Problem 108
Question
At \(\mathrm{pH}=4\), glycine exists as (a) \(\mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-}\) (b) \(\mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}\) (c) \(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}\) (d) \(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-}\)
Step-by-Step Solution
Verified Answer
At pH 4, glycine exists as \(\mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-}\).
1Step 1: Understand the pH Meaning
The pH of the solution is 4, which is slightly acidic. At this pH, we need to determine the dominant form of glycine, an amino acid.
2Step 2: Consider Glycine and Its Forms
Glycine can exist in different ionized forms depending on the pH. The relevant forms are the protonated amine form \(\mathrm{H}_3\mathrm{N}^+\) and carboxyl groups \(\mathrm{COOH}\), and their dissociated forms \(\mathrm{H}_2\mathrm{N}\) and \(\mathrm{COO}^-\).
3Step 3: Analyze pKa Values of Glycine
Glycine has two relevant pKa values: one around 2.34 for the \(\mathrm{COOH/COO}^-\) transition and one around 9.6 for the \(\mathrm{H}_3\mathrm{N}^+/\mathrm{H}_2\mathrm{N}\) transition. At pH 4, it is above the first pKa and below the second.
4Step 4: Determine Charge on Groups
Since pH 4 is above the pKa of the carboxyl group, it will exist in the \(\mathrm{COO}^-\) form. Since pH 4 is below the pKa of the amine group, it will remain in the \(\mathrm{H}_3\mathrm{N}^+\) form.
5Step 5: Identify the Zwitterionic Form at pH 4
Given the analyses, glycine at pH 4 will have \(\mathrm{H}_3\mathrm{N}^+\) and \(\mathrm{COO}^-\) groups, corresponding to the zwitterionic structure \(\mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-}\).
Key Concepts
Amino Acid StructurespH and pKa RelationshipIonization of Amino Acids
Amino Acid Structures
Amino acids are the building blocks of proteins and are essential for various functions in living organisms. Each amino acid consists of a central carbon atom (called the alpha carbon), to which four different groups are attached:
- An amino group (5hnH5hnH3N
- A carboxyl group (5hnCOOH
- A hydrogen atom
- A variable side chain (R group), which differentiates one amino acid from another
pH and pKa Relationship
The pH is a measure of the acidity or basicity of a solution, which correlates with the concentration of hydrogen ions (H⁺) in the solution. Instruments like pKa are used to understand the propensity of chemical groups like the carboxyl group and amino group to donate or accept protons:
- pKa indicates the pH at which the group is 50% ionized.
- If the pH is lower than the pKa, the group tends to stay protonated (e.g., 5hnCOOH rather than 5hnCOO^-).
- If the pH is higher than the pKa, the group tends to deprotonate (e.g., 5hnNH_2 over 5hnNH3^+).
Ionization of Amino Acids
Ionization refers to the process in which an atom or a molecule gains or loses an electron, forming ions. In the context of amino acids, this process involves the ionization of specific functional groups:
- Carboxyl group (5hnCOOH): It ionizes to become 5hnCOO^- by losing a proton (H^+).
- Amino group (5hnNH2): It can accept a proton to become 5hnNH3^+.
Other exercises in this chapter
Problem 106
Sucrose on hydrolysis gives (a) glucose \(+\) glucose (b) glucose \(+\) galactose (c) glucose + fructose (d) glucose + lactose
View solution Problem 107
State the correct general formula of carbohydrates (a) \(\mathrm{C}_{x}\left(\mathrm{H}_{2}\right)_{y} \mathrm{O}\) (b) \(\mathrm{C}_{x-1}\left(\mathrm{H}_{2} \
View solution Problem 109
In addition to aldehyde group glucose contains (a) one secondary OH and four primary OH groups (b) one primary OH and four secondary OH groups (c) two primary O
View solution Problem 110
Thymine is (a) 5 -methyluracil (b) 4-methyluracil (c) 3-methyluracil (d) 1-methyluracil
View solution