Problem 109
Question
(a) If the temperature of a gas is doubled while the pressure is kept constant, the volume of the gas (b) If the pressure of a gas is halved while the temperature is kept constant, the volume of the gas
Step-by-Step Solution
Verified Answer
(a) When the temperature of a gas is doubled while the pressure is kept constant, the volume of the gas is doubled (\(V2 = 2 * V1\)).
(b) When the pressure of a gas is halved while the temperature is kept constant, the volume of the gas is doubled (\(V2 = 2 * V1\)).
1Step 1: Write down the ideal gas law equation
The ideal gas law states that (P * V) / T = constant.
2Step 2: Find the initial and final states
In this case, the initial state has temperature T1, pressure P1, and volume V1. The final state has temperature 2 * T1 (since the temperature is doubled), pressure P1 (since the pressure is constant), and volume V2.
3Step 3: Apply the ideal gas law for the initial and final states
For the initial state: (P1 * V1) / T1 = C
For the final state: (P1 * V2) / (2 * T1) = C
4Step 4: Compare the initial and final states
Since the constant C is the same for both equations, we can set them equal to each other:
(P1 * V1) / T1 = (P1 * V2) / (2 * T1)
5Step 5: Solve for the final volume V2
By cross-multiplying and simplifying, we get:
V2 = 2 * V1
So, the volume of the gas when the temperature is doubled and the pressure is kept constant is double the initial volume.
#Scenario 2: Pressure halved while the temperature is kept constant#
6Step 1: Write down the ideal gas law equation
The ideal gas law states that (P * V) / T = constant.
7Step 2: Find the initial and final states
In this case, the initial state has temperature T1, pressure P1, and volume V1. The final state has temperature T1 (since the temperature is constant), pressure P1/2 (since the pressure is halved), and volume V2.
8Step 3: Apply the ideal gas law for the initial and final states
For the initial state: (P1 * V1) / T1 = C
For the final state: ((P1/2) * V2) / T1 = C
9Step 4: Compare the initial and final states
Since the constant C is the same for both equations, we can set them equal to each other:
(P1 * V1) / T1 = ((P1/2) * V2) / T1
10Step 5: Solve for the final volume V2
By cross-multiplying and simplifying, we get:
V2 = 2 * V1
So, the volume of the gas when the pressure is halved and the temperature is kept constant is double the initial volume.
Key Concepts
temperature and volume relationshippressure and volume relationshipgas laws in chemistry
temperature and volume relationship
When exploring the relationship between temperature and volume in gases, we need to consider Charles's Law. It is a part of the ideal gas law and states that, at constant pressure, the volume of a gas is directly proportional to its temperature. This means that as the temperature of a gas increases, its volume will also increase if the pressure is constant.
For example:
For example:
- Doubling the temperature of an ideal gas will double the volume, assuming the pressure stays the same.
- Conversely, if the temperature is halved, the volume is also halved.
pressure and volume relationship
Another key relationship in gas behavior is explained by Boyle's Law. This principle highlights that the volume of a gas is inversely proportional to its pressure when temperature remains constant. Practically, this means if you increase the pressure exerted on a gas, its volume will decrease and vice versa.
Consider these scenarios:
Consider these scenarios:
- When pressure is doubled, the volume of the gas is reduced by half.
- If the pressure is halved, the volume will double.
gas laws in chemistry
The behavior of gases is primarily governed by three classical gas laws: Boyle’s Law, Charles’s Law, and Avogadro's Law, collectively integrated into the Ideal Gas Law. The ideal gas law formulates how pressure, volume, temperature, and the number of molecules relate to each other in a typical gas setting. It is expressed with the equation \( PV = nRT \), where:
- \( P \) stands for pressure,
- \( V \) is volume,
- \( n \) signifies the number of moles of gas,
- \( R \) is the ideal gas constant,
- \( T \) symbolizes temperature.
Other exercises in this chapter
Problem 107
In the laboratory preparation of oxygen gas, the following reaction is carried out: \(2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)\)
View solution Problem 108
In an ideal gas, the molecules are considered to have no forces.
View solution Problem 110
What is the Celsius temperature of a gas if \(3.200\) moles of it occupy \(12.00 \mathrm{~L}\) at \(8.500 \mathrm{~atm} ?\)
View solution Problem 111
A \(1.25-g\) sample of a gas of unknown identity occupies \(2.50 \mathrm{~L}\). and exerts a pressure of \(0.400 \mathrm{~atm}\) at \(0^{\circ} \mathrm{C}\). (a
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