Problem 11
Question
\(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}, \mathrm{Mh} \mathrm{O}_{3}\) The reaction, \(3 \mathrm{ClO}^{-}(\mathrm{aq}) \longrightarrow \mathrm{ClO}_{3}^{-}(\mathrm{aq})+\) \(2 \mathrm{Cl}^{-}(\mathrm{aq})\), is an example of [2001S] (a) oxidation reaction (b) reduction reaction (c) disproportionation reaction (d) decomposition reaction
Step-by-Step Solution
Verified Answer
The reaction is a disproportionation reaction (option c).
1Step 1: Define Disproportionation Reaction
A disproportionation reaction is a specific type of redox reaction in which a single substance is simultaneously oxidized and reduced, resulting in two different products.
2Step 2: Analyze the Given Reaction
The reaction is \(3\, \text{ClO}^- (aq) \rightarrow \text{ClO}_3^- (aq) + 2\, \text{Cl}^- (aq)\). Here, notice that the \(\text{ClO}^-\) in the reactants is transformed into two different products: \(\text{ClO}_3^-\) and \(\text{Cl}^-\).
3Step 3: Identify Oxidation and Reduction Elements
Within the reaction, \(\text{ClO}^-\) is being oxidized to form \(\text{ClO}_3^-\) as chlorine's oxidation state increases, and it is being reduced to form \(\text{Cl}^-\) as chlorine's oxidation state decreases.
4Step 4: Conclude the Reaction Type
Since the same substance, \(\text{ClO}^-\), is both oxidized and reduced, this is an example of a disproportionation reaction. This matches the definition provided in Step 1.
Key Concepts
Understanding Oxidation ReactionsGrasping the Concept of Reduction ReactionsExploring Redox Reactions
Understanding Oxidation Reactions
Oxidation reactions are processes in which an atom, ion, or molecule loses electrons, resulting in an increase in its oxidation state. Essentially, during oxidation, there is a shift of electrons away from a particular species.
This can often involve the addition of oxygen or the elimination of hydrogen. To easily remember this, you can use the mnemonic: "OIL RIG" - Oxidation Is Loss (of electrons) and Reduction Is Gain (of electrons).
This can often involve the addition of oxygen or the elimination of hydrogen. To easily remember this, you can use the mnemonic: "OIL RIG" - Oxidation Is Loss (of electrons) and Reduction Is Gain (of electrons).
- For an oxidation reaction to occur, another species often accepts the electrons that are being lost. This typically results in a companion reduction reaction, forming what is known as a redox pair.
- Common examples of oxidation include the rusting of iron, where iron is oxidized to form iron oxide.
Grasping the Concept of Reduction Reactions
Reduction reactions are just the opposite of oxidation reactions. In these reactions, an atom, ion, or molecule gains electrons, leading to a decrease in its oxidation state. This gain of electrons often involves the removal of oxygen or the addition of hydrogen.
Reduction is crucial because it balances the electron transfer in redox reactions. In every redox reaction, while one species is oxidized, another must be reduced. They go hand in hand.
Reduction is crucial because it balances the electron transfer in redox reactions. In every redox reaction, while one species is oxidized, another must be reduced. They go hand in hand.
- An easy way to spot reduction is by looking for a reduction in charge or the addition of electrons in the reaction.
- For example, in the reaction where copper oxide is reduced to metallic copper, electrons are gained by the copper ions to become solid copper.
Exploring Redox Reactions
Redox reactions, or oxidation-reduction reactions, involve the transfer of electrons between two substances. These types of reactions are characterized by the simultaneous occurrence of oxidation and reduction processes.
This dual process ensures that the electrons lost by one species (oxidation) are gained by another (reduction).
This dual process ensures that the electrons lost by one species (oxidation) are gained by another (reduction).
- Redox reactions can be found everywhere, from the batteries that power our gadgets to metabolic processes in living organisms.
- The concept of redox is vital in understanding reaction mechanisms, energy conversions, and electron flow in chemical systems.
Other exercises in this chapter
Problem 8
Oxidation state of sulphur in anions \(\mathrm{SO}_{3}^{2-}, \mathrm{S}_{2} \mathrm{O}_{4}^{2-}\) and \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}\) increases in the or
View solution Problem 9
Consider a titration of potassium dichromate solution with acidified Mohr's salt solution using diphenylamine as indicator. The number of moles of Mohr's salt r
View solution Problem 12
Amongst the following identify the species with an atom in \(+6\) oxidation state [2000S] (a) \(\mathrm{MnO}_{4}^{-}\) (b) \(\mathrm{Cr}(\mathrm{CN})_{6}^{3-}\)
View solution Problem 13
The oxidation number of sulphur in \(\mathrm{S}_{8}, \mathrm{~S}_{2} \mathrm{~F}_{2}, \mathrm{H}_{2} \mathrm{~S}\) respectively, are [1999-2 Marks] (a) \(0,+1\)
View solution