Problem 11
Question
Find the indefinite integral. $$ \int \frac{(\ln x)^{2}}{x} d x $$
Step-by-Step Solution
Verified Answer
The indefinite integral \(\int \frac{(\ln x)^{2}}{x} dx = \frac{1}{3}(\ln x)^3 + C\).
1Step 1: Identify Function for Substitution
Identify the inner function that makes the integral complex. Here, \(\ln x\) is such a function. We make a substitution such that \(u = \ln x\). This simplifies the integral. Differentiate \(u\) with respect to \(x\) to find \(du\), i.e., \(du = \frac{1}{x} dx\).
2Step 2: Replace in Integral
Replace \(\ln x\) and \(dx\) in the integral with \(u\) and \(du\) respectively. This transforms the integral into the much simpler form \(\int u^2 du\).
3Step 3: Integrate
Evaluate the integral \(\int u^2 du\). This is a basic power rule integral, and its antiderivative is \(\frac{1}{3}u^3 + C\), where \(C\) is the constant of integration.
4Step 4: Substitute Back
Finally, substitute \(u\) back into the integral. Since \(u = \ln x\), the final result of the integral is \(\frac{1}{3}(\ln x)^3 + C\).
Other exercises in this chapter
Problem 11
Evaluate the definite integral of the algebraic function. Use a graphing utility to verify your result. $$ \int_{1}^{4} \frac{u-2}{\sqrt{u}} d u $$
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Approximate the definite integral using the Trapezoidal Rule and Simpson's Rule with \(n=4\). Compare these results with the approximation of the integral using
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Verify the identity. \(\cosh x+\cosh y=2 \cosh \frac{x+y}{2} \cosh \frac{x-y}{2}\)
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