such as factoring, completing the square, or using the quadratic formula.
  • The quadratic formula, \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \), provides the solutions for any quadratic equation.
  • The discriminant, \( b^2 - 4ac \), within the quadratic formula helps to determine the nature of the roots. If it's negative, the solutions are complex numbers.
The given exercise is an example of a quadratic equation where the solution involves complex numbers, illustrating the versatility and scope of quadratic equations.
Square Root of Negative Number
The idea of finding the square root of a negative number is closely tied to the introduction of the imaginary unit. Normally, the square root function is defined only for non-negative values in the real number system. But, the concept of the square root of negative numbers opens up the realm of complex numbers.
  • To compute the square root of a negative number, such as \( -9 \), we break it down to \( \sqrt{9} \times \sqrt{-1} \). This yields \( 3i \), using the property that \( i = \sqrt{-1} \).
  • Complex solutions like \( x = 3i \) and \( x = -3i \) involve considering both the positive and negative roots, just as we do with positive numbers.
The exercise shows how taking the square root of a negative number directly brings us into the territory of imaginary numbers, turning negative roots into valid complex solutions.