Problem 11
Question
Exer. 9-14: (a) Find the distance \(d(A, B)\) between \(A\) and \(B\). (b) Find the midpoint of the segment \(A B\). $$ A(-5,0), \quad B(-2,-2) $$
Step-by-Step Solution
Verified Answer
Distance: \(\sqrt{13}\); Midpoint: \((-\frac{7}{2}, -1)\).
1Step 1: Determine the Distance Formula
The distance formula to find the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ d(A, B) = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \].
2Step 2: Substitute the Coordinates of Points A and B into the Distance Formula
Given points \(A(-5,0)\) and \(B(-2,-2)\), substitute \(x_1 = -5\), \(y_1 = 0\), \(x_2 = -2\), and \(y_2 = -2\) into the distance formula: \[ d(A, B) = \sqrt{(-2 - (-5))^2 + (-2 - 0)^2} \].
3Step 3: Calculate the Distance
Perform the calculations to find \(d(A, B)\):\[ d(A, B) = \sqrt{(3)^2 + (-2)^2} = \sqrt{9 + 4} = \sqrt{13} \].
4Step 4: Determine the Midpoint Formula
The midpoint formula for two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \].
5Step 5: Substitute the Coordinates of Points A and B into the Midpoint Formula
Use the coordinates of \(A(-5,0)\) and \(B(-2,-2)\) and substitute them into the midpoint formula:\(x_1 = -5\), \(y_1 = 0\), \(x_2 = -2\), \(y_2 = -2\).\[ M = \left( \frac{-5 + (-2)}{2}, \frac{0 + (-2)}{2} \right) \].
6Step 6: Calculate the Midpoint
Perform the calculations to find the midpoint \(M\):\[ M = \left( \frac{-7}{2}, \frac{-2}{2} \right) = \left( -\frac{7}{2}, -1 \right) \].
Key Concepts
Distance FormulaMidpoint FormulaCoordinate Geometry
Distance Formula
The Distance Formula is a handy tool in coordinate geometry, used to calculate the distance between two points on a plane. If you have two points, let's say \(A(x_1, y_1)\) and \(B(x_2, y_2)\), the distance between them is calculated using the formula: \[ d(A, B) = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] This formula is derived from the Pythagorean theorem. It essentially finds the hypotenuse of a right-angled triangle formed by the difference in x-coordinates and y-coordinates of the points.
- Steps to use the Distance Formula:
- Find the change in x (\(x_2 - x_1\))
- Find the change in y (\(y_2 - y_1\))
- Square both changes
- Add them together
- Take the square root of the sum
Midpoint Formula
The Midpoint Formula is a method used to find the point that is exactly halfway between two points on a coordinate plane. This point is known as the midpoint. Suppose we have two endpoints of a line segment: \(A(x_1, y_1)\) and \(B(x_2, y_2)\). The midpoint \(M\) can be found using:\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]This formula gives the average of the x-coordinates and the y-coordinates for the two endpoints.
- Steps to find the midpoint:
- Add the x-coordinates together, then divide by 2.
- Add the y-coordinates together, then divide by 2.
Coordinate Geometry
Coordinate Geometry, also known as analytic geometry, is a branch of mathematics that deals with points, lines, and shapes using coordinates. It provides a systematic way to analyze geometric shapes algebraically. This involves using the coordinate plane to provide visual representation and solutions to geometric problems.
Key Concepts in Coordinate Geometry:
Key Concepts in Coordinate Geometry:
- Coordinates: Specify the position of points using pairs of numbers (x, y).
- Distance: Calculate understanding using the distance formula and how far two points are from each other.
- Midpoint: Determine the center point of a line segment with the midpoint formula.
- Equations of Lines: Understand slopes and y-intercepts to form equations representing lines.
Other exercises in this chapter
Problem 11
Exer. 11-14: If \(a\) is a positive real number, find (a) \(g\left(\frac{1}{a}\right)\) (b) \(\frac{1}{g(a)}\) (c) \(g(\sqrt{a})\) (d) \(\sqrt{g(a)}\) $$ g(x)=4
View solution Problem 11
Exer. 1-20: Sketch the graph of the equation, and label the \(x\) - and \(y\)-intercepts. $$ x=-y^{2}+3 $$
View solution Problem 12
Exer. 3-12: Determine whether \(f\) is even, odd, or neither even nor odd. $$ f(x)=x^{3}-\frac{1}{x} $$
View solution Problem 12
Exer. 11-20: Find (a) \((f \circ g)(x)\) (b) \((g \circ f)(x)\) (c) \(f(g(-2))\) (d) \(g(f(3))\) $$ f(x)=5 x+2, \quad g(x)=6 x-1 $$
View solution