Problem 11
Question
In Exercises 11 - 24, use the given values to evaluate (if possible)all six trigonometric functions. \( \sin x = \dfrac{1}{2} \), \( \cos x = \dfrac{\sqrt{3}}{2} \)
Step-by-Step Solution
Verified Answer
The six evaluated trigonometric functions are: \( \sin x = \dfrac{1}{2} \), \( \cos x = \dfrac{\sqrt{3}}{2} \), \( \tan x = \dfrac{1}{\sqrt{3}} \), \( \csc x = 2 \), \( \sec x = \dfrac{2}{\sqrt{3}} \), and \( \cot x = \sqrt{3} \).
1Step 1: Evaluate the Given Functions
The values for \( \sin x \) and \( \cos x \) are already provided: \( \sin x = \dfrac{1}{2} \) and \( \cos x = \dfrac{\sqrt{3}}{2} \).
2Step 2: Evaluate the Remaining Trigonometric Functions
The remaining trigonometric functions can be evaluated based on the given values. Here are the expressions for them: \n\n\t- Tangent function: \( \tan x = \dfrac{\sin x}{\cos x} = \dfrac{\dfrac{1}{2}}{\dfrac{\sqrt{3}}{2}} = \dfrac{1}{\sqrt{3}} \)\n\n\t- Cosecant function: \( \csc x = \dfrac{1}{\sin x} = \dfrac{1}{\dfrac{1}{2}} = 2 \)\n\n\t- Secant function: \( \sec x = \dfrac{1}{\cos x} = \dfrac{1}{\dfrac{\sqrt{3}}{2}} = \dfrac{2}{\sqrt{3}} \)\n\n\t- Cotangent function: \( \cot x = \dfrac{1}{\tan x} = \dfrac{1}{\dfrac{1}{\sqrt{3}}} = \sqrt{3} \)
Key Concepts
sine functioncosine functiontangent functioncosecant functionsecant functioncotangent function
sine function
The sine function is one of the primary trigonometric functions. It is denoted as \( \sin \theta \), where \( \theta \) is an angle in a right triangle.
This function helps in determining the ratio of the length of the side of the triangle opposite to the angle to the length of the hypotenuse.
For example, if given \( \sin x = \frac{1}{2} \), it means the opposite side is half the length of the hypotenuse.
This function helps in determining the ratio of the length of the side of the triangle opposite to the angle to the length of the hypotenuse.
For example, if given \( \sin x = \frac{1}{2} \), it means the opposite side is half the length of the hypotenuse.
- The sine function is periodic, with a period of \( 2\pi \). This periodic nature allows it to repeat its values in cycles.
- Its range is between -1 and 1, inclusive, as it measures ratio based on triangle sides.
cosine function
The cosine function, noted as \( \cos \theta \), complements the sine function. In a right triangle, it represents the ratio of the length of the adjacent side to the hypotenuse.
For instance, \( \cos x = \frac{\sqrt{3}}{2} \), suggests that the adjacent side is \( \frac{\sqrt{3}} \) times as large as half the hypotenuse.
For instance, \( \cos x = \frac{\sqrt{3}}{2} \), suggests that the adjacent side is \( \frac{\sqrt{3}} \) times as large as half the hypotenuse.
- The cosine function is also periodic with a period of \( 2\pi \).
- Its range is identical to that of the sine function, going from -1 to 1.
tangent function
Tangent, denoted as \( \tan \theta \), is another essential trigonometric function. It expresses the ratio of sine to cosine, or more simply, the opposite to adjacent side in a right triangle.
In our exercise, \( \tan x = \frac{1}{\sqrt{3}} \), which can be thought of as the slope of the line connecting the point to the origin in a triangle.
In our exercise, \( \tan x = \frac{1}{\sqrt{3}} \), which can be thought of as the slope of the line connecting the point to the origin in a triangle.
- Tangent is periodic with a period of \( \pi \), making it different from the sine and cosine functions in terms of repetition.
- Unlike sine and cosine, the range of tangent is all real numbers from negative to positive infinity.
cosecant function
The cosecant function, represented as \( \csc \theta \), is the reciprocal of the sine function.
Its formula is easy: \( \csc x = \frac{1}{\sin x} \). In the example, it equals 2, indicating that the hypotenuse is twice as long as the opposite side.
Its formula is easy: \( \csc x = \frac{1}{\sin x} \). In the example, it equals 2, indicating that the hypotenuse is twice as long as the opposite side.
- Cosecant does not include zero in its range since that would result in division by zero.
- Its range excludes values between -1 and 1 but spans from negative to positive infinity outside that interval.
secant function
The secant function is the reciprocal of the cosine function. It is denoted as \( \sec \theta \), calculated through \( \frac{1}{\cos \theta} \).
For \( \cos x = \frac{\sqrt{3}}{2} \), the secant function results in \( \frac{2}{\sqrt{3}} \).
For \( \cos x = \frac{\sqrt{3}}{2} \), the secant function results in \( \frac{2}{\sqrt{3}} \).
- Similar to cosecant, the secant excludes zero in its range, diverging at the points where cosine equals zero.
- Its range also excludes values from -1 to 1, extending into infinities in both directions.
cotangent function
Cotangent is the inverse of the tangent function, denoted \( \cot \theta \). It is calculated as \( \frac{1}{\tan \theta} \), or the adjacent over the opposite side in a triangle.
In the provided example, \( \cot x = \sqrt{3} \), representing a particular angle's inclination.
In the provided example, \( \cot x = \sqrt{3} \), representing a particular angle's inclination.
- Like tangent, cotangent is periodic with a period of \( \pi \).
- Its range covers the entire real number line, indicating how it can represent various slopes and angles.
Other exercises in this chapter
Problem 11
In Exercises 11-24, solve the equation. \( 2 \cos x + 1 = 0 \)
View solution Problem 11
In Exercises 9-50, verify the identity \( \cot^2 y (\sec^2 y - 1) = 1 \)
View solution Problem 12
In Exercises 7 - 12, find the exact value of each expression. (a) \( \sin\left(315^\circ - 60^\circ\right) \) (b) \( \sin 315^\circ - 60^\circ \)
View solution Problem 12
In Exercises 11-24, solve the equation. \( 2 \sin x + 1 = 0 \)
View solution