Problem 108
Question
Solve \(x^{2}-4 x+k=0\) for \(k=0,4,5,\) and 10. a) When does the equation have only one solution? b) For what values of \(k\) are the solutions real? c) For what values of \(k\) are the solutions imaginary?
Step-by-Step Solution
Verified Answer
a) k = 4b) k = 0, 4c) k = 5, 10
1Step 1 - Determine the Discriminant
For a quadratic equation of the form x^2 + bx + c = 0the discriminant D = b^2 - 4ac.Determine the discriminant for the given equation.
2Step 2 - Calculate the Discriminant for Each k Value
Substitute the values of k (0, 4, 5, 10) into the equation and calculate the discriminant D.For k = 0: D = (-4)^2 - 4(1)(0) = 16For k = 4: D = (-4)^2 - 4(1)(4) = 0For k = 5: D = (-4)^2 - 4(1)(5) = -4For k = 10: D = (-4)^2 - 4(1)(10) = -24
3Step 3 - Analyze the Discriminant Values
Use the discriminant to determine the nature of the solutions.If D > 0, there are two distinct real solutions.If D = 0, there is exactly one real solution.If D < 0, the solutions are imaginary.
4Step 4 - Answer When Equation Has Only One Solution
The equation has only one solution when the discriminant is zero.When k = 4, D = 0, so the equation has exactly one solution for k = 4.
5Step 5 - Answer for Real Solutions
The solutions are real when the discriminant is greater than or equal to zero.For k = 0: D = 16 (real solutions)For k = 4: D = 0 (one real solution)
6Step 6 - Answer for Imaginary Solutions
The solutions are imaginary when the discriminant is less than zero.For k = 5: D = -4 (imaginary solutions)For k = 10: D = -24 (imaginary solutions)
Key Concepts
discriminant in quadratic equationsreal solutionsimaginary solutionsquadratic discriminant analysis
discriminant in quadratic equations
In quadratic equations, the discriminant is a crucial tool for understanding the nature of the solutions. For a general quadratic equation of the form \(ax^2 + bx + c = 0\), the discriminant \(D\) is given by the formula: \[\text{D} = b^2 - 4ac\]. The value of the discriminant tells us whether the solutions to the equation are real or imaginary, and whether they are distinct or repeated.
real solutions
Real solutions in quadratic equations occur when the discriminant is greater than or equal to zero.
We use the following rules to understand this:
For \k = 0\, \D = 16\ (2 real solutions)
For \k = 4\, \D = 0\ (1 real solution)
We use the following rules to understand this:
- If \[\text{D} > 0\], there are two distinct real solutions.
- If \[\text{D} = 0\], there is exactly one real solution, which is also called a repeated root.
For \k = 0\, \D = 16\ (2 real solutions)
For \k = 4\, \D = 0\ (1 real solution)
imaginary solutions
Imaginary solutions occur when the discriminant is less than zero, indicating that the quadratic equation has no real solutions. Instead, it results in complex numbers.
In mathematical terms:
For \k = 5\, \D = -4\ (2 imaginary solutions)
For \k = 10\, \D = -24\ (2 imaginary solutions)
In mathematical terms:
- If \[\text{D} < 0\], the solutions are imaginary.
For \k = 5\, \D = -4\ (2 imaginary solutions)
For \k = 10\, \D = -24\ (2 imaginary solutions)
quadratic discriminant analysis
Quadratic discriminant analysis involves examining the discriminant to determine the nature and number of solutions of a quadratic equation. It allows us to see if the solutions are real or imaginary, and whether the real solutions are distinct or repeated.
Let's break down the discriminant analysis for the equation \x^2 - 4x + k = 0\ based on various \text{k}\ values:
Let's break down the discriminant analysis for the equation \x^2 - 4x + k = 0\ based on various \text{k}\ values:
- \k = 0\rightarrow \[D = 16\] (2 real solutions)
- \k = 4\rightarrow \[D = 0\] (1 real solution)
- \k = 5\rightarrow \[D = -4\] (2 imaginary solutions)
- \k = 10\rightarrow \[D = -24\] (2 imaginary solutions)
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