Problem 11
Question
For the sample space \(\\{\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\\},\) determine how many events are possible.
Step-by-Step Solution
Verified Answer
There are 16 possible events.
1Step 1: Understand What is an Event
In probability and statistics, an event is a subset of the sample space. Each event represents a possible outcome or a group of outcomes from an experiment.
2Step 2: Identify the Sample Space
The sample space for this exercise is given by \( \{ \mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D} \} \). It consists of 4 elements.
3Step 3: Determine the Number of Subsets
The number of events (subsets) possible in a sample space with \( n \) elements is calculated using the formula \( 2^n \). Here, \( n = 4 \) since the sample space consists of 4 elements.
4Step 4: Apply the Formula
Calculate \( 2^4 \) to find the total number of events. \( 2^4 = 16 \).
5Step 5: Verify the Answer
List a few subsets to verify understanding: 1. An empty set \( \{ \} \) is a subset.2. Single element subsets such as \( \{ \mathrm{A} \} \), \( \{ \mathrm{B} \} \), etc.3. Two element subsets such as \( \{ \mathrm{A}, \mathrm{B} \} \), \( \{ \mathrm{B}, \mathrm{C} \} \), etc.Thus confirming there are indeed 16 possible subsets.
Key Concepts
Sample Space: The Foundation of ProbabilitySubsets: Building Blocks of EventsNumber of Events: Calculating Possibilities
Sample Space: The Foundation of Probability
In probability, the sample space is crucial. It is the set of all possible outcomes of a particular experiment or random event. Imagine rolling a die; the sample space would include numbers from 1 to 6.
In the example provided in the exercise, the sample space is given as \( \{\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\} \). But why is sample space so important? It represents every potential outcome.
In the example provided in the exercise, the sample space is given as \( \{\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\} \). But why is sample space so important? It represents every potential outcome.
- Helps identify the events we can calculate probabilities for.
- Establishes the universe within which all probability calculations are made.
- Serves as the starting point for listing all possible events and analyzing them.
Subsets: Building Blocks of Events
Subsets are groups of elements taken from the sample space. Each subset corresponds to an event in probability. Let's return to our sample space \( \{\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\} \).
- The empty set \( \{\} \) is a subset, representing no occurrence.
- Single element subsets like \( \{\mathrm{A}\} \) or \( \{\mathrm{B}\} \) represent individual events.
- Multiple element subsets, such as \( \{\mathrm{A}, \mathrm{B}\} \), represent events where these elements occur together.
Number of Events: Calculating Possibilities
Determining the number of possible events describes the range of outcomes we can account for. In any sample space with \( n \) elements, the number of potential events (or subsets) is given by the formula \( 2^n \).
For the sample space \( \{\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\} \), this translates to \( 2^4 \), equating to 16 distinct events.
For the sample space \( \{\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\} \), this translates to \( 2^4 \), equating to 16 distinct events.
- One way to look at it: each element either participates in a subset or it doesn't, forming a binary decision.
- This leads to exponential growth in possibilities as more elements enter the sample space.
- Listing a few demonstrates this: the empty set, single elements like \( \{\mathrm{A}\} \), two-element combinations like \( \{\mathrm{A}, \mathrm{B}\} \), all the way up to the full set itself.
Other exercises in this chapter
Problem 11
The letters of the word TOMATO are arranged at random. What is the probability that the arrangement begins and ends with T?
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In \(12-17,\) write the \(n\) th term of each binomial expansion. $$ (x+y)^{15}, n=3 $$
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In \(7-14,\) answers can be rounded to four decimal places. Assume that there are an equal number of births in each month so that the probability is \(\frac{1}{
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