Problem 11
Question
For the following exercises, consider this scenario: For each year \(t,\) the population of a forest of trees is represented by the function \(A(t)=115(1.025)^{t} .\) In a neighboring forest, the population of the same type of tree is represented by the function \(B(t)=82(1.029)^{t} .\) (Round answers to the nearest whole number.) Assuming the population growth models continue to represent the growth of the forests, which forest will have a greater number of trees after 20 years? By how many?
Step-by-Step Solution
Verified Answer
Forest A will have 34 more trees than Forest B after 20 years.
1Step 1: Define the Population Functions
We have two population functions: - For the first forest: \(A(t) = 115(1.025)^t\)- For the second forest: \(B(t) = 82(1.029)^t\)These functions represent the population of trees in each forest for year \(t\).
2Step 2: Calculate Population of Forest A after 20 Years
Substitute \(t = 20\) into the function for forest A:\[ A(20) = 115(1.025)^{20} \]Calculate \(A(20)\) to find the population of forest A after 20 years:
3Step 3: Evaluate A(20)
Calculate \((1.025)^{20}\):\(A(20) = 115 imes (1.025)^{20} \approx 188\)Thus, the population of forest A after 20 years is approximately 188 trees.
4Step 4: Calculate Population of Forest B after 20 Years
Substitute \(t = 20\) into the function for forest B:\[ B(20) = 82(1.029)^{20} \]Calculate \(B(20)\) to find the population of forest B after 20 years:
5Step 5: Evaluate B(20)
Calculate \((1.029)^{20}\):\(B(20) = 82 imes (1.029)^{20} \approx 154\)Thus, the population of forest B after 20 years is approximately 154 trees.
6Step 6: Compare Populations
Now compare the populations:
- Population of Forest A after 20 years: 188 trees
- Population of Forest B after 20 years: 154 trees
Forest A has more trees than Forest B.
7Step 7: Calculate Difference
Subtract the population of Forest B from Forest A to find the difference:
188 (Forest A) - 154 (Forest B) = 34 trees.
So, Forest A has 34 more trees than Forest B after 20 years.
Key Concepts
Population ModelingAlgebraic FunctionsComparison of Growth Rates
Population Modeling
Population modeling is an essential tool used to understand how populations of organisms, such as trees in a forest, grow over time. This type of modeling can involve simple or complex mathematical functions to depict real-world scenarios.
In our exercise, each forest's population grows exponentially, represented by specific functions with their distinct parameters. For Forest A, the function is given by \(A(t) = 115(1.025)^t\). This means that the initial population is 115 trees, and the population grows by a factor of 1.025 each year.
In our exercise, each forest's population grows exponentially, represented by specific functions with their distinct parameters. For Forest A, the function is given by \(A(t) = 115(1.025)^t\). This means that the initial population is 115 trees, and the population grows by a factor of 1.025 each year.
- Initial population: The constant before the exponential factor.
- Growth rate: The base of the exponent (1.025), indicating a 2.5% annual increase.
Algebraic Functions
Algebraic functions are powerful tools in mathematics that help us express relationships between quantities. These functions can easily demonstrate the growth of a population when exponential growth is involved.
To understand how these functions operate within the context of population modeling, consider that both functions, \(A(t)\) and \(B(t)\), as exponential functions. They are characterized by a constant raised to the power affected by the variable time, \(t\).
This variable \(t\) indicates the passage of time in years in our problem. Exponential functions like these grow much faster than linear functions, as seen in their rapid increase over time. In our exercise, substituting a particular time value, such as \(t = 20\), into the function directly calculates tree populations after that number of years:
To understand how these functions operate within the context of population modeling, consider that both functions, \(A(t)\) and \(B(t)\), as exponential functions. They are characterized by a constant raised to the power affected by the variable time, \(t\).
This variable \(t\) indicates the passage of time in years in our problem. Exponential functions like these grow much faster than linear functions, as seen in their rapid increase over time. In our exercise, substituting a particular time value, such as \(t = 20\), into the function directly calculates tree populations after that number of years:
- For Forest A: \(A(20) = 115(1.025)^{20}\)
- For Forest B: \(B(20) = 82(1.029)^{20}\)
Comparison of Growth Rates
Comparing growth rates is a crucial aspect when analyzing population models where exponential growth is involved. Exponential growth means the population increases by a constant rate relative to its current size, which significantly impacts long-term populations.
In the provided scenario, we compare two forests:
After performing the calculations, we found that Forest A has 188 trees, and Forest B has 154 trees after 20 years. By subtracting these values, the difference in populations is 34 trees, indicating that despite faster growth, a higher initial population can lead to a larger final population size in the long term.
In the provided scenario, we compare two forests:
- Forest A with an annual growth rate of 2.5%
- Forest B with an annual growth rate of 2.9%
After performing the calculations, we found that Forest A has 188 trees, and Forest B has 154 trees after 20 years. By subtracting these values, the difference in populations is 34 trees, indicating that despite faster growth, a higher initial population can lead to a larger final population size in the long term.
Other exercises in this chapter
Problem 11
For the following exercises, graph each set of functions on the same axes. $$ f(x)=3\left(\frac{1}{4}\right)^{x}, g(x)=3(2)^{x}, \text { and } h(x)=3(4)^{x} $$
View solution Problem 11
For the following exercises, rewrite each equation in exponential form. $$\log _{15}(a)=b$$
View solution Problem 12
Rewrite the exponential model \(A(t)=1550(1.085)^{x}\) as an equivalent model with base \(e\). Express the exponent to four signifi ant digits.
View solution Problem 12
For the following exercises, state the domain and the vertical asymptote of the function. $$g(x)=\ln (3-x)$$
View solution