Problem 11
Question
Evaluate each limit. $$ \lim _{t \rightarrow 0} \frac{\tan ^{2} 3 t}{2 t} $$
Step-by-Step Solution
Verified Answer
The limit is 0.
1Step 1: Identify the form of the limit
Begin by identifying the form of the limit. As \( t \to 0 \), \( \tan^2(3t) \) and \( 2t \) both approach 0, indicating an indeterminate form \( \frac{0}{0} \).
2Step 2: Apply Trigonometric Identity
Recall the trigonometric identity \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). Thus, \( \tan^2(3t) = \left(\frac{\sin(3t)}{\cos(3t)}\right)^2 = \frac{\sin^2(3t)}{\cos^2(3t)} \). The limit becomes \( \lim_{t \to 0} \frac{\sin^2(3t)}{2t \cos^2(3t)} \).
3Step 3: Use Limit Property for Sine
Apply the limit property \( \lim_{x \to 0} \frac{\sin(x)}{x} = 1 \). We transform \( \sin^2(3t) \) into \( 9t^2 \left(\frac{\sin(3t)}{3t}\right)^2 \). Substitute to get \( \lim_{t \to 0} \frac{9t^2 (\frac{\sin(3t)}{3t})^2}{2t \cos^2(3t)} \).
4Step 4: Simplify and Evaluate the Limit
Simplify the expression: \( \frac{9t^2}{2t \cos^2(3t)} \times (\frac{\sin(3t)}{3t})^2 = \frac{9t}{2 \cos^2(3t)} \times (1)^2 \). Substitute \( t = 0 \) to get \( \frac{9 \times 0}{2 \times 1} = 0 \).
5Step 5: Conclusion
Concluding, after simplifications using trigonometric identities and limit properties, the given limit evaluates to 0.
Key Concepts
Trigonometric LimitsIndeterminate FormsLimit Evaluation Techniques
Trigonometric Limits
Trigonometric limits often involve expressions where trigonometric functions approach a specific point, causing them to tend towards infinity or form indeterminate expressions. When dealing with trigonometric limits, such as the given exercise,\[ \lim_{t \to 0} \frac{\tan^2(3t)}{2t}, \]we encounter trigonometric functions like \(\tan(x)\). These functions can behave unpredictably as their argument approaches certain critical values.To handle these scenarios, we exploit trigonometric identities.
- Recalling the identity \(\tan(x) = \frac{\sin(x)}{\cos(x)}\), which helps reform expressions.
- This assists in transforming the limit into a more manageable form, such as dealing with \(\sin(x)\) and \(\cos(x)\).
Indeterminate Forms
Indeterminate forms occur in calculus when standard arithmetic operations do not directly resolve to a concrete value as a variable approaches a limit. These commonly include forms like \(\frac{0}{0}\), \(\frac{\infty}{fty}\), or \(0 \times \infty\).In our exercise,\[ \lim_{t \to 0} \frac{\tan^2(3t)}{2t}, \]both the numerator \(\tan^2(3t)\) and the denominator \(2t\) approach zero. This means the expression becomes a \(\frac{0}{0}\) indeterminate form when \(t\) tends to zero.To address this, we need to apply techniques that transform the expression into a determinate form.
- Utilizing trigonometric identities, such as those involving sine and cosine, helps to eliminate indeterminacy.
- Applying specific limit properties can simplify the expression further, often converting it into recognizable standard limit problems.
Limit Evaluation Techniques
Limit evaluation techniques are essential when directly substituting values into an expression results in indeterminate forms like \(\frac{0}{0}\). These techniques help us find meaningful limits.In this example:\[ \lim_{t \to 0} \frac{\tan^2(3t)}{2t}, \]we apply several methods:
- **Trigonometric Identities**: By converting \(\tan^2(3t)\) into \(\frac{\sin^2(3t)}{\cos^2(3t)}\), we manipulate the expression into a simpler form.
- **Using \(\lim_{x \to 0} \frac{\sin(x)}{x} = 1\)**: This key limit property helps when reasoning about expressions involving \(\sin(3t)\).
- **Algebraic Simplification**: Breaking down the complex limit into smaller, more manageable pieces, makes use of the relation \((\frac{\sin(3t)}{3t})^2\) which resolves to \(1^2 = 1\).
Other exercises in this chapter
Problem 11
State whether the indicated function is continuous at \(3 .\) If it is not continuous, tell why. $$ r(t)=\left\\{\begin{array}{ll} \frac{t^{3}-27}{t-3} & \text
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Give an \(\varepsilon-\delta\) proof of each limit fact. $$ \lim _{x \rightarrow 0}(2 x-1)=-1 $$
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Find the limits. $$ \lim _{x \rightarrow \infty} \frac{3 \sqrt{x^{3}}+3 x}{\sqrt{2 x^{3}}} $$
View solution Problem 12
State whether the indicated function is continuous at \(3 .\) If it is not continuous, tell why. $$ r(t)=\left\\{\begin{array}{ll} \frac{t^{3}-27}{t-3} & \text
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