Problem 11
Question
In Exercises 11-18, (a) write the linear function \(f\) such that it has the indicated function values and (b) sketch the graph of the function. \(f(1) = 4\), \(f(0) = 6\)
Step-by-Step Solution
Verified Answer
The linear function that satisfies the given conditions is \(f(x) = -2x + 6\). The graph of the function starts at the point (0,6) and has a slope of -2.
1Step 1: Finding the Slope
The slope of a line is calculated by the formula \(m = (y_2 - y_1)/(x_2 - x_1)\). Substituting the given points (1, 4) and (0, 6) into the formula gives: \(m = (4 - 6) / (1 - 0) = -2\). Thus, the slope of the function is -2.
2Step 2: Determining the y-intercept
The y-intercept of a line is the y-coordinate where the line crosses the y-axis. From the problem, it's known that when \(x = 0\), \(y = 6\), which means the y-intercept is 6.
3Step 3: Writing the Function
Using the calculated slope and y-intercept, the linear function can be written as \(f(x) = -2x + 6\)
4Step 4: Sketching the Graph
To sketch this function, start by plotting the y-intercept at (0,6). Then, use the slope to determine the next point: from (0,6), move down 2 units and over to the right by 1 which lands at (1, 4). Draw a line through these two points to complete the graph.
Key Concepts
Slope CalculationY-InterceptGraphing Linear Equations
Slope Calculation
Understanding the slope of a line is essential in working with linear functions. The slope (often represented by the letter \(m\)) describes the steepness and direction of a line. For a given linear function, it's calculated using the formula:
Remember:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
- \( m = \frac{4 - 6}{1 - 0} = -2 \)
Remember:
- A positive slope means upward as you move right.
- A zero slope is a flat horizontal line.
- An undefined slope is a vertical line.
Y-Intercept
The y-intercept is a crucial part of graphing linear equations. It is the point where the line crosses the y-axis. This means, it's where the x-value is zero. The y-intercept provides a starting spot for graphing a line.
In the problem, when \(x = 0\), \(y = 6\). Therefore, the y-intercept is 6. This tells us that the line will pass through the point \((0, 6)\) on the graph.
This information can be used directly in the equation of the line, giving it a form like:
In the problem, when \(x = 0\), \(y = 6\). Therefore, the y-intercept is 6. This tells us that the line will pass through the point \((0, 6)\) on the graph.
This information can be used directly in the equation of the line, giving it a form like:
- \(f(x) = mx + b\)
Graphing Linear Equations
Graphing linear equations visually represents the relationship between variables. It all starts with understanding the function's form, typically written as \(f(x) = mx + b\).
Once you've calculated the slope and determined the y-intercept, you can easily sketch the graph.To graph the function \(f(x) = -2x + 6\):
Once you've calculated the slope and determined the y-intercept, you can easily sketch the graph.To graph the function \(f(x) = -2x + 6\):
- Start at the y-intercept: plot the point \((0, 6)\).
- Use the slope: from \((0, 6)\), move down 2 units and right 1 unit to plot \((1, 4)\).
- Draw a line through these points. The line will extend in both directions.
- Identify the y-intercept on the graph.
- Apply the slope to find another point.
- Connect the points with a straight line.
Other exercises in this chapter
Problem 11
In Exercises 7-14, find the inverse function of \(f\) informally. Verify that \(f(f^{-1}(x)) = x\) and \(f^{-1}(f(x)) = x\). \(f(x) = 3x + 1\)
View solution Problem 11
In Exercises 9-16, find (a) \((f+g)(x)\), (b) \((f-g)(x)\), (c) \((fg)(x)\), and (d) \((f/g)(x). What is the domain of \)f/g\(? \)f(x) = x^2, \(g(x) = 4x - 5\)
View solution Problem 11
In Exercises 11 and 12, sketch the lines through the point with the indicated slopes on the same set of coordinate axes. Point \( (2, 3) \) Slopes (a) \(0\) (b)
View solution Problem 11
In Exercises 7-14, determine whether each point lies on the graph of the equation. \( y = |x - 1| + 2 \) (a) \( (2, 3) \) (b) \( (-1, 0) \)
View solution