Problem 109
Question
Which one is the correct statement? (a) 2 -butene is Saytzeff's product (b) 1 -butene is the Hofmann product (c) both (a) and (b) are correct (d) none is correct
Step-by-Step Solution
Verified Answer
Both (a) and (b) are correct, so the answer is (c).
1Step 1: Understand the Saytzeff Rule
Saytzeff's rule (also called Zaitsev's rule) states that in an elimination reaction, the more substituted alkene—meaning the alkene with more alkyl groups attached to the double-bonded carbons—is usually the major product. This often happens because the more substituted alkene is more stable.
2Step 2: Understand the Hofmann Rule
Hofmann's rule suggests that in elimination reactions, especially with bulky bases, the less substituted alkene is the predominant product. This is typically the case when sterics impede the formation of more substituted alkene.
3Step 3: Identify the Structure of 2-butene and 1-butene
2-butene is the alkene with a double bond between the second and third carbon atoms (CH3-CH=CH-CH3), making it a more substituted (and hence more stable) alkene compared to 1-butene, which has the double bond between the first and second carbon atoms (CH2=CH-CH2-CH3), making it the less substituted alkene.
4Step 4: Apply Saytzeff's Rule to 2-butene
According to Saytzeff's rule, 2-butene is indeed the product expected in a reaction where a more substituted, more stable alkene is favored. Thus, statement (a) is correct.
5Step 5: Apply Hofmann's Rule to 1-butene
According to Hofmann's rule, 1-butene is the product expected when the reaction conditions favor the formation of less substituted alkenes, often using a bulky base. Hence, statement (b) is also correct.
6Step 6: Draw Conclusion from Analysis
Since both statements (a) and (b) are correct according to Saytzeff's and Hofmann's rules respectively, the correct answer is (c) both (a) and (b) are correct.
Key Concepts
Saytzeff RuleHofmann RuleAlkene Stability
Saytzeff Rule
The Saytzeff Rule, also known as Zaitsev's Rule, is a guiding principle in organic chemistry when dealing with elimination reactions. It states that during an elimination reaction, the most stable and thermodynamically favorable alkene product is the one that is more substituted. In simpler terms, the alkene with the greater number of alkyl groups attached to the carbon atoms involved in the double bond will predominantly form.
This rule is based on the concept that more substituted alkenes enjoy enhanced stability. The stability arises because alkyl groups can donate electron density to the double bond, stabilizing it through hyperconjugation and the inductive effect. This electron donation reduces the energy of the alkene, making it more stable.
Saytzeff's rule is typically observed under standard reaction conditions, where factors such as solvent type or temperature do not overly favor alternative pathways. This rule tells chemists what to expect in terms of major products when no other interfering factors are present, like steric hindrance by bulky groups.
This rule is based on the concept that more substituted alkenes enjoy enhanced stability. The stability arises because alkyl groups can donate electron density to the double bond, stabilizing it through hyperconjugation and the inductive effect. This electron donation reduces the energy of the alkene, making it more stable.
Saytzeff's rule is typically observed under standard reaction conditions, where factors such as solvent type or temperature do not overly favor alternative pathways. This rule tells chemists what to expect in terms of major products when no other interfering factors are present, like steric hindrance by bulky groups.
Hofmann Rule
The Hofmann Rule offers an alternative perspective for predicting the outcome of elimination reactions, especially when bulky bases are involved. Unlike Saytzeff’s Rule, which predicts more substituted alkenes, the Hofmann Rule suggests that less substituted alkenes are often the major products when steric factors come into play.
Bulky bases, due to their size, have difficulty approaching more substituted alkene-forming sites, thereby favoring the formation of a less substituted alkene. In such scenarios, the base interacts more effectively with the hydrogen atom that can lead to the formation of a less hindered, less substituted alkene.
The prediction based on the Hofmann Rule is significant when using bulky bases like t-butoxide or when the leaving group is poor. Thus, the rule is particularly useful for specific reaction settings where steric hindrance is a critical factor.
Bulky bases, due to their size, have difficulty approaching more substituted alkene-forming sites, thereby favoring the formation of a less substituted alkene. In such scenarios, the base interacts more effectively with the hydrogen atom that can lead to the formation of a less hindered, less substituted alkene.
The prediction based on the Hofmann Rule is significant when using bulky bases like t-butoxide or when the leaving group is poor. Thus, the rule is particularly useful for specific reaction settings where steric hindrance is a critical factor.
Alkene Stability
Understanding alkene stability is crucial for predicting the major products in elimination reactions. Generally, alkenes are more stable if they are more substituted. Substitution increases stability due to a phenomenon known as hyperconjugation, where the overlap of \(\sigma\) bonds with \(\pi\) bonds spreads out electron density and lowers overall energy.
There are several factors that contribute to alkene stability:
There are several factors that contribute to alkene stability:
- **Substitution level:** More substituted alkenes are more stable, as they have more \(\sigma\) bond overlap.
- **Hyperconjugation:** The dispersal of charge across the alkene stabilizes electron-rich environments.
- **Inductive effects:** Electronegative atoms can withdraw electrons via inductive effects, stabilizing the molecule.
Other exercises in this chapter
Problem 107
Identify the final product (C) in the following sequence of reactions. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{I} \stackrel{\text { Alc. } \mathrm{KOH}, \Delt
View solution Problem 108
Consider the following sequence of reactions \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHBr} \stackrel{\text { Ethanolic KOH }}{\longrightarrow}(\mathrm{X}) \s
View solution Problem 110
Replacement of \(\mathrm{Cl}\) of chlorobenzene to give phenol requires drastic conditions, but chlorine of 2,4 dinitrochlorobenzene is readily replaced because
View solution Problem 114
The refluxing of the silver salt of the carboxylic acid in \(\mathrm{CCl}_{4}\) to form haloalkane or haloarene is called (a) Friedel-Crafts reaction (b) Wittig
View solution