Problem 11
Question
Determine whether the series is convergent or divergent. \( 1 + \frac {1}{8} + \frac {1}{27} + \frac {1}{64} + \frac {1}{125} + \cdot \cdot \cdot \)
Step-by-Step Solution
Verified Answer
The series is convergent.
1Step 1: Recognize the series terms pattern
First, note that the given series is composed of terms of the form \( \frac{1}{n^3} \) where \( n \) is an integer starting at 1. The terms can be written as follows: \[ a_n = \frac{1}{n^3} \] The series can, therefore, be written as:\[ \sum_{n=1}^{\infty} \frac{1}{n^3} \]
2Step 2: Determine the type of series
Recognize that this is a p-series of the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \). In our case, the series is \( \sum_{n=1}^{\infty} \frac{1}{n^3} \), where \( p = 3 \).
3Step 3: Apply p-series convergence test
For a p-series \( \sum_{n=1}^{\infty} \frac{1}{n^p} \), the series converges if \( p > 1 \) and diverges if \( p \leq 1 \). In this instance, we have \( p = 3 \), which is greater than 1, satisfying the condition for convergence.
4Step 4: Conclude the behavior of the series
Since the condition \( p > 1 \) for the convergence of a p-series is satisfied (where \( p = 3 \)), the series \( \sum_{n=1}^{\infty} \frac{1}{n^3} \) is convergent.
Key Concepts
P-seriesConvergence TestsInfinite Series
P-series
A p-series is a type of series where each term is of the form \( \frac{1}{n^p} \) with \( n \) being a positive integer starting from 1. These series are called p-series because the exponent "p" in the denominator crucially affects their behavior. When you encounter a p-series, identifying the value of "p" is essential for determining convergence or divergence.
- If \( p > 1 \), the series converges, meaning the sum of all terms up to infinity approaches a finite number.
- If \( p \leq 1 \), the series diverges, which implies that the sum grows infinitely as you add more terms.
Convergence Tests
When dealing with series, determining whether a series converges or diverges is key. Convergence tests are tools developed to help mathematicians and students assess the behavior of series.
One of the most common tests is the p-series test, specifically designed for series of the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \). If \( p > 1 \), it confirms convergence; if \( p \leq 1 \), divergence.
There are other tests available, such as:
One of the most common tests is the p-series test, specifically designed for series of the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \). If \( p > 1 \), it confirms convergence; if \( p \leq 1 \), divergence.
There are other tests available, such as:
- Comparison Test: Compares the given series with a known convergent or divergent series.
- Ratio Test: Uses the ratio of successive terms to find convergence or divergence.
- Integral Test: Relies on the integration of a related function for analysis.
Infinite Series
An infinite series is essentially a sum of an infinite sequence of numbers. You're adding up numbers forever! These series can often behave in surprising ways, sometimes yielding a finite sum, and other times not stabilizing at all.
Infinite series appear frequently in mathematical analysis, physics, and engineering, representing real-world phenomena and functions that need such extensive summation. The number of terms is infinite, yet the outcome might still be a finite value or infinite.
Infinite series appear frequently in mathematical analysis, physics, and engineering, representing real-world phenomena and functions that need such extensive summation. The number of terms is infinite, yet the outcome might still be a finite value or infinite.
- Convergent Infinite Series: These add up to a specific number as you approach infinity.
- Divergent Infinite Series: These do not settle into any finite sum, their total sum just keeps getting larger.
Other exercises in this chapter
Problem 11
Use the Ratio Test to determine whether the series is convergent or divergent. \( \displaystyle \sum_{k = 1}^{\infty} \frac {1}{k!} \)
View solution Problem 11
Determine whether the series converges or diverges. \( \displaystyle \sum_{k = 1}^{\infty} \frac { \sqrt [3]{k}}{\sqrt {k^3 + 4k + 3}} \)
View solution Problem 11
Find at least 10 partial sums of the series. Graph both the sequence of terms and the sequence of partial sums on the same screen. Does it appear that the serie
View solution Problem 11
List the first five terms of the sequence. \( a_1 = 2, a_{n+1} = \frac {a_n}{1 + a_n} \)
View solution