Problem 108
Question
Find the equation of the line that passes through the following points: \((2 a, b)\) and \((a, b+1)\).
Step-by-Step Solution
Verified Answer
The equation is \(y = -\frac{1}{a}x + (b + 2)\).
1Step 1: Identify the Points
We have two points given: - Point 1 is \((x_1, y_1) = (2a, b)\) - Point 2 is \((x_2, y_2) = (a, b+1)\).
2Step 2: Calculate the Slope
The formula for the slope \(m\) of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) is:\[m = \frac{y_2 - y_1}{x_2 - x_1}\]Substitute the given points into the formula:\[m = \frac{(b+1) - b}{a - 2a} = \frac{1}{-a} = -\frac{1}{a}\].
3Step 3: Use the Point-Slope Form
The point-slope form of a line is:\[y - y_1 = m(x - x_1)\]Using Point 1 \((2a, b)\) and the slope \(-\frac{1}{a}\), the equation becomes:\[y - b = -\frac{1}{a}(x - 2a)\].
4Step 4: Simplify the Equation
Distribute and simplify the equation from the previous step:\[y - b = -\frac{1}{a}x + 2\]\[y = -\frac{1}{a}x + 2 + b\].
5Step 5: Write the Final Equation
The equation of the line in slope-intercept form is:\[y = -\frac{1}{a}x + (b + 2)\].
Key Concepts
slope calculationpoint-slope formslope-intercept formalgebra
slope calculation
In algebra, understanding how to calculate the slope between two points is essential. The slope of a line measures its steepness and direction. It is calculated using two points, often represented as \((x_1, y_1)\) and \((x_2, y_2)\).
The formula for the slope \(m\) is:
Substituting the given points \((2a, b)\) and \((a, b+1)\) into the formula:
The formula for the slope \(m\) is:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Substituting the given points \((2a, b)\) and \((a, b+1)\) into the formula:
- \( m = \frac{(b+1) - b}{a - 2a} = \frac{1}{-a} = -\frac{1}{a} \)
point-slope form
Once the slope is known, the point-slope form is a powerful tool to express the equation of a line. It is especially helpful when you have one point and the slope.
The point-slope form is represented as:
Using the slope \(-\frac{1}{a}\) and point \((2a, b)\), the equation becomes:
It will eventually lead us to a more commonly used form, the slope-intercept form, through further simplification.
The point-slope form is represented as:
- \( y - y_1 = m(x - x_1) \)
Using the slope \(-\frac{1}{a}\) and point \((2a, b)\), the equation becomes:
- \( y - b = -\frac{1}{a}(x - 2a) \)
It will eventually lead us to a more commonly used form, the slope-intercept form, through further simplification.
slope-intercept form
Simplifying a point-slope equation often leads to the slope-intercept form. This is the most recognized equation of a line, expressed as \(y = mx + b\), where \(m\) is the slope, and \(b\) is the y-intercept.
Simplifying the equation from the point-slope form \(y - b = -\frac{1}{a}(x - 2a)\), you distribute and rearrange terms:
Recognizing different forms of linear equations is crucial for various algebraic applications.
The slope-intercept form is particularly useful for graphing and analyzing the behavior of lines.
Simplifying the equation from the point-slope form \(y - b = -\frac{1}{a}(x - 2a)\), you distribute and rearrange terms:
- \( y - b = -\frac{1}{a}x + 2 \)
- \( y = -\frac{1}{a}x + 2 + b \)
- \( y = -\frac{1}{a}x + (b + 2) \)
Recognizing different forms of linear equations is crucial for various algebraic applications.
The slope-intercept form is particularly useful for graphing and analyzing the behavior of lines.
algebra
Algebra serves as the foundational language of mathematics, enabling you to describe relationships between quantities.
At its core, it involves using symbols and letters to represent numbers and express mathematical ideas in general terms.
In working with equations of lines, algebra allows you to:
These skills build upon the basic principles of algebra, showcasing its importance in widespread areas of mathematics and real-world problem solving.
At its core, it involves using symbols and letters to represent numbers and express mathematical ideas in general terms.
In working with equations of lines, algebra allows you to:
- Determine relationships between variables
- Solve for unknowns
- Transform equations to different forms
These skills build upon the basic principles of algebra, showcasing its importance in widespread areas of mathematics and real-world problem solving.
Other exercises in this chapter
Problem 106
Find the value of \(y\) if a linear function goes through the following points and has the following slope: \((10, y),(25,100), m=-5\).
View solution Problem 107
Find the equation of the line that passes through the following points: \((a, b)\) and \((a, b+1)\).
View solution Problem 109
Find the equation of the line that passes through the following points: \((a, 0)\) and \((c, d)\).
View solution Problem 110
Find the equation of the line parallel to the line \(g(x)=-0.01 x+2.01\) through the point (1,2).
View solution