Problem 11
Question
In \(3-14 :\) a. Determine the number of possible triangles for each set of given measures. b. Find the measures of the three angles of each possible triangle. Express approximate values to the nearest degree $$ P Q=12, P R=15, \mathrm{m} \angle R=100 $$
Step-by-Step Solution
Verified Answer
One triangle is possible with angles \(100^\circ, 35^\circ,\) and \(45^\circ.\)
1Step 1: Analyze the Given Information
We are given two side lengths of a triangle, \(PQ = 12\), \(PR = 15\), and the measure of angle \(\angle R = 100^\circ\). Our task is to find the number of triangles possible with this information and then calculate the measures of all three angles if a triangle exists.
2Step 2: Apply the Law of Cosines
We use the Law of Cosines to find the length of the third side \(QR\):\[ QR^2 = PQ^2 + PR^2 - 2 \cdot PQ \cdot PR \cdot \cos(\angle R) \]Substituting the given values:\[ QR^2 = 12^2 + 15^2 - 2 \cdot 12 \cdot 15 \cdot \cos(100^\circ) \]Calculate the right-hand side to solve for \(QR\).
3Step 3: Solve for QR Length
Calculating the equation:\[ QR^2 = 144 + 225 - 2 \cdot 12 \cdot 15 \cdot (-0.1736) \]\[ = 369 + 62.496 = 431.496 \]\[ QR = \sqrt{431.496} \approx 20.77 \]Thus, the length of side \(QR\) is approximately 20.77 units.
4Step 4: Calculate Other Angles Using Law of Sines
Next, use the Law of Sines to find the measures of angles \(\angle P\) and \(\angle Q\):\( \frac{\sin(\angle Q)}{12} = \frac{\sin(100^\circ)}{20.77} \)\( \sin(\angle Q) = \frac{12 \cdot \sin(100^\circ)}{20.77} \) Calculate \(\angle Q\).
5Step 5: Solve for \(\angle Q\)
Calculate \(\sin(\angle Q)\):\( \sin(\angle Q) = \frac{12 \cdot 0.9848}{20.77} \approx 0.568 \)Using inverse sine, \(\angle Q = \sin^{-1}(0.568) \approx 35^\circ\).
6Step 6: Find \(\angle P\)
The sum of angles in a triangle is \(180^\circ\). Use this to find \(\angle P\):\(\angle P = 180^\circ - 100^\circ - 35^\circ = 45^\circ\).
Key Concepts
Triangle Angle CalculationTriangle Side CalculationSolving Triangles
Triangle Angle Calculation
To calculate the angles in a triangle, one fundamental rule is the sum of all interior angles equals 180 degrees. Knowing this rule is crucial when you are given some, but not all, the angles of a triangle, as you can often deduce missing angles easily. In our example, we know \( \angle R = 100^{\circ} \). Once we find one of the other angles, let's say \( \angle Q \), calculating the last angle, \( \angle P \), involves simply subtracting the known angles from 180 degrees. Another helpful method for finding unknown angles is the Law of Sines, which we used in our problem. This law says that the ratio of the length of a side to the sine of its opposite angle is constant across all three sides of the triangle:
- \( \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} \)
Triangle Side Calculation
Calculating the sides of a triangle can often involve the Pythagorean Theorem for right triangles or, in our problem, the Law of Cosines, which works for any triangle. The Law of Cosines is especially handy when you have two sides and an included angle, or when you need to determine the length of a side but you don't have a right triangle.In our example, with \( PQ = 12 \), \( PR = 15 \), and \( \angle R = 100^{\circ} \), we employed the Law of Cosines:
- \( c^2 = a^2 + b^2 - 2ab\cos(C) \)
Solving Triangles
Solving a triangle means finding all its side lengths and angle measures. To do this effectively, you'll often employ a mix of the Law of Sines and the Law of Cosines, each tuned to help with specific scenarios.
For cases where you know two sides and an included angle (like in our example), the Law of Cosines is the ideal first step to find the unknown side. Once that's determined, the Law of Sines comes into play to help find the remaining angles.
Here's a quick guideline to solve triangles:
- Identify what you know: sides, angles, or both.
- Choose the appropriate method: Law of Sines or Law of Cosines.
- Solve for the missing angles and sides.
Other exercises in this chapter
Problem 11
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