Problem 109
Question
Verify that equation is an identity. \((2 \sin x+\cos x)^{2}+(2 \cos x-\sin x)^{2}=5\)
Step-by-Step Solution
Verified Answer
The equation is an identity as both sides simplify to 5.
1Step 1 - Expand the Squared Terms
First, let's expand each squared term inside the expression:\[(2 \sin x + \cos x)^{2} = (2 \sin x + \cos x)(2 \sin x + \cos x) = 4 \sin^2 x + 4 \sin x \cos x + \cos^2 x\]\[(2 \cos x - \sin x)^{2} = (2 \cos x - \sin x)(2 \cos x - \sin x) = 4 \cos^2 x - 4 \sin x \cos x + \sin^2 x\]
2Step 2 - Combine Like Terms
Now, add the two expanded expressions together:\[4 \sin^2 x + 4 \sin x \cos x + \cos^2 x + 4 \cos^2 x - 4 \sin x \cos x + \sin^2 x\]
3Step 3 - Simplify the Expression
Combine like terms in the expression from Step 2:1. Combine \( \sin^2 x \) terms: \(4 \sin^2 x + \sin^2 x = 5 \sin^2 x\)2. Combine \( \cos^2 x \) terms: \(4 \cos^2 x + \cos^2 x = 5 \cos^2 x\)3. The \( \sin x \cos x \) terms cancel each other out: \(4 \sin x \cos x - 4 \sin x \cos x = 0\)This simplifies to:\[5 \sin^2 x + 5 \cos^2 x\]
4Step 4 - Apply Trigonometric Identity
Recall the fundamental trigonometric identity: \( \sin^2 x + \cos^2 x = 1\).Substitute this identity into the expression:\[5 (\sin^2 x + \cos^2 x) = 5 \times 1 = 5\]
5Step 5 - Verify the Identity
Finally, confirm that the identity holds:By simplifying, our left side \((2 \sin x + \cos x)^{2} + (2 \cos x - \sin x)^{2}\) simplifies to 5, which matches the right side of the original equation. Thus, the equation is an identity.
Key Concepts
Algebraic ManipulationSimplifying ExpressionsFundamental Trigonometric Identity
Algebraic Manipulation
In mathematics, especially in algebra and trigonometry, algebraic manipulation is a critical skill. It involves rearranging and transforming expressions by following algebraic rules. This can include operations such as expanding, factoring, and simplifying expressions. In the exercise provided, the goal of algebraic manipulation is to verify the given trigonometric identity.Let's focus on expanding the squared terms:
- The term \(2 \sin x + \cos x\) is expanded by multiplying it by itself, leading to the expression \(4 \sin^2 x + 4 \sin x \cos x + \cos^2 x\).
- Similarly, \(2 \cos x - \sin x\) is expanded to \(4 \cos^2 x - 4 \sin x \cos x + \sin^2 x\).
Simplifying Expressions
The process of simplifying expressions reduces mathematical expressions to their most basic form. This does not change the expression's value but makes it easier to interpret and solve.In our example, after expanding the squared terms, we need to combine like terms:
- The \(\sin^2 x\) terms add up to \(5 \sin^2 x\).
- The \(\cos^2 x\) terms combine to form \(5 \cos^2 x\).
- The \(\sin x \cos x\) terms cancel each other out, equating to zero.
Fundamental Trigonometric Identity
Trigonometric identities are equations that hold true for all values within their domains. Among these, the fundamental trigonometric identity \(\sin^2 x + \cos^2 x = 1\) is particularly noteworthy.In solving our exercise, after simplification, we reach \(5 \sin^2 x + 5 \cos^2 x\). Leveraging the fundamental identity, we substitute \(\sin^2 x + \cos^2 x\) with 1, transforming the expression into \(5 \times 1 = 5\).This identity not only verifies our original equation but also demonstrates the powerful tool that trigonometric identities provide in simplifying and solving equations.Understanding these identities and knowing when to apply them is crucial:
- They simplify complex-trigonometric expressions.
- They allow verification of trigonometric equations.
- They are pivotal in fields such as engineering, physics, and computer science.
Other exercises in this chapter
Problem 109
Write each expression as an algebraic expression in \(u, u>0\). $$\tan \left(\sin ^{-1} \frac{u}{\sqrt{u^{2}+2}}\right)$$
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Verify that each equation is an identity by using any of the identities introduced in the first three sections of this chapter. $$\frac{\cos ^{4} x-\sin ^{4} x}
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Write each expression as an algebraic expression in \(u, u>0\). $$\sec \left(\cos ^{-1} \frac{u}{\sqrt{u^{2}+5}}\right)$$
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Verify that each equation is an identity by using any of the identities introduced in the first three sections of this chapter. $$\frac{\csc t+1}{\csc t-1}=(\se
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