Problem 108
Question
In Exercises \(97-108,\) graph by hand the equation of the circle or the parabola with a horizontal axis. $$x=(y-2)^{2}-1$$
Step-by-Step Solution
Verified Answer
The parabola opens to the right with vertex \((-1, 2)\).
1Step 1: Identify the Equation
The given equation is \( x = (y - 2)^2 - 1 \). This is the equation of a parabola with the form \(x = a(y - k)^2 + h\), indicating that it opens horizontally.
2Step 2: Determine the Vertex
The vertex form of the horizontal parabola equation is \(x = a(y - k)^2 + h\), where \( (h, k) \) is the vertex. For \( x=(y-2)^2-1 \), we identify the vertex as \( (-1, 2) \).
3Step 3: Determine the Direction
The coefficient \(a\) in \( (y - k)^2 \) determines the direction the parabola opens. Here, \(a = 1\) (positive), so the parabola opens to the right.
4Step 4: Plot the Vertex
Plot the point \((-1, 2)\) as the vertex on the graph. This is the starting point for drawing the parabola.
5Step 5: Choose Additional Points
Select values for \(y\), such as \(y = 0, 1, 3, 4\), and substitute them into the equation to find corresponding \(x\) values.
6Step 6: Calculate and Plot Points
Calculate: - For \(y = 0\), \(x = 3\). - For \(y = 1\), \(x = 0\). - For \(y = 3\), \(x = 0\). - For \(y = 4\), \(x = 3\). Plot these points: \( (3, 0), (0, 1), (0, 3), (3, 4) \) on the graph.
7Step 7: Draw the Parabola
Using the plotted points, sketch a smooth curve from the vertex through these points to create the parabola, ensuring it opens to the right.
Key Concepts
vertex formhorizontal parabolasplotting points
vertex form
The vertex form is a useful way to express the equation of a parabola, allowing you to easily identify the vertex. For horizontal parabolas, the equation takes the form \(x = a(y - k)^2 + h\), where \((h, k)\) represents the vertex of the parabola.
The vertex is a crucial point, as it is the point where the parabola changes direction. It's essentially the 'center' of the parabola.
The vertex is a crucial point, as it is the point where the parabola changes direction. It's essentially the 'center' of the parabola.
- In the equation \(x = (y - 2)^2 - 1\), we have \(h = -1\) and \(k = 2\). Thus, the vertex is \((-1, 2)\).
- Recognizing the vertex form helps in determining how to shift the parabola on the coordinate plane.
horizontal parabolas
Horizontal parabolas open either to the right or to the left, unlike the more common vertical parabolas which open upward or downward.
The general form of a horizontal parabola is \(x = a(y - k)^2 + h\).
This form allows us to immediately see the direction in which the parabola opens:
The general form of a horizontal parabola is \(x = a(y - k)^2 + h\).
This form allows us to immediately see the direction in which the parabola opens:
- If \(a > 0\), the parabola opens to the right.
- If \(a < 0\), the parabola opens to the left.
plotting points
Plotting points is essential for accurately drawing a parabola on a graph. Once you've identified the vertex, the next step is to choose additional points that the parabola will pass through.
Each chosen \(y\)-value will allow you to solve for an \(x\)-value, giving a coordinate to plot.
Each chosen \(y\)-value will allow you to solve for an \(x\)-value, giving a coordinate to plot.
- For instance, selecting \(y = 0\), you calculate \(x = 3\), leading to the point \((3, 0)\).
- Another example is \(y = 1\), where \(x = 0\), resulting in the point \((0, 1)\).
Other exercises in this chapter
Problem 107
In Exercises \(97-108,\) graph by hand the equation of the circle or the parabola with a horizontal axis. $$x=-(y+1)^{2}+2$$
View solution Problem 108
Solve each problem involving rate of work. A sink can be filled by the hot-water tap alone in \(4 \mathrm{min}\) utes more than it takes the cold-water tap alon
View solution Problem 109
In Exercises \(109-116\), describe the graph of the equation as either a circle or a parabola with a horizontal axis of symmetry. Then, determine two functions,
View solution Problem 110
In Exercises \(109-116\), describe the graph of the equation as either a circle or a parabola with a horizontal axis of symmetry. Then, determine two functions,
View solution