Problem 109
Question
Electrical Resistance If two electrical resistors with resistances R1 and R2 are connected in parallel (see the figure), then the total resistance R is given by $$ R=\frac{1}{\frac{1}{R_{1}}+\frac{1}{R_{2}}} $$ (a) Simplify the expression for \(R\) . (b) If \(R_{1}=10\) ohms and \(R_{2}=20\) ohms, what is the total resistance \(R ?\)
Step-by-Step Solution
Verified Answer
R = \( \frac{R_1 R_2}{R_1 + R_2} \); for \( R_1 = 10 \) and \( R_2 = 20 \), \( R \approx 6.67 \) ohms.
1Step 1: Write the Formula
We are given the formula for total resistance when two resistors are connected in parallel: \[ R = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2}} \] Our task is to simplify this expression.
2Step 2: Find a Common Denominator
The expression \( \frac{1}{R_1} + \frac{1}{R_2} \) can be combined by finding a common denominator. The common denominator for \( R_1 \) and \( R_2 \) is \( R_1 \times R_2 \). Rewrite the expression as: \[ \frac{1}{R_1} + \frac{1}{R_2} = \frac{R_2}{R_1 R_2} + \frac{R_1}{R_1 R_2} \]
3Step 3: Combine the Fractions
Now, combine the fractions: \[ \frac{R_2}{R_1 R_2} + \frac{R_1}{R_1 R_2} = \frac{R_2 + R_1}{R_1 R_2} \]
4Step 4: Simplify the Resistance Formula
Substitute the combined fraction into the original resistance formula: \[ R = \frac{1}{\frac{R_1 + R_2}{R_1 R_2}} \] Simplify by multiplying: \[ R = \frac{R_1 R_2}{R_1 + R_2} \] This is the simplified expression for the total resistance \( R \).
5Step 5: Insert Values for R1 and R2
Given \( R_1 = 10 \) ohms and \( R_2 = 20 \) ohms, substitute these values into the simplified formula: \[ R = \frac{10 \times 20}{10 + 20} \]
6Step 6: Calculate the Total Resistance
Calculate the expression: \[ R = \frac{200}{30} = \frac{20}{3} \] The total resistance is approximately \( 6.67 \) ohms.
Key Concepts
Parallel ResistorsResistor FormulaResistance CalculationOhm's Law
Parallel Resistors
When we have two or more resistors in an electrical circuit, they can be connected in different ways: series or parallel. Today, we're focusing on parallel connections. In a parallel connection, each resistor is connected across the same two points. This means the voltage across each resistor is the same.
Parallel resistors have an interesting property: their overall resistance is lower than the smallest resistance in the group. This happens because the current has multiple paths to take, reducing the total resistance that the current experiences.
In essence, connecting resistors in parallel helps spread out the electrical flow, making it easier for electricity to travel through the circuit. The formula to calculate total resistance when resistors are placed in parallel is essential to ensure you understand how the total resistance changes with parallel configurations.
Parallel resistors have an interesting property: their overall resistance is lower than the smallest resistance in the group. This happens because the current has multiple paths to take, reducing the total resistance that the current experiences.
In essence, connecting resistors in parallel helps spread out the electrical flow, making it easier for electricity to travel through the circuit. The formula to calculate total resistance when resistors are placed in parallel is essential to ensure you understand how the total resistance changes with parallel configurations.
Resistor Formula
The formula for calculating the total resistance of resistors in parallel is:
The formula we used in our exercise simplifies this basic principle for two resistors:
- \[\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n} \]
The formula we used in our exercise simplifies this basic principle for two resistors:
- \[R = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2}}\]
Resistance Calculation
Calculating resistance, especially in parallel circuits, requires attention to detail. The first step involves using the formula above to combine the resistances. Our task was to simplify this for two resistors, resulting in:
For the example in the problem, we calculated the total resistance for \( R_1 = 10 \) ohms and \( R_2 = 20 \) ohms. Plugging these numbers into our simplified expression resulted in a total resistance of approximately 6.67 ohms.
Understanding how to perform these calculations accurately is key to mastering circuitry, especially in designing circuits where precise resistance levels are crucial.
- \[ R = \frac{R_1 R_2}{R_1 + R_2} \]
For the example in the problem, we calculated the total resistance for \( R_1 = 10 \) ohms and \( R_2 = 20 \) ohms. Plugging these numbers into our simplified expression resulted in a total resistance of approximately 6.67 ohms.
Understanding how to perform these calculations accurately is key to mastering circuitry, especially in designing circuits where precise resistance levels are crucial.
Ohm's Law
Ohm's Law is a fundamental principle in the study of circuits and electronics. It states that the current \( I \) flowing through a conductor between two points is directly proportional to the voltage \( V \) across the two points and inversely proportional to the resistance \( R \) within the circuit.
By determining the total resistance in a parallel circuit, we can then use Ohm's Law to find the total current or total voltage, ensuring that we can tackle more complex circuit problems with confidence.
- \( V = I \times R \)
By determining the total resistance in a parallel circuit, we can then use Ohm's Law to find the total current or total voltage, ensuring that we can tackle more complex circuit problems with confidence.
Other exercises in this chapter
Problem 108
State whether the given equation is true for all values of the variables. (Disregard any value that makes a denominator zero.) $$ \frac{1+x+x^{2}}{x}=\frac{1}{x
View solution Problem 108
Distances Between Powers Which pair of numbers is closer together? $$ 10^{10} \text { and } 10^{50} \quad \text { or } \quad 10^{100} \text { and } 10^{101} $$
View solution Problem 109
Signs of Numbers Let \(a, b,\) and \(c\) be real numbers with \(a>0, b
View solution Problem 110
Average Cost \(A\) clothing manufacturer finds that the cost of producing \(x\) shirts is \(500+6 x+0.01 x^{2}\) dollars. (a) Explain why the average cost per s
View solution