Problem 11
Question
Find the domain of the expression. $$\sqrt{x+3}$$
Step-by-Step Solution
Verified Answer
Domain is \([-3, \infty)\).
1Step 1: Understand the Problem
The expression is \( \sqrt{x+3} \). We are asked to find its domain. This means we need to determine for which values of \( x \) the expression is defined.
2Step 2: Identify Restrictions for the Square Root Function
Recall that the square root function \( \sqrt{u} \) is only defined when \( u \geq 0 \). Hence, for \( \sqrt{x+3} \), the expression \( x+3 \) must be greater than or equal to 0.
3Step 3: Solve the Inequality
Set up the inequality \( x + 3 \geq 0 \) and solve for \( x \). Subtract 3 from both sides to find \( x \geq -3 \).
4Step 4: Write the Domain in Interval Notation
The solution from the inequality gives us the domain. In interval notation, the domain is \([-3, \infty)\), meaning \( x \) can be any real number greater than or equal to \(-3\).
Key Concepts
Square Root FunctionInequality SolvingInterval Notation
Square Root Function
The square root function is a common mathematical function we encounter often, denoted by the symbol \( \sqrt{} \). It represents a number that, when multiplied by itself, gives the original number underneath the square root symbol.
The important thing about the square root function is that it only works when the number under the square root is zero or positive. This is because the square root of a negative number is not defined within the set of real numbers. Instead, it falls into the category of complex numbers, which is a topic for another day.
The important thing about the square root function is that it only works when the number under the square root is zero or positive. This is because the square root of a negative number is not defined within the set of real numbers. Instead, it falls into the category of complex numbers, which is a topic for another day.
- For example, \( \sqrt{4} = 2 \) because \( 2 \times 2 = 4 \).
- If we try \( \sqrt{-1} \), it does not have a real number solution.
Inequality Solving
Solving inequalities is like solving equations, but there are a few extra rules to remember. Inequalities show a relationship where one side is larger or smaller than the other.
Consider the inequality \( x + 3 \geq 0 \), which arose from ensuring the term inside the square root is non-negative. Our task here is to rearrange this inequality and find the values of \( x \) that make it true.
Here's how we proceed:
Consider the inequality \( x + 3 \geq 0 \), which arose from ensuring the term inside the square root is non-negative. Our task here is to rearrange this inequality and find the values of \( x \) that make it true.
Here's how we proceed:
- You have \( x + 3 \geq 0 \), suggesting that the smallest \( x \) can be is one that makes \( x + 3 \) exactly zero.
- Subtract 3 from both sides: \( x \geq -3 \).
Interval Notation
Interval notation is a shorthand way to write the solution set of an inequality. It tells us the range of values that a variable like \( x \) can take.
In our case, the inequality \( x \geq -3 \) translates to interval notation as \([-3, \infty)\).
In our case, the inequality \( x \geq -3 \) translates to interval notation as \([-3, \infty)\).
- The square bracket \([ \) indicates that \(-3\) is included in the interval, meaning \( x \) can be exactly \(-3\).
- The parenthesis \(( \)) next to \( \infty \) shows that infinity is not a number we reach, but a concept indicating the numbers keep increasing.
Other exercises in this chapter
Problem 11
Complete the following table by stating whether the polynomial is a monomial, binomial, or trinomial; then list its terms and state its degree. $$\begin{array}{
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Find the real and imaginary parts of the complex number. $$3$$
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Properties of Real Numbers State the property of real numbers being used. $$3+7=7+3$$
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Write an equation that expresses the statement. \(P\) varies inversely as \(T\).
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