Problem 11
Question
For the logistic differential equations (a) Give values for \(k\) and for \(L\) and interpret the meaning of each in terms of the growth of the quantity \(P\) (b) Give the value of \(P\) when the rate of change is at its peak. $$\frac{d P}{d t}=0.035 P\left(1-\frac{P}{6000}\right)$$
Step-by-Step Solution
Verified Answer
(a) \(k = 0.035\), \(L = 6000\); they represent growth rate and carrying capacity.
(b) The value of \(P\) when growth rate is at its peak is 3000.
1Step 1: Identifying Values for Parameters
In the given logistic differential equation \( \frac{dP}{dt} = 0.035P \left(1 - \frac{P}{6000}\right) \), we identify two key parameters: - \( k = 0.035 \): This is the growth rate constant, determining how quickly the population \( P \) grows when far below the carrying capacity.- \( L = 6000 \): This is the carrying capacity, representing the maximum population size the environment can sustain indefinitely.
2Step 2: Understanding Parameters in Context
The parameter \( k = 0.035 \) indicates the proportional growth rate of the population when its size is small compared to the carrying capacity. The parameter \( L = 6000 \) means that as \( P \) approaches 6000, the growth rate slows down, and the population stabilizes at this level. Thus, \( L \) represents the environmental limit for the population size.
3Step 3: Finding Peak Growth Rate Value
The rate of change is at its peak when the derivative \( \frac{dP}{dt} \) is maximized. For logistic growth, this occurs at \( P = \frac{L}{2} \). To find this value:\[ L = 6000 \]\[ P = \frac{6000}{2} = 3000 \] At \( P = 3000 \), \( \frac{dP}{dt} \) is at its maximum.
Key Concepts
Understanding Differential Equations in Logistic GrowthExploring the Growth Rate Constant \( k \)Interpreting Carrying Capacity \( L \)Determining the Peak Growth Rate
Understanding Differential Equations in Logistic Growth
In logistic growth models, differential equations are used to describe how a quantity changes over time. Specifically, the equation given in the exercise \( \frac{dP}{dt} = 0.035P \left(1 - \frac{P}{6000}\right) \) is a first-order differential equation. It details how a population \( P \) of a certain species evolves depending on two factors: the current population size and its proximity to the carrying capacity. Differential equations can look intimidating, but they are very helpful tools. They provide a relationship between a function and its derivatives, which are the rates of change. In this context, \( \frac{dP}{dt} \) indicates how the population size \( P \) changes with respect to time \( t \).
- The formula reflects the growth rate being proportional to both the current population \( P \) and what fraction of the carrying capacity remains unfilled.
- This type of equation is widely used in biology, economics, and other fields to model situations where growth levels out after initially increasing rapidly.
Exploring the Growth Rate Constant \( k \)
The growth rate constant, referred to as \( k \), plays a significant role in logistic growth equations. In the given equation, \( k = 0.035 \). This number tells us how quickly the population grows when it is far below its carrying capacity.The parameter \( k \) can be thought of as the potential growth speed in ideal conditions:
- With a higher \( k \), the population grows more rapidly.
- A smaller \( k \) results in slower growth.
Interpreting Carrying Capacity \( L \)
Carrying capacity is one of the most fundamental aspects of logistic growth models. Denoted as \( L \), it represents the maximum number of individuals that an environment can support indefinitely without being degraded.In our specific example, \( L = 6000 \). This implies that the environment in question can sustain a population up to 6000. Beyond this number, resources become limiting, preventing any further increase in size.
- The carrying capacity is contingent upon various factors, such as food availability, habitat space, and competition with other species.
- It reflects a state of balance where births are equal to deaths, causing the population growth to stabilize.
Determining the Peak Growth Rate
In logistic growth models, the peak growth rate describes the point at which the population increases in size most rapidly. To find this peak, we examine when the derivative \( \frac{dP}{dt} \) is at its maximum.For logistic equations, this peak growth happens when the population \( P \) is half of the carrying capacity \( L \). As calculated, for \( L = 6000 \), the peak occurs when \( P = \frac{6000}{2} = 3000 \).This is because, at \( P = 3000 \), there is still enough room for growth, but the population is also large enough to produce many new individuals:
- The mid-point provides a balance between abundant resources and significant population numbers.
- This understanding is valuable for identifying stages in biological or economic systems where interventions might be most effective.
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