Problem 11
Question
Find the derivative of each function. $$ h(x)=\frac{3}{x^{2}} $$
Step-by-Step Solution
Verified Answer
The derivative of \( h(x) = \frac{3}{x^2} \) is \( h'(x) = -6x^{-3} \).
1Step 1: Rewrite the Function
Start by rewriting the function to make differentiating easier. The function is given as \( h(x) = \frac{3}{x^2} \). We can rewrite this as \( h(x) = 3x^{-2} \). This allows us to use the power rule more straightforwardly.
2Step 2: Identify the Power Rule
The power rule for differentiation states that if \( f(x) = ax^n \), then the derivative \( f'(x) = anx^{n-1} \). We will apply this rule to our rewritten function.
3Step 3: Differentiate Using the Power Rule
Apply the power rule to \( h(x) = 3x^{-2} \). According to the power rule, the derivative is \( h'(x) = 3(-2)x^{-2-1} = -6x^{-3} \).
Key Concepts
Power RuleDifferentiationFunctions
Power Rule
The power rule is a fundamental tool in calculus for finding derivatives, especially when dealing with polynomial terms. It's a straightforward method to determine the derivative of a function of the form \( f(x) = ax^n \). Here's how it works:
- If you have a term \( ax^n \), its derivative, using the power rule, is \( anx^{n-1} \).
- The rule is applied by multiplying the exponent \( n \) by the coefficient \( a \), then reducing the exponent by one.
- For example, if you had \( 3x^{-2} \), applying the power rule gives \( -6x^{-3} \).
Differentiation
Differentiation is the process in calculus used to find the derivative of a function. The derivative represents the rate at which a function is changing at any given point and is a central concept in calculus. Here’s why differentiation is so important:
- It helps us understand how quantities change over time or space. For instance, velocity is a derivative of the position with respect to time.
- In simple terms, differentiation provides the slope of a function at any given point, enlightening us on how steep the graph of the function is at that point.
- Applying differentiation to a function like \( h(x) = 3x^{-2} \) efficiently provides insights into its behaviour and allows for practical applications, such as graphing.
Functions
Functions are one of the building blocks of calculus, embodying relationships between sets of numbers. In calculus, a function expresses how one variable depends on another. Here’s a fundamental look at functions:
- A function is typically written as \( f(x) \), indicating that \( f \) is a function of \( x \).
- This notation means that for each value of \( x \), the function gives a unique output \( f(x) \).
- For example, the function \( h(x) = \frac{3}{x^2} \) defines a specific mathematical rule that relates \( x \) to \( h(x) \).
Other exercises in this chapter
Problem 11
For each function, find: a. \(f^{\prime \prime}(x)\) and b. \(f^{\prime \prime}(3)\). $$ f(x)=\frac{1}{6 x^{2}} $$
View solution Problem 11
a. Show that the definition of the derivative applied to the function \(f(x)=\sqrt{x}\) at \(x=0\) gives \(f^{\prime}(0)=\lim _{h \rightarrow 0} \frac{\sqrt{h}}
View solution Problem 11
Find the derivative of each function by using the Product Rule. Simplify your answers. $$ f(x)=\left(x^{2}+1\right)\left(x^{2}-1\right) $$
View solution Problem 12
Use the Generalized Power Rule to find the derivative of each function. $$ f(x)=\left(x^{3}+1\right)^{4} $$
View solution