Problem 11
Question
In \(3-17,\) find the exact value of \(\cos (A+B)\) for each given pair of values. \(A=270^{\circ}, B=45^{\circ}\)
Step-by-Step Solution
Verified Answer
The exact value of \(\cos(270^{\circ} + 45^{\circ})\) is \(\frac{\sqrt{2}}{2}\).
1Step 1: Recall Cosine Addition Formula
The formula for the cosine of the sum of two angles, \(\cos(A+B)\), is given by: \[\cos(A+B) = \cos A \cos B - \sin A \sin B.\]
2Step 2: Determine Trigonometric Values for 270° and 45°
Find the cosine and sine for each angle: - For \(A = 270°\), \(\cos 270° = 0\) and \(\sin 270° = -1\).- For \(B = 45°\), \(\cos 45° = \frac{\sqrt{2}}{2}\) and \(\sin 45° = \frac{\sqrt{2}}{2}\).
3Step 3: Substitute Values into the Formula
Substitute the trigonometric values into \(\cos(A+B) = \cos A \cos B - \sin A \sin B\): \[\cos(270° + 45°) = (0)(\frac{\sqrt{2}}{2}) - (-1)(\frac{\sqrt{2}}{2}).\]
4Step 4: Simplify the Expression
Calculate the expression: - \(0 \times \frac{\sqrt{2}}{2} = 0\) - \(-1 \times \frac{\sqrt{2}}{2} = -\frac{\sqrt{2}}{2}\). Since it's subtraction, \(0 + \frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{2}\).
5Step 5: Conclusion: Final Result
The exact value of \(\cos(A+B)\) for \(A = 270^{\circ}\) and \(B = 45^{\circ}\) is \(\frac{\sqrt{2}}{2}\).
Key Concepts
Trigonometric IdentitiesExact Trigonometric ValuesAngle Addition in Trigonometry
Trigonometric Identities
Trigonometric identities are fundamental relationships between the trigonometric functions that are true for all angles. These identities are crucial tools in simplifying expressions and solving equations. One of the most useful identities in trigonometry is the cosine addition formula:
Learning and memorizing these identities can be very beneficial, especially when dealing with complex trigonometric problems.
- \(\cos(A+B) = \cos A \cos B - \sin A \sin B\)
Learning and memorizing these identities can be very beneficial, especially when dealing with complex trigonometric problems.
Exact Trigonometric Values
Trigonometry often requires finding exact values for sine, cosine, and tangent of important angles such as 0°, 30°, 45°, 60°, and 90°. These values are easy to remember because they repeat regularly and are often used across various problems.
Moreover, understanding these values aids in quickly obtaining results and verifying the correctness of answers you derive using identities or other trigonometric methods.
- For example, \(\cos 45° = \sin 45° = \frac{\sqrt{2}}{2}\), making it a central value for calculations.
- For angles like \(270°\), it's essential to recognize \(\cos 270° = 0\) and \(\sin 270° = -1\). This is because they represent significant points on the unit circle's axes.
Moreover, understanding these values aids in quickly obtaining results and verifying the correctness of answers you derive using identities or other trigonometric methods.
Angle Addition in Trigonometry
The concept of angle addition in trigonometry revolves around calculating the sine, cosine, or tangent of the sum or difference of two angles. This is particularly helpful when dealing with non-standard angles, allowing us to decompose them into known quantities. Here's how angle addition formulas, like the cosine addition formula, benefit solving problems:
The approach of using triangles or the unit circle to visualize and derive these values makes this concept not only more accessible but also intuitive once you've practiced it enough.
- They break the sum of two angles into components that are easier to calculate using known values.
- For example, knowing \(\cos(270° + 45°)\) can be calculated by using \(\cos(270°)\) and \(\cos(45°)\), along with their sine counterparts.
The approach of using triangles or the unit circle to visualize and derive these values makes this concept not only more accessible but also intuitive once you've practiced it enough.
Other exercises in this chapter
Problem 11
In \(3-26,\) prove that each equation is an identity. $$ \cos \theta(\sec \theta-\cos \theta)=\sin ^{2} \theta $$
View solution Problem 11
\(\ln 3-17,\) find the exact value of \(\sin (A-B)\) and of \(\sin (A+B)\) for each given pair of values. \(A=60^{\circ}, B=270^{\circ}\)
View solution Problem 11
In \(3-14,\) write each expression as a single term using \(\sin \theta, \cos \theta,\) or both. $$ \frac{1}{\sec \theta \csc \theta} $$
View solution Problem 11
In \(3-17,\) find the exact value of \(\cos (A-B)\) for each given pair of values. \(A=60^{\circ}, B=270^{\circ}\)
View solution