Problem 11
Question
Show that \(\arg \left(\frac{1}{x}\right)=-\arg z\)
Step-by-Step Solution
Verified Answer
\(\arg \left(\frac{1}{z}\right) = -\arg z\) is true by polar form analysis.
1Step 1: Understand the Problem
We are asked to show that the argument of the reciprocal of a complex number \(z\) is the negative of the argument of \(z\). This statement is represented by the equation \(\arg \left(\frac{1}{z}\right) = -\arg z\).
2Step 2: Recall the Definition of Argument
The argument of a complex number \(z = a + bi\) is defined as the angle \(\theta\) such that \(\tan \theta = \frac{b}{a}\). This is denoted as \(\arg z\).
3Step 3: Express the Reciprocal in Polar Form
A complex number \(z\) can be expressed in polar form as \(r (\cos \theta + i \sin \theta)\). The reciprocal \(\frac{1}{z}\) is then \(\frac{1}{r} (\cos \theta - i \sin \theta)\), which corresponds to the argument \(-\theta\).
4Step 4: Apply Properties of Argument
Using Euler's formula, \(z = re^{i\theta}\), the reciprocal becomes \(\frac{1}{z} = \frac{1}{r} e^{-i\theta}\). Here, \(\arg e^{-i\theta} = -\theta\).
5Step 5: Conclude the Proof
Thus, \(\arg \left(\frac{1}{z}\right) = -\theta = -\arg z\). Therefore, it is shown that \(\arg \left(\frac{1}{z}\right) = -\arg z\).
Key Concepts
Argument of a Complex NumberPolar FormEuler's Formula
Argument of a Complex Number
The argument of a complex number is a fundamental concept in understanding complex numbers, which are numbers of the form \(z = a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit. The argument of \(z\), denoted as \(\arg z\), is the angle \((\theta)\) that the line representing \(z\) in the complex plane makes with the positive real axis. Simply put, the argument tells you how much you need to rotate from the positive x-axis to get to the line going through \(z\).
Here's how you can find it:
Here's how you can find it:
- The formula for calculating the argument is \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\), which involves the arctangent of the ratio of the imaginary part \(b\) to the real part \(a\).
- The argument \(\theta\) is typically measured in radians ranging from \(-\pi\) to \(\pi\).
- It provides a way to fully describe the location of a complex number along with the magnitude (modulus) of the number.
Polar Form
Representing complex numbers in polar form is both practical and insightful. A complex number \(z = a + bi\) can be expressed as \(r (\cos \theta + i \sin \theta)\), where \(r\) is the modulus of \(z\) and \(\theta\) is the argument.
To transform a complex number to its polar form:
To transform a complex number to its polar form:
- Find the modulus \(r\) of the complex number, calculated as \(\sqrt{a^2 + b^2}\). This modulus measures the distance of the point from the origin in the complex plane.
- Determine the argument \(\theta\), which we discussed earlier, as \(\tan^{-1}\left(\frac{b}{a}\right)\).
- Simplifying the process of multiplying and dividing complex numbers.
- Allowing easy transition to exponential form, which is crucial for certain mathematical operations.
- Makes it easier to visualize and understand rotations and magnitudes in the complex plane.
Euler's Formula
Euler's Formula is one of the most beautiful and important relationships in mathematics. It links complex exponential notation with trigonometry and is stated as \(e^{i\theta} = \cos \theta + i \sin \theta\). This formula provides a way to represent complex numbers in an exponential form, which is highly advantageous in calculations.
When you use Euler's formula, the polar form \(r (\cos \theta + i \sin \theta)\) can be elegantly rewritten as \(re^{i\theta}\). This exponential form simplifies many operations in algebra and calculus involving complex numbers.
Key uses of Euler's formula include:
When you use Euler's formula, the polar form \(r (\cos \theta + i \sin \theta)\) can be elegantly rewritten as \(re^{i\theta}\). This exponential form simplifies many operations in algebra and calculus involving complex numbers.
Key uses of Euler's formula include:
- Efficiently calculating powers and roots of complex numbers.
- Simplifying the computation of products and quotients in complex number operations.
- Providing insight into periodic phenomena in engineering and physics.
Other exercises in this chapter
Problem 10
Show that \(D_{1}(0)\) is connected. Hint: Show that if \(z_{1}\) and \(z_{2}\) lie in \(D_{1}(0)\), then the straight-line segment joining them lies entirely i
View solution Problem 11
Show that if \(z \neq 0\), the four points \(z\), \(\bar{z},-z\), and \(-\bar{z}\) are the vertices of a rectangle with its center at the otigin.
View solution Problem 12
Show that if \(z \neq 0\), the four points \(z, i z,-z\), and \(-i z\) are the vertices of a square with its center at the origin.
View solution Problem 12
If \(1=z_{0}, z_{1}, \ldots, z_{n-1}\) are the \(n\) th roots of unity, prove that \(\left(z-z_{1}\right)\left(z-z_{2}\right) \cdots\left(z-z_{n-1}\right)=1+z+z
View solution