Problem 109
Question
When \(\mathrm{AgNO}_{3}\) is heated strongly the products formed are (a) \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\) (b) \(\mathrm{NO}_{2}\) and \(\mathrm{O}_{2}\) (c) \(\mathrm{NO}_{2}\) and \(\mathrm{N}_{2} \mathrm{O}\) (d) \(\mathrm{NO}\) and \(\mathrm{O}_{2}\)
Step-by-Step Solution
Verified Answer
The correct answer is (b) \( \mathrm{NO}_{2} \) and \( \mathrm{O}_{2} \).
1Step 1: Write the Chemical Reaction
When silver nitrate \( \text{AgNO}_{3} \) is heated, it decomposes into silver metal \( \text{Ag} \), nitrogen dioxide \( \text{NO}_{2} \), and oxygen gas \( \text{O}_{2} \). The balanced chemical equation is: \[ 2 \text{AgNO}_{3(s)} \rightarrow 2 \text{Ag}_{(s)} + 2 \text{NO}_{2(g)} + \text{O}_{2(g)} \]
2Step 2: Identify Products
From the chemical equation, we identify the products of the decomposition of silver nitrate. The products are silver \( \text{Ag} \), nitrogen dioxide \( \text{NO}_{2} \), and oxygen gas \( \text{O}_{2} \).
3Step 3: Match with Given Options
Compare the identified products \( \text{NO}_{2} \) and \( \text{O}_{2} \) with the options provided in the problem. The products match option (b), which lists \( \text{NO}_{2} \) and \( \text{O}_{2} \) as the decomposition products.
Key Concepts
Chemical Equation BalancingThermal DecompositionSilver Nitrate Decomposition
Chemical Equation Balancing
Balancing chemical equations is a crucial skill in chemistry as it ensures the conservation of mass. When a chemical reaction occurs, atoms aren't lost or gained but merely rearranged. Thus, a balanced chemical equation reflects this principle. For instance, when we examine the decomposition of silver nitrate, it initially presents itself as: \[ \mathrm{AgNO}_{3} \rightarrow \mathrm{Ag} + \mathrm{NO}_{2} + \mathrm{O}_{2} \]This equation is unbalanced because the number of atoms of each element does not match on both sides. To balance it, we must adjust coefficients to ensure equal numbers of each type of atom appear on both sides of the equation. For the reaction, the balanced form becomes:\[ 2 \mathrm{AgNO}_{3} \rightarrow 2 \mathrm{Ag} + 2 \mathrm{NO}_{2} + \mathrm{O}_{2} \]Here, every element has an equal count on both the reactant and product sides: - Silver: 2 atoms each side- Nitrogen: 2 atoms each side- Oxygen: 6 atoms each side (2×3 from \(\mathrm{AgNO}_{3}\) and 2×2 from \(\mathrm{NO}_{2}\) plus 2 from \(\mathrm{O}_{2}\))Balancing equations helps in predicting product amounts accurately, which is critical for any experiment or industrial chemical process.
Thermal Decomposition
Thermal decomposition is a type of chemical reaction where a compound breaks down into simpler products when heated. This process is prevalent across various substances, leading to significant changes in composition and properties. Silver nitrate is a prime example, which decomposes upon heating into elemental silver, nitrogen dioxide, and oxygen, as demonstrated by:\[ 2 \mathrm{AgNO}_{3(s)} \rightarrow 2 \mathrm{Ag}_{(s)} + 2 \mathrm{NO}_{2(g)} + \mathrm{O}_{2(g)} \]During thermal decomposition:
- Heat provides the energy needed to break chemical bonds.
- The stability of the compound under heat influences whether decomposition will occur.
- Different compounds decompose at different temperatures.
Silver Nitrate Decomposition
The decomposition of silver nitrate is a classic chemical reaction often studied in chemistry due to its simplicity and clear demonstration of principles. When silver nitrate heats up, the compound transitions from a white crystalline solid into decomposition products:
- Silver metal (\(\mathrm{Ag}\)) is formed as a solid deposit, often as a pale, metallic residue in the reaction container.
- Nitrogen dioxide (\(\mathrm{NO}_{2}\)), a toxic brown gas, is released. This gas, being heavier than air, can pose environmental and health risks if not managed properly.
- Oxygen gas (\(\mathrm{O}_{2}\)) is also produced, contributing to the reaction's gas output and exhibiting the principle of releasing simpler gaseous products.
Other exercises in this chapter
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