Problem 11
Question
Add or subtract, then factor and simplify. $$ \frac{10}{r^{2}+9 r+20}-\frac{-2 r}{r^{2}+9 r+20} $$
Step-by-Step Solution
Verified Answer
The final answer is \( \frac{2}{r+4} \)
1Step 1: Add the fractions
Since the fractions have the same denominator, we just add the numerators: \[ \frac{10 - (-2r)}{r^{2} + 9r + 20} \] which simplifies to \[ \frac{10 + 2r}{r^{2} + 9r + 20} \]
2Step 2: Simplify the numerator
We can rearrange terms in the numerator, it looks like: \[ \frac{2r + 10}{r^{2} + 9r + 20} \]
3Step 3: Factor the expressions
Factoring out a 2 from the numerator we get: \[ \frac{2(r+5)}{r^{2} + 9r + 20} \]. Factoring the denominator using the formula \( (x+a)(x+b) \) where a and b are roots of equation \(x^{2} + (a+b)x + ab = 0\), we get: \[ \frac{2(r+5)}{(r+5)(r+4)} \]
4Step 4: Simplify the fraction
The \( (r+5) \) terms in the numerator and the denominator cancel each other out. \[ \frac{2}{r+4} \]
Key Concepts
Factoring PolynomialsSimplifying ExpressionsRational Expressions
Factoring Polynomials
Factoring polynomials is a key technique to simplify algebraic expressions, especially when dealing with rational expressions like fractions with polynomials in the numerator and denominator.
To factor a quadratic polynomial, such as \( r^2 + 9r + 20 \), look for two numbers that multiply to the constant term, 20, and add to the linear coefficient, 9. These numbers, called the roots of the polynomial, are 5 and 4 in this example. Thus, we can express the polynomial as \((r+5)(r+4)\).
This method of factoring is often called the reverse FOIL (First, Outer, Inner, Last) method, commonly used in algebra to decompose expressions. Factoring helps break down complex expressions into simpler, solvable parts.
Polynomials are factored by recognizing patterns, such as a difference of squares, sums, or differences of cubes, or by using formulas and trial methods.
To factor a quadratic polynomial, such as \( r^2 + 9r + 20 \), look for two numbers that multiply to the constant term, 20, and add to the linear coefficient, 9. These numbers, called the roots of the polynomial, are 5 and 4 in this example. Thus, we can express the polynomial as \((r+5)(r+4)\).
This method of factoring is often called the reverse FOIL (First, Outer, Inner, Last) method, commonly used in algebra to decompose expressions. Factoring helps break down complex expressions into simpler, solvable parts.
Polynomials are factored by recognizing patterns, such as a difference of squares, sums, or differences of cubes, or by using formulas and trial methods.
Simplifying Expressions
Simplifying algebraic expressions involves combining like terms and reducing complex terms into simpler forms. This is crucial when dealing with large expressions.
For example, when simplifying \( \frac{10 - (-2r)}{r^2 + 9r + 20}\), combine the terms \(10 + 2r\) correctly. This removes any negative signs and combines coefficients correctly to make it simpler.
Next, look for common factors in the numerator and the denominator that can be canceled out. Factoring the numerator allows you to see \(2(r+5)\), illustrating a common factor with the denominator.
Simplification eliminates unnecessary parts to provide a cleaner, equivalent expression. Always check each step for common factors and correct signs to ensure accuracy.
For example, when simplifying \( \frac{10 - (-2r)}{r^2 + 9r + 20}\), combine the terms \(10 + 2r\) correctly. This removes any negative signs and combines coefficients correctly to make it simpler.
Next, look for common factors in the numerator and the denominator that can be canceled out. Factoring the numerator allows you to see \(2(r+5)\), illustrating a common factor with the denominator.
Simplification eliminates unnecessary parts to provide a cleaner, equivalent expression. Always check each step for common factors and correct signs to ensure accuracy.
Rational Expressions
Rational expressions are fractions where the numerator and/or the denominator are polynomials. Working with these requires ensuring they are in the simplest form.
Start by factoring both the numerator and the denominator, as seen in the expression \( \frac{2(r+5)}{(r+5)(r+4)} \). This reveals cancelable terms like \((r+5)\), which simplifies the expression further to \(\frac{2}{r+4}\).
Rational expressions can look intimidating, but by breaking them into smaller, factorable parts, the solution becomes straightforward. Ensuring both the numerator and denominator are factored is key to simplifying effectively.
Always watch out for potential restrictions in the domain, such as values that make the denominator zero (e.g., \(r eq -4\) in the final expression). This consideration is crucial for defining where the expression is valid.
Start by factoring both the numerator and the denominator, as seen in the expression \( \frac{2(r+5)}{(r+5)(r+4)} \). This reveals cancelable terms like \((r+5)\), which simplifies the expression further to \(\frac{2}{r+4}\).
Rational expressions can look intimidating, but by breaking them into smaller, factorable parts, the solution becomes straightforward. Ensuring both the numerator and denominator are factored is key to simplifying effectively.
Always watch out for potential restrictions in the domain, such as values that make the denominator zero (e.g., \(r eq -4\) in the final expression). This consideration is crucial for defining where the expression is valid.
Other exercises in this chapter
Problem 10
Simplify the expression. If not possible, write already in simplest form. $$ \frac{18}{2 x+4} $$
View solution Problem 11
Suppose \(y=6\) when \(x=4 .\) For the given type of variation, find an equation that relates \(x\) and \(y .\) $$\text{\(x\) and \(y\) vary inversely.}$$
View solution Problem 11
Find the least common denominator of the pair of rational expressions. $$ \frac{3}{c^{3}}, \frac{-5}{7 c^{5}} $$
View solution Problem 11
Solve the equation by multiplying by the least common denominator. Check your solutions. \(\frac{1}{x}+\frac{x}{x+2}=1\)
View solution