Problem 107
Question
Without using a calculator, determine which is the greater number: \(\log _{4} 60\) or \(\log _{3} 40.\)
Step-by-Step Solution
Verified Answer
\(\log_3 40\) is greater than \(\log_4 60\).
1Step 1: Rewrite with the change of base formula
First, rewrite the given logarithms using the change of base formula: \(log_b a > log_c d\) if and only if \(a^c > b^d\). This gives us \(60^3 > 4^{40}\)
2Step 2: Break down expressions to compare them
Evaluate this expression involves large numbers which proves to be difficult without a calculator so it is best to break it down into smaller, more manageable parts which are easier to compare. To do this, apply the property of exponents \(b^{m*n} = (b^m)^n\). This gives \(60^3 = (4*15)^3 = 4^3 * 15^3\) and \(4^{40} = (4^{10})^4\).
3Step 3: Comparison
Once the expression has been simplified, we see that we have \(4^3\) on one side and \(4^4\) on the other side, so clearly \(4^4\) is larger and therefore \(log_3 40\) is greater than \(log_4 60\).
Key Concepts
Understanding the Change of Base FormulaDemystifying ExponentsLogarithmic Comparison Made Simple
Understanding the Change of Base Formula
The change of base formula is a fundamental tool within logarithms that helps us compare logarithms with different bases. This formula allows us to express logarithms in terms of a convenient base, often base 10 or base 'e', which are more familiar and easier to work with.
For any logarithm \log_b(a)\, the change of base formula is expressed as:
This technique is crucial for solving logarithmic problems that involve comparisons or where a calculation might not seem straightforward at first glance.
For any logarithm \log_b(a)\, the change of base formula is expressed as:
- \(\log_b a = \frac{\log_k a}{\log_k b}\)
This technique is crucial for solving logarithmic problems that involve comparisons or where a calculation might not seem straightforward at first glance.
Demystifying Exponents
Exponents, also known as powers, represent repeated multiplication. For instance, \(4^3\) means multiplying 4 by itself three times, which equals 64. Exponents have several important properties that are useful in various mathematical operations.
Key exponent rules include:
Key exponent rules include:
- Power of a Power: \(b^{m\cdot n} = (b^m)^n\)
- Product of Powers: \(b^m \cdot b^n = b^{m+n}\)
- Zero Exponent: \(b^0 = 1\) for any non-zero \(b\)
- Negative Exponent: \(b^{-n} = \frac{1}{b^n}\)
Logarithmic Comparison Made Simple
Logarithmic comparison involves determining which of two logarithmic expressions represents the greater value. To do this effectively, converting logarithmic form into exponential form can often make evaluation more intuitive.
In the original exercise, \(\log_4 60\) and \(\log_3 40\) were compared using their exponent forms. Using the property that \(a^c > b^d\) implies \(\log_b a > \log_c d\), we can transition from logarithms to exponents.
In the original exercise, \(\log_4 60\) and \(\log_3 40\) were compared using their exponent forms. Using the property that \(a^c > b^d\) implies \(\log_b a > \log_c d\), we can transition from logarithms to exponents.
- Convert: Determine equivalent exponential expressions for each logarithm.
- Simplify: Break down into smaller components if the numbers are too large.
- Compare: Analyze the simplified expressions for clear understanding.
Other exercises in this chapter
Problem 105
Without using a calculator, find the exact value of $$\frac{\log _{3} 81-\log _{\pi} 1}{\log _{2 \sqrt{2}} 8-\log 0.001}$$
View solution Problem 106
Solve for \(x: \log _{4}\left[\log _{3}\left(\log _{2} x\right)\right]=0.\)
View solution Problem 108
This group exercise involves exploring the way we grow. Group members should create a graph for the function that models the percentage of adult height attained
View solution Problem 105
If \(f(x)=\log _{\phi} x,\) show that \(\frac{f(x+h)-f(x)}{h}=\log _{b}\left(1+\frac{h}{x}\right)^{1 / h}, h \neq 0\)
View solution