Problem 11
Question
Create your own vectors \(\vec{u}, \vec{v}\) and \(\vec{w}\) in \(\mathbb{R}^{2}\) and show that \(\vec{u} \cdot(\vec{v}+\vec{w})=\vec{u} \cdot \vec{v}+\vec{u} \cdot \vec{w}\)
Step-by-Step Solution
Verified Answer
The equation holds true, demonstrating the distributive property of the dot product.
1Step 1: Define the Vectors
Create your own vectors: let \( \vec{u} = \begin{pmatrix} 1 \ 2 \end{pmatrix}, \vec{v} = \begin{pmatrix} 3 \ 4 \end{pmatrix}, \) and \( \vec{w} = \begin{pmatrix} 5 \ 6 \end{pmatrix} \) in \( \mathbb{R}^{2} \). Write these vectors down for reference.
2Step 2: Find Sum of Vectors \(\vec{v}\) and \(\vec{w}\)
Calculate the sum \( \vec{v} + \vec{w} \): \( \begin{pmatrix} 3 \ 4 \end{pmatrix} + \begin{pmatrix} 5 \ 6 \end{pmatrix} = \begin{pmatrix} 8 \ 10 \end{pmatrix} \). This represents the combined vector of \(\vec{v}\) and \(\vec{w}\).
3Step 3: Compute Dot Product on Left-Hand Side
Find the dot product \(\vec{u} \cdot (\vec{v} + \vec{w})\): \( \begin{pmatrix} 1 \ 2 \end{pmatrix} \cdot \begin{pmatrix} 8 \ 10 \end{pmatrix} = 1 \cdot 8 + 2 \cdot 10 = 8 + 20 = 28 \).
4Step 4: Compute Dot Products on Right-Hand Side
Calculate \(\vec{u} \cdot \vec{v}\) and \(\vec{u} \cdot \vec{w}\) separately:1. \(\vec{u} \cdot \vec{v} = \begin{pmatrix} 1 \ 2 \end{pmatrix} \cdot \begin{pmatrix} 3 \ 4 \end{pmatrix} = 1 \cdot 3 + 2 \cdot 4 = 3 + 8 = 11 \).2. \(\vec{u} \cdot \vec{w} = \begin{pmatrix} 1 \ 2 \end{pmatrix} \cdot \begin{pmatrix} 5 \ 6 \end{pmatrix} = 1 \cdot 5 + 2 \cdot 6 = 5 + 12 = 17 \).Add these results: \(11 + 17 = 28\).
5Step 5: Compare Results
Observe that both sides of the equation equal 28, hence showing \( \vec{u} \cdot (\vec{v} + \vec{w}) = \vec{u} \cdot \vec{v} + \vec{u} \cdot \vec{w} \). This confirms the distributive property of the dot product.
Key Concepts
Distributive Property of the Dot ProductUnderstanding Vector AdditionVector Multiplication and the Dot Product
Distributive Property of the Dot Product
In the world of vectors, the distributive property is a fundamental concept. It states that if you have a vector multiplied by the sum of two other vectors, you can break it down into individual dot products. It's like distributing multiplication over addition. In mathematical terms, this property is expressed as:
In the exercise provided, the distributive property is verified by showing that the dot product of \( \vec{u} \) with the sum of \( \vec{v} \) and \( \vec{w} \) equals the sum of the dot products \( \vec{u} \cdot \vec{v} \) and \( \vec{u} \cdot \vec{w} \). The solution neatly confirms that this property holds true, making it a reliable tool when working with vector expressions.
- \( \vec{u} \cdot (\vec{v} + \vec{w}) = \vec{u} \cdot \vec{v} + \vec{u} \cdot \vec{w} \).
In the exercise provided, the distributive property is verified by showing that the dot product of \( \vec{u} \) with the sum of \( \vec{v} \) and \( \vec{w} \) equals the sum of the dot products \( \vec{u} \cdot \vec{v} \) and \( \vec{u} \cdot \vec{w} \). The solution neatly confirms that this property holds true, making it a reliable tool when working with vector expressions.
Understanding Vector Addition
Vector addition is a straightforward yet powerful operation. It involves adding corresponding components of two vectors to form a new vector. Imagine you have two vectors \( \vec{v} = \begin{pmatrix} 3 \ 4 \end{pmatrix} \) and \( \vec{w} = \begin{pmatrix} 5 \ 6 \end{pmatrix} \). When you add them together, you simply add the first components, and then the second components like so:
Vector addition is commutative, meaning the order in which you add vectors doesn't matter. So \( \vec{v} + \vec{w} \) will give you the same result as \( \vec{w} + \vec{v} \). This property is essential when handling multiple vector operations, as it allows flexibility in how calculations are structured.
In our exercise, you see vector addition applied when \( \vec{v} \) and \( \vec{w} \) are combined into a single vector to verify the distributive property.
- \( \vec{v} + \vec{w} = \begin{pmatrix} 3 \ 4 \end{pmatrix} + \begin{pmatrix} 5 \ 6 \end{pmatrix} = \begin{pmatrix} 8 \ 10 \end{pmatrix} \)
Vector addition is commutative, meaning the order in which you add vectors doesn't matter. So \( \vec{v} + \vec{w} \) will give you the same result as \( \vec{w} + \vec{v} \). This property is essential when handling multiple vector operations, as it allows flexibility in how calculations are structured.
In our exercise, you see vector addition applied when \( \vec{v} \) and \( \vec{w} \) are combined into a single vector to verify the distributive property.
Vector Multiplication and the Dot Product
Vector multiplication can take different forms, but when we talk about the dot product, it's a specific kind of multiplication. The dot product is a scalar that results from multiplying corresponding components of two vectors and then summing those products.
For example, with vectors \( \vec{u} = \begin{pmatrix} 1 \ 2 \end{pmatrix} \) and \( \vec{v} = \begin{pmatrix} 3 \ 4 \end{pmatrix} \), the dot product calculation is as follows:
The dot product is commutative, much like vector addition. Therefore, \( \vec{u} \cdot \vec{v} \) will yield the same value as \( \vec{v} \cdot \vec{u} \).
In the exercise, the dot product is crucial for confirming the distributive property. First, the dot product involving the sum of vectors is calculated, and then individual dot products are used to confirm the equation.
For example, with vectors \( \vec{u} = \begin{pmatrix} 1 \ 2 \end{pmatrix} \) and \( \vec{v} = \begin{pmatrix} 3 \ 4 \end{pmatrix} \), the dot product calculation is as follows:
- \( \vec{u} \cdot \vec{v} = 1 \cdot\ 3 + 2 \cdot\ 4 = 3 + 8 = 11 \)
The dot product is commutative, much like vector addition. Therefore, \( \vec{u} \cdot \vec{v} \) will yield the same value as \( \vec{v} \cdot \vec{u} \).
In the exercise, the dot product is crucial for confirming the distributive property. First, the dot product involving the sum of vectors is calculated, and then individual dot products are used to confirm the equation.
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