Problem 11
Question
Find the standard equation of each parabola from the given information. Assume that the vertex is at the origin. Directrix is \(y-2=0\)
Step-by-Step Solution
Verified Answer
The standard equation is \(x^2 = -8y\).
1Step 1: Determine the Direction of Opening
Since the directrix is a horizontal line given by the equation \(y = 2\), the parabola will open upwards or downwards. For a parabola with a vertex at the origin and a horizontal directrix, the parabola opens downwards if the directrix is above it.
2Step 2: Calculate the Focus
The focus of a parabola is at an equal distance from the vertex as the directrix, but on the opposite side of the vertex. Given the directrix is \(y = 2\), and the vertex is at the origin \((0,0)\), the directrix is 2 units above the vertex. Therefore, the focus will be 2 units below the vertex, at \((0, -2)\).
3Step 3: Write the Standard Equation
For a parabola opening downwards with the vertex at the origin, the standard form is \(x^2 = -4py\), where \(p\) is the distance from the vertex to the focus (negative because it opens downwards). Here, \(p = 2\), so the equation is \(x^2 = -4(2)y = -8y\).
Key Concepts
Understanding the Vertex of a ParabolaExplaining the DirectrixRole of the Focus in a ParabolaDeriving the Standard Equation
Understanding the Vertex of a Parabola
In the context of a parabola, the vertex is a key point that determines its shape and position. Typically, the vertex is either the highest or lowest point, depending on the direction in which the parabola opens.
- If the vertex is at the origin \((0,0)\), it simplifies calculations and understanding, as the vertex acts as a central anchor point.
- For upward or downward-opening parabolas, the vertex indicates the minimum or maximum value.
- A parabola opening to the sides would have a vertex that acts as a center point horizontally.
Explaining the Directrix
The directrix of a parabola is a fixed line used to define its curvature along with the focus. Together, they help determine the parabola's shape and orientation.
- The directrix is located at a specific distance from the vertex along the axis of symmetry.
- For the parabola in this exercise, the directrix is given by the equation \(y = 2\).
- This horizontal line indicates the parabola will open either upwards or downwards.
Role of the Focus in a Parabola
The focus of a parabola is a special point located inside the curve, which, along with the directrix, defines the parabola's properties and orientation.
- The focus is located the same distance from the vertex as the directrix but on the opposite side.
- For this parabola, with the directrix at \(y = 2\), the focus is found at \(0, -2\).
- The focus is a critical point where all reflected lines parallel to the parabola's opening direction converge.
Deriving the Standard Equation
The standard equation of a parabola efficiently represents its algebraic form. For a parabola opening vertically and with the vertex at the origin, the equation is typically written as:
- \(x^2 = 4py\) for upward opening.
- \(x^2 = -4py\) for downward opening.
In this task:
- The parabola opens downward since the directrix is above the vertex.
- \(p\), the distance from vertex to focus, is 2, but because the parabola opens downwards, we use -2 for calculations.
Other exercises in this chapter
Problem 11
Name the conic or limiting form represented by the given equation. Usually you will need to use the process of completing the square. $$ 4 x^{2}-4 y^{2}+8 x+12
View solution Problem 11
Sketch the limaçon \(r=3-4 \sin \theta\), and find the area of the region inside its small loop.
View solution Problem 12
In each of Problems 11-16, sketch the graph of the given Cartesian equation, and then find the polar equation for it. \(x=0\)
View solution Problem 12
Sketch the graph of the given equation, indicating vertices, foci, and asymptotes. \(\frac{x^{2}}{7}+\frac{y^{2}}{4}=1\)
View solution