Problem 11
Question
Determine whether the given value is a solution of the equation. \(\frac{X-a}{X-b}=\frac{a}{b} \quad(b \neq 0)\) (a) \(x=0 \quad\) (b) \(x=b\)
Step-by-Step Solution
Verified Answer
The value \(x = 0\) is a solution; \(x = b\) is not a solution (undefined).
1Step 1: Understand the Equation
The equation given is \( \frac{X-a}{X-b}=\frac{a}{b} \) where \(b eq 0\). Our goal is to determine if a particular value for \(x\) satisfies this equation.
2Step 2: Substitute x = 0 into the Equation
First, we will check if \(x = 0\) is a solution. Substitute \(X = 0\) into the equation: \( \frac{0-a}{0-b} = \frac{a}{b} \). Simplifying the left side gives \( \frac{-a}{-b} = \frac{a}{b} \). This simplifies to \( \frac{a}{b} = \frac{a}{b} \), which is true. So, \(x = 0\) is a solution.
3Step 3: Substitute x = b into the Equation
Next, check if \(x = b\) is a solution. Substitute \(X = b\) into the equation: \( \frac{b-a}{b-b} = \frac{a}{b} \). The left side becomes \( \frac{b-a}{0} \), which is undefined. Therefore, \(x = b\) cannot be a solution as the equation is not defined for this value.
Key Concepts
Rational EquationsSubstitution MethodUndefined Expressions
Rational Equations
Rational equations are mathematical expressions where one fraction, often involving polynomials, is set equal to another fraction. These types of equations are common in algebra problems and have specific techniques for solving them. In this exercise, the rational equation is depicted as \( \frac{X-a}{X-b}=\frac{a}{b} \). The aim here is to find out if certain values for \(x\) satisfy or solve this equation.
When working with rational equations, it's important to remember the following:
When working with rational equations, it's important to remember the following:
- Simplify both sides of the equation if possible.
- Clear the fractions by finding a common denominator if needed.
- Check for any restrictions, such as values that make the denominator zero, which are undefined.
Substitution Method
The substitution method is a useful technique in algebra for determining if a specific value is a solution to an equation. The process involves substituting the potential solution into the equation and simplifying to see if both sides remain equal.
Here's how to apply the substitution method step by step:
Here's how to apply the substitution method step by step:
- Take the given value for \(x\) and substitute it into the rational equation.
- Simplify each side of the equation after substitution.
- Check if the simplified expressions on both sides of the equation are equal. If they are, the value is a solution.
Undefined Expressions
Undefined expressions occur in mathematics when operations are attempted that do not yield valid numerical results. A common cause of undefined expressions in rational equations is division by zero.
When you substitute a value into a rational equation, it's crucial to check if the denominator becomes zero, as this would make the expression undefined.
To avoid undefined expressions:
When you substitute a value into a rational equation, it's crucial to check if the denominator becomes zero, as this would make the expression undefined.
To avoid undefined expressions:
- Identify the values that make any denominator zero before substituting.
- Remember that any such value cannot be a solution to the equation.
Other exercises in this chapter
Problem 11
\(5-60\) Find all real solutions of the equation. $$ x^{3}-5 x^{2}+6 x=0 $$
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Find the real and imaginary parts of the complex number. $$ i \sqrt{3} $$
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Solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ -4 x \geq 10 $$
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