Problem 11
Question
Parameter reduced population models are shown below. In the Ricker equation, find a condition on \(\gamma_{0}\) that will insure that there is a value of \(v\) for which the population is growing the fastest. In the Beverton-Holt equation show that there is no value of \(v\) for which the population is growing the fastest. In the Gompertz equation, find the value of \(v\) for which the population is growing the fastest. $$\text { a. } \quad v^{\prime}=v e^{-v}-\gamma_{0} v \text { Ricker }$$$$\begin{array}{l} \text { b. } \quad v^{\prime}=\frac{v}{1+v} \\\\\text { c. } v^{\prime}=-v \ln (v)\end{array}$$ Beverton-Holt Gompertz The three previous problems have important implications for wildlife management, at least conceptually. Suppose you are managing a wildlife population, salmon, for example, as a renewable resource, and wish to annually harvest as many salmon as possible. If you harvest too severely, the next years spawn will be low, and four years later the harvest will be limited. Your optimum strategy is to maintain the population at the level where the growth is the greatest.
Step-by-Step Solution
VerifiedKey Concepts
Ricker equation
To find where the population is growing the fastest in this model, we need to find the value of \( v \) that maximizes the growth rate \( v' \). This is done by setting the derivative of \( v' \) with respect to \( v \) to zero and solving. In our case, this means finding when \( e^{-v}(1 - v) = \gamma_0 \).
- If \( \gamma_0 \) is too large, the population may not grow quickly as the overriding factor could be population decline due to overcrowding or resource limitation.
- For \( e^{-v}(1-v) \) to be greater than \( \gamma_0 \), certain conditions must be met so the expression remains positive.
Beverton-Holt equation
The structure of the Beverton-Holt equation introduces a form of carrying capacity, which limits the population size. When analyzing this equation, we differentiate with respect to \( v \) to find where this function grows the fastest, expecting a standout point of rapid growth.
Interestingly, differentiating \( \frac{v}{1+v} \) shows us \( \frac{1}{(1+v)^2} \), which is always positive, indicating a monotonic increase as \( v \) increases. This positivity means there is no specific maximum growth value because the rate continuously increases.
- No single \( v \) results in the fastest growth. Instead, it limits the size naturally as it gets larger.
- This model is beneficial to understand equilibria in maximum sustainable yield conditions.
Gompertz equation
In this context, finding the fastest growth involves differentiating \( -v \ln(v) \) to pinpoint where this rate peaks. Solving \( -\ln v - 1 = 0 \), we find that the fastest growth occurs at \( v = \frac{1}{e} \).
- Here, \( \ln(v) = -1 \), which highlights the nature of the Gompertz model as focused on growth deceleration with increasing size.
- This peak explains how systems behave under constraints that naturally regulate their expansion.