Problem 11
Question
Correct order of boiling point for the alkyl halide is (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\) (d) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\)
Step-by-Step Solution
Verified Answer
The correct order is (b)
C_{2}H_{5}I > C_{2}H_{5}Br > C_{2}H_{5}Cl
.
1Step 1: Understanding the Concept
Boiling points of alkyl halides depend on molecular weight and intermolecular forces, particularly Van der Waals forces. The larger and heavier the molecule, the stronger these forces, leading to a higher boiling point.
2Step 2: Identify Alkyl Halides
The alkyl halides given are ethyl chloride (
C_{2}H_{5}Cl
), ethyl bromide (
C_{2}H_{5}Br
), and ethyl iodide (
C_{2}H_{5}I
). Their molecular weights increase from chlorine (Cl) to bromine (Br) to iodine (I).
3Step 3: Analyze Molecular Weight and Forces
As molecular weight increases (from Cl to I), the van der Waals forces also increase, meaning the boiling point should increase from ethyl chloride to ethyl iodide.
4Step 4: Order the Boiling Points
Based on molecular weight and intermolecular forces, the correct order of boiling points is
C_{2}H_{5}I > C_{2}H_{5}Br > C_{2}H_{5}Cl
.
Key Concepts
Alkyl HalidesMolecular WeightIntermolecular ForcesVan der Waals Forces
Alkyl Halides
Alkyl halides are organic compounds where a halogen atom is bonded to an alkyl group. This specific group of compounds includes molecules like ethyl chloride, ethyl bromide, and ethyl iodide. Each of these compounds consists of ethyl groups
- Ethyl Chloride: C₂H₅Cl
- Ethyl Bromide: C₂H₅Br
- Ethyl Iodide: C₂H₅I
Molecular Weight
Molecular weight is a crucial factor that influences the boiling points of alkyl halides. Molecular weight refers to the sum of the atomic weights of all the atoms in a molecule. For the series of alkyl halides under discussion, the molecular weights vary as follows:
- Ethyl Chloride: Low
- Ethyl Bromide: Moderate
- Ethyl Iodide: High
Intermolecular Forces
Intermolecular forces are the forces of attraction or repulsion between different molecules. These forces play a crucial role in determining physical properties such as boiling points. In alkyl halides:
- Dipole-Dipole Interactions: These occur because of electronegativity differences between the alkyl group and the halogen atom.
- Van der Waals Forces: These are generally the most significant forces in determining boiling points in non-polar sections of the molecule.
Van der Waals Forces
Van der Waals forces are weak electric forces that generally contribute to the boiling points of molecules, including alkyl halides. These forces include attractions between molecules that have temporary dipoles:
- They grow stronger as the molecular weight increases.
- They depend largely on the surface area of the molecule.
- For alkyl halides, larger halogens like iodine create stronger Van der Waals forces than smaller ones like chlorine.
Other exercises in this chapter
Problem 9
Of the following compounds, the one with the lowest boiling point is? (a) pentyl chloride (b) tertiary butyl chloride (c) isobutyl chloride (d) \(\mathrm{n}\)-b
View solution Problem 10
Which among \(\mathrm{MeX}, \mathrm{RCH}_{2} \mathrm{X}, \mathrm{R}_{2} \mathrm{CHX}, \mathrm{R}_{3} \mathrm{CX}\) is most reactive towards \(\mathrm{S}_{\mathr
View solution Problem 12
Which of the following will have the maximum dipole moment? (a) \(\mathrm{CH}_{3} \mathrm{Cl}\) (b) \(\mathrm{CH}_{3} \mathrm{Br}\) (c) \(\mathrm{CH}_{3} \mathr
View solution Problem 13
Substitution of chlorine takes place at higher temperature in (a) \(\mathrm{CH}_{2}=\mathrm{CH}_{2}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\) (c) \(
View solution