Problem 11
Question
In Exercises \(7-14,\) use \(\log 2 \approx 0.3010, \log 5 \approx 0.6990,\) and \(\log 7 \approx 0.8451\) to evaluate each logarithm without using a calculator. Then check your answer using a calculator. $$\log \sqrt{2}$$
Step-by-Step Solution
Verified Answer
The value of \(\log \sqrt{2}\) is approximately 0.1505
1Step 1: Transform the equation
First, we should transform \(\log \sqrt{2}\) into an easier form. We know that \(\sqrt{2}\) is \(2^{\frac{1}{2}}\), so we transform \(\log \sqrt{2}\) as \(\frac{1}{2} \log 2\).
2Step 2: Substitute the value of \(\log 2\)
In the second step, substitute the given value of \(\log 2\) into our equation from step 1. Hence, we get \(\frac{1}{2} * 0.3010\).
3Step 3: Calculation
In the last step, perform the multiplication operation from step 2. Doing the multiplication of \(\frac{1}{2} * 0.3010\) gets approximately 0.1505.
Key Concepts
Logarithm propertiesLogarithm calculationMathematics problem solving
Logarithm properties
Logarithms have some important properties that simplify mathematical calculations. These properties help in transforming complex expressions into simpler forms. Here, we will focus on the property used in this exercise, which is the power rule.
The power rule of logarithms states that if you have a logarithm of a number raised to a power, you can simplify it by multiplying the logarithm by that power. In mathematical terms:
The power rule of logarithms states that if you have a logarithm of a number raised to a power, you can simplify it by multiplying the logarithm by that power. In mathematical terms:
- \(\log_b (x^n) = n \cdot \log_b x\)
Logarithm calculation
Calculating logarithms can sometimes seem daunting without a calculator. But using known values and logarithm properties makes it manageable. In our specific exercise, after applying the power rule, we transformed the problem into a simple multiplication.
Given \(\log 2 \approx 0.3010\), the expression becomes \(\frac{1}{2} \cdot 0.3010\). To complete the calculation, we perform the multiplication:
Given \(\log 2 \approx 0.3010\), the expression becomes \(\frac{1}{2} \cdot 0.3010\). To complete the calculation, we perform the multiplication:
- Multiply \(\frac{1}{2} \times 0.3010\)
- This equals approximately \(0.1505\)
Mathematics problem solving
Solving mathematical problems like this one requires a combination of understanding and strategy. Start by analyzing the problem and identifying which mathematical rules or properties apply.
In this exercise, recognizing the need for the power rule enabled us to simplify the initial expression. The next step was to substitute the given value, \(\log 2 \approx 0.3010\).
In this exercise, recognizing the need for the power rule enabled us to simplify the initial expression. The next step was to substitute the given value, \(\log 2 \approx 0.3010\).
- Transform complex expressions using known rules
- Substitute given values to simplify calculations
- Perform basic arithmetic to arrive at the solution
Other exercises in this chapter
Problem 11
Solve the exponential equation. Round to three decimal places, when needed. $$4 e^{x}=36$$
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use \(f(t)=10 e^{-t}\) Evaluate \(f(1)\)
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Verify that the given functions are inverses of each other. $$f(x)=6 x ; g(x)=\frac{1}{6} x$$
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Evaluate each expression to four decimal places using a calculator. $$3^{\sqrt{2}}$$
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