Problem 109
Question
When 2 -methyl butan-1-ol is dehydrated to give an alkene, the preferred product is (a) but-1-ene (b) but-2-ene (c) 2 -methyl but-1-ene
Step-by-Step Solution
Verified Answer
(c) 2-methylbut-2-ene is the preferred product due to greater stability from increased substitution.
1Step 1: Identify the Given Compound
The given compound is 2-methylbutan-1-ol, which is an alcohol. The structure of the compound includes a hydroxyl group (-OH) attached to the first carbon of a four-carbon backbone with a methyl group attached to the second carbon.
2Step 2: Understand Dehydration Reaction
Dehydration of an alcohol involves the removal of a water molecule (H2O) from the alcohol, resulting in the formation of a double bond, thus converting the alcohol into an alkene.
3Step 3: Determine the Major Product Using Zaitsev's Rule
According to Zaitsev's Rule, during an elimination reaction, the more substituted alkene (the alkene with more alkyl groups attached to the double-bonded carbons) is generally the more stable and favored product.
4Step 4: Apply Zaitsev's Rule to Identify Preferred Alkene
In this reaction, the removal of water (specifically the -OH and a hydrogen from the second carbon) will lead to the formation of 2-methylbut-2-ene as the major product, since it has a more substituted and thus more stable double bond.
Key Concepts
Zaitsev's Rule2-methylbutan-1-olAlkene Formation
Zaitsev's Rule
When dealing with reactions that involve the removal of atoms or groups, Zaitsev's Rule becomes incredibly important. This rule predicts the predominant arrangement of the atoms in the alkene product formed by the dehydration of alcohols.
In simple terms, during an elimination reaction, the more stable alkene is favored. Stability in this context means that the alkene should have as many alkyl groups attached to the double-bonded carbons as possible.
- The more alkyl substituents around the double bond, the more stable the alkene.
- This is because alkyl groups are electron-releasing, which stabilizes the positive charge in the transition state.
2-methylbutan-1-ol
2-methylbutan-1-ol is an alcohol, which is an organic compound that contains a hydroxyl group (-OH) attached to a saturated carbon atom. In 2-methylbutan-1-ol, the structure is particularly special because of its branching.
Here's the breakdown:
Here's the breakdown:
- A four-carbon chain forms the backbone of this molecule.
- A methyl group ( -CH₃) is attached to the second carbon atom, giving it a branched structure.
- The alcohol functional group (-OH) is on the first carbon, which classifies it as a primary alcohol.
Alkene Formation
In organic chemistry, alkene formation is a central reaction, particularly when it comes from alcohol dehydration. Dehydration is a chemical reaction where water is removed from the alcohol molecule, resulting in an alkene.
The process involves two steps:
Zaitsev's Rule helps in predicting this step by favoring more substituted alkenes, which are more stable. In the case of 2-methylbutan-1-ol, the dehydration most likely leads to 2-methylbut-2-ene, a more stable, substituted alkene, thus demonstrating the efficiency of Zaitsev's Rule in experimental reactions.
The process involves two steps:
- Removing the hydroxyl group (-OH) from the alcohol.
- Removing a hydrogen atom from a neighboring carbon atom.
Zaitsev's Rule helps in predicting this step by favoring more substituted alkenes, which are more stable. In the case of 2-methylbutan-1-ol, the dehydration most likely leads to 2-methylbut-2-ene, a more stable, substituted alkene, thus demonstrating the efficiency of Zaitsev's Rule in experimental reactions.
Other exercises in this chapter
Problem 107
In the solvolysis of 3 -methyl-3-bromohexane, which of the following statements is not correct? (a) it involves carbocation intermediate (b) the intermediate in
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