Problem 11
Question
\(7-14\) A pair of points is graphed. (a) Plot the points in a coordinate plane. (b) Find the distance between them. (c) Find the midpoint of the segment that joins them. $$ (6,-2),(-1,3) $$
Step-by-Step Solution
Verified Answer
The points are (6,-2) and (-1,3). Distance: \(\sqrt{74}\); Midpoint: \((\frac{5}{2}, \frac{1}{2})\).
1Step 1: Plot the Points
Start by plotting the given points on a coordinate plane. The first point is \((6, -2)\) and the second point is \((-1, 3)\). Use the horizontal axis for the x-coordinates and the vertical axis for the y-coordinates. Mark and label the points accordingly.
2Step 2: Calculate the Distance between the Points
Use the distance formula to find the distance between the points \((6, -2)\) and \((-1, 3)\). The distance formula is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]Substitute the given points into the formula:\[ d = \sqrt{(-1 - 6)^2 + (3 - (-2))^2} \]\[ d = \sqrt{(-7)^2 + (5)^2} \]\[ d = \sqrt{49 + 25} \]\[ d = \sqrt{74} \]Thus, the distance between the points is \(\sqrt{74}\) or approximately \(8.6\).
3Step 3: Find the Midpoint of the Segment
To find the midpoint of the segment joining the points \((6, -2)\) and \((-1, 3)\), use the midpoint formula:\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]Substitute the given values into the formula:\[ M = \left( \frac{6 + (-1)}{2}, \frac{-2 + 3}{2} \right) \]\[ M = \left( \frac{5}{2}, \frac{1}{2} \right) \]So, the midpoint of the segment is \(\left( \frac{5}{2}, \frac{1}{2} \right)\).
Key Concepts
coordinate planemidpoint formulaplotting points
coordinate plane
The coordinate plane is a two-dimensional space determined by two axes: the horizontal axis, known as the x-axis, and the vertical axis, known as the y-axis. These axes intersect at a point called the origin. The origin is the center of the coordinate system and is denoted as \(0, 0\).In this system, every point is represented by a pair of numbers \(x, y\), which are known as coordinates. The first number corresponds to the position on the x-axis, and the second number corresponds to the position on the y-axis. When working with a coordinate plane:
- The right side of the x-axis represents positive values while the left side depicts negative values.
- Above the origin on the y-axis are positive values, and below are negative values.
midpoint formula
The midpoint formula is a handy tool in geometry to identify the center point of a line segment on a coordinate plane. Imagine you want to find the exact middle point between two given points. The midpoint formula enables this calculation using simple geometry.The formula itself is: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]Here, \(x_1\) and \(x_2\) are the x-coordinates of the two points, and \(y_1\) and \(y_2\) are the y-coordinates. By computing the average of the x-coordinates and y-coordinates separately, the formula provides the midpoint coordinates.Let's say we have the points \(6, -2\) and \(-1, 3\). Using the midpoint formula:1. Calculate the average of the x-coordinates: \[ \frac{6 + (-1)}{2} = \frac{5}{2} \]2. Calculate the average of the y-coordinates: \[ \frac{-2 + 3}{2} = \frac{1}{2} \]Putting these together, the midpoint of the segment is at \left( \frac{5}{2}, \frac{1}{2} \right)\. Finding this midpoint can be quite useful in various applications, such as dividing a section into equal parts or determining symmetry.
plotting points
Plotting points on a coordinate plane is an essential skill in mathematics. It involves accurately placing a point on the graph according to its coordinates. Let's break down the steps for plotting with an easy guide.First, take the coordinate pair \(x, y\). The x-coordinate indicates how far to move along the horizontal axis. If the x-coordinate is positive, move right; if it's negative, move left. Next, consider the y-coordinate. This figure tells you how far to move along the vertical axis. If the y-coordinate is positive, go up; if negative, go down.For example, to plot the point \(6, -2\):
- Begin at the origin \(0, 0\).
- Move 6 units to the right since the x-coordinate is 6.
- Then, move 2 units downward because the y-coordinate is -2.
- Mark the point on your graph.
Other exercises in this chapter
Problem 10
7–10 ? An equation and its graph are given. Find the x- and y-intercepts. $$ x^{2}+y^{3}-x^{2} y^{2}=64 $$
View solution Problem 11
1–12 ? Write an equation that expresses the statement. \(R\) is proportional to \(i\) and inversely proportional to \(P\) and \(t.\)
View solution Problem 11
11–18 ? Find the x- and y-intercepts of the graph of the equation. $$ y=x-3 $$
View solution Problem 12
1–12 ? Write an equation that expresses the statement. \(A\) is jointly proportional to the square roots of \(x\) and \(y.\)
View solution