Problem 11
Question
Factor each trinomial by grouping. Exercises 9 through 12 are broken into parts to help you get started. \(15 x^{2}-23 x+4\) a. Find two numbers whose product is \(15 \cdot 4=60\) and whose sum is -23 . b. Write \(-23 x\) using the factors from part (a). c. Factor by grouping.
Step-by-Step Solution
Verified Answer
The factored form is \((3x - 4)(5x - 1)\).
1Step 1: Understand the Problem
The task is to factor the trinomial \(15x^2 - 23x + 4\) by grouping. We'll break it down into parts as guided.
2Step 2: Calculate Product and Sum
First, we need to find two numbers whose product is \( 15 \times 4 = 60 \) and whose sum is \(-23\). This will help us break down the middle term.
3Step 3: Find the Pair of Numbers
To satisfy both conditions, we look for two numbers: \(-20\) and \(-3\). These numbers multiply to \(60\) (since \(-20 \times -3 = 60\)) and add up to \(-23\) (since \(-20 + -3 = -23\)).
4Step 4: Rewrite the Middle Term
Use the numbers found in Step 3 to decompose \(-23x\). Thus, rewrite the expression as: \(15x^2 - 20x - 3x + 4\).
5Step 5: Factor by Grouping
Now, group the terms for factoring: \((15x^2 - 20x) - (3x - 4)\). Factor out the common factors in each group. In \(15x^2 - 20x\), the common factor is \(5x\), giving us \(5x(3x - 4)\). In \(-3x + 4\), factor out \(-1\), giving us \(-1(3x - 4)\).
6Step 6: Combine and Factor the Expression
Notice \(3x - 4\) is common in both groups. Factor it out: \((3x - 4)(5x - 1)\).
7Step 7: Final Verification
Multiply the factors \((3x - 4)\) and \((5x - 1)\) to ensure they give back the original polynomial \(15x^2 - 23x + 4\).
Key Concepts
Polynomial ExpressionsGrouping MethodAlgebra Techniques
Polynomial Expressions
Polynomial expressions are mathematical phrases that involve variables raised to different powers and combined using addition or subtraction. They play a fundamental role in algebra, providing a way to express relationships and solve various algebraic problems. A trinomial is a type of polynomial consisting of three terms.
- The standard form of a trinomial is: ax² + bx + c, where a, b, and c are constants.
- In our example, the trinomial expression is 15x² - 23x + 4.
Grouping Method
The grouping method is a useful factoring technique for polynomials, especially trinomials, where the goal is to break down and factor the expression into simpler components.
Here’s how the grouping method works in practice:
Here’s how the grouping method works in practice:
- First, identify two numbers that multiply to give the product of the first and last coefficients (in this case, 15 and 4) and add up to the middle coefficient.
- Rewrite the middle term using these two numbers to split it into two terms.
- We looked for numbers that multiply to 60 (15 * 4) and sum to -23, which are -20 and -3.
- Rewriting the expression: 15x² - 20x - 3x + 4.
- By grouping terms, we created: (15x² - 20x) and (-3x + 4).
Algebra Techniques
Algebra involves various techniques to manipulate expressions and solve equations, with factoring being one of the key methods. The art of factoring transforms a polynomial into a product of simpler expressions, aiding in solving equations or simplifying algebraic fractions.
Here’s an outline of important algebra techniques used in factoring by grouping:
Here’s an outline of important algebra techniques used in factoring by grouping:
- Identify the greatest common factor in each group of terms: In the expression 15x² - 20x, the greatest common factor is 5x.
- Similarly, in -3x + 4, factor out -1.
- Re-factor the entire expression by taking out the common binomial factor: In this example, 3x - 4 was common in both groups.
Other exercises in this chapter
Problem 10
Solve each equation. $$ 2 x(x+12)=0 $$
View solution Problem 11
Factor each trinomial completely. $$ x^{2}+22 x+121 $$
View solution Problem 11
Find the \(G C F\) for each list. $$ x^{10} y^{2}, x y^{2}, x^{3} y^{3} $$
View solution Problem 11
Factor each trinomial completely. If a polynomial can't be factored, write "prime." $$ x^{2}+5 x+2 $$
View solution