Problem 11
Question
Graph the complex number and find its modulus. $$ \sqrt{3}+i $$
Step-by-Step Solution
Verified Answer
The complex number is \( \sqrt{3}+i \) and its modulus is 2.
1Step 1: Plotting the Complex Number
To graph the complex number \( \sqrt{3} + i \), we interpret it as a point in the complex plane. The real part is \( \sqrt{3} \) and the imaginary part is \( 1 \). Plot the point \( (\sqrt{3}, 1) \) on the Cartesian plane, where \( x = \sqrt{3} \) represents the real axis and \( y = 1 \) represents the imaginary axis.
2Step 2: Finding the Modulus
The modulus of a complex number \( a + bi \) is given by the formula \( \sqrt{a^2 + b^2} \). For the complex number \( \sqrt{3} + i \), substitute \( a = \sqrt{3} \) and \( b = 1 \).
3Step 3: Calculating the Modulus
Calculate the modulus using the formula: \[\sqrt{(\sqrt{3})^2 + 1^2} = \sqrt{3 + 1} = \sqrt{4} = 2.\]
4Step 4: Conclusion and Interpretation
The complex number \( \sqrt{3} + i \) is plotted at the point \( (\sqrt{3}, 1) \) in the complex plane. Its modulus, or distance from the origin, is 2. This confirms both the plotted point and calculated modulus are consistent on the graph.
Key Concepts
Complex PlaneModulus of a Complex NumberGraphing Complex Numbers
Complex Plane
The complex plane is a fascinating mathematical visualization tool. It provides a graphical way to interpret complex numbers. Think of it just like a typical Cartesian plane that you might use in geometry class, but with a twist! In the complex plane, the horizontal axis, known as the real axis, represents the real part of a complex number. Meanwhile, the vertical axis, called the imaginary axis, represents the imaginary part of the complex number.
This system allows us to visualize each complex number as a unique point on the plane.
This system allows us to visualize each complex number as a unique point on the plane.
- The point's coordinates reflect the real and imaginary parts. For example, the complex number \( \sqrt{3} + i \) will have a real part of \( \sqrt{3} \) and an imaginary part of \( 1 \).
- Thus, it's plotted at \((\sqrt{3}, 1)\) on the complex plane.
Modulus of a Complex Number
The modulus of a complex number is like a fancy way of saying "its length." It's similar to how we measure the length of a vector in geometry.To find the modulus of a complex number \( a + bi \), we use the formula: \[\sqrt{a^2 + b^2}\]Here's why this works:
- Imagine the complex number as a right triangle on the complex plane where the real part \( a \) and the imaginary part \( b \) are the legs of the triangle.
- The modulus is the hypotenuse, or the "longest side," of this triangle.
- It's calculated just like you would in the Pythagorean theorem.
- The modulus is \( \sqrt{(\sqrt{3})^2 + 1^2} = 2 \).
- This tells us that the "distance" from the origin \((0,0)\) to our point \((\sqrt{3}, 1)\) is exactly \( 2 \).
Graphing Complex Numbers
Graphing complex numbers is a rewarding endeavor that brings abstract concepts to life. To graph a complex number, we look at its location in the complex plane, pinpointing it using its real and imaginary parts.Here's a simple way to think about it:
- Every complex number can be thought of as a point with coordinates \((a, b)\), where \(a\) is the real part and \(b\) is the imaginary part.
- To graph \(\sqrt{3} + i\), we plot it at \((\sqrt{3}, 1)\).
- The real part tells you "how far to go left or right" from the origin on the real axis.
- The imaginary part tells you "how far to go up or down" on the imaginary axis.
Other exercises in this chapter
Problem 10
Test the polar equation for symmetry with respect to the polar axis, the pole, and the line \(\theta=\pi / 2 .\) $$ r=4+8 \cos \theta $$
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Plot the point that has the given polar coordinates. Then give two other polar coordinate representations of the point, one with \(r0\) . $$ (-1,7 \pi / 6) $$
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\(3-24=A\) pair of parametric equations is given. (a) Sketch the curve represented by the parametric equations. (b) Find a rectangular coordinate equation for t
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Test the polar equation for symmetry with respect to the polar axis, the pole, and the line \(\theta=\pi / 2 .\) $$ r=3 \sec \theta $$
View solution