Problem 107
Question
Name each of the following compounds: a. CsF b. \(\mathrm{Li}_{3} \mathrm{N}\) c. \(A g_{2} S\) d. \(\mathrm{MnO}_{2}\) e. \(\mathrm{TiO}_{2}\) f. \(\mathrm{Sr}_{3} \mathrm{P}_{2}\)
Step-by-Step Solution
Verified Answer
The names of the compounds are:
a. Cesium Fluoride
b. Lithium Nitride
c. Silver Sulfide
d. Manganese (IV) Oxide
e. Titanium (IV) Oxide
f. Strontium Phosphide
1Step 1: Identify the elements present in the compound
First, we will need to know the symbols of the chemical elements making up each compound.
a. CsF : Cs is Cesium, F is Fluorine
b. Li3N : Li is Lithium, N is Nitrogen
c. Ag2S : Ag is Silver, S is Sulfur
d. MnO2 : Mn is Manganese, O is Oxygen
e. TiO2 : Ti is Titanium, O is Oxygen
f. Sr3P2 : Sr is Strontium, P is Phosphorus
2Step 2: Determine the type of bonding in the compound
Compounds consisting of metals and non-metals typically form ionic bonds. Metals are elements from groups 1, 2 and 13-15 of the periodic table, while non-metals are elements from groups 14-18. In each case given, the compounds are made up of a metal and a non-metal, so they are ionic compounds.
3Step 3: Apply ionic compound nomenclature
Naming ionic compounds involves writing the name of the metal followed by the name of the non-metal with the ending changed to -ide. If the metal has more than one oxidation state (charge), we use a Roman numeral to indicate the oxidation state.
a. CsF -> Cesium Fluoride
b. Li3N -> Lithium Nitride
c. Ag2S -> Silver Sulfide (Since Silver has only one common oxidation state, +1, no Roman numeral is needed)
d. MnO2 -> Manganese (IV) Oxide (Manganese has a +4 oxidation state, as it binds to 2 Oxygens with -2 charge each)
e. TiO2 -> Titanium (IV) Oxide (Titanium has a +4 oxidation state, as it binds to 2 Oxygens with -2 charge each)
f. Sr3P2 -> Strontium Phosphide
The names of the compounds are:
a. Cesium Fluoride
b. Lithium Nitride
c. Silver Sulfide
d. Manganese (IV) Oxide
e. Titanium (IV) Oxide
f. Strontium Phosphide
Key Concepts
NomenclatureOxidation StateChemical Bonding
Nomenclature
Naming ionic compounds might sound complex at first, but it is quite straightforward if you follow the rules. The name of an ionic compound is derived from its constituent elements: the cation (positive ion, typically a metal) is named first, followed by the anion (negative ion, usually a non-metal). For example, in "Cesium Fluoride" (CsF), "Cesium" is the metal cation and "Fluoride" is the non-metal anion.
For most simple ionic compounds:
For most simple ionic compounds:
- The metal (cation) keeps its elemental name.
- The non-metal (anion) name ends with the suffix -ide, replacing its normal ending.
Oxidation State
Oxidation states represent the number of electrons an atom either gains or loses when bonding. These states are crucial for understanding how elements combine to form compounds. For metals, the oxidation state is typically indicated in the name of the compound using a Roman numeral.
In ionic compounds, non-metals often have set oxidation states, such as -1 for Fluorine. Metals can have multiple oxidation states, such as Manganese (Mn) in MnO₂, which is Manganese (IV) Oxide because Mn exhibits a +4 oxidation state.
Understanding oxidation states is essential in predicting and naming compounds accurately.
Key points to remember:
In ionic compounds, non-metals often have set oxidation states, such as -1 for Fluorine. Metals can have multiple oxidation states, such as Manganese (Mn) in MnO₂, which is Manganese (IV) Oxide because Mn exhibits a +4 oxidation state.
Understanding oxidation states is essential in predicting and naming compounds accurately.
Key points to remember:
- An element's oxidation state changes depending on what it is bound to.
- Roman numerals in names represent the metal's oxidation state.
- Common rules, like "oxygen is typically -2," help predict states.
Chemical Bonding
Chemical bonding involves the interactions between atoms to form compounds. Ionic bonds occur when electrons are transferred from one atom to another, resulting in a compound made of ions—charged particles. This usually happens between metals and non-metals, forming an ionic compound.
Consider the case of Li₃N (Lithium Nitride). Lithium (Li), a metal, donates electrons to Nitrogen (N), a non-metal. This electron exchange keeps both elements balanced and forms a strong ionic bond, creating a stable compound. Ionic compounds have distinctive properties that arise from their bond types:
Consider the case of Li₃N (Lithium Nitride). Lithium (Li), a metal, donates electrons to Nitrogen (N), a non-metal. This electron exchange keeps both elements balanced and forms a strong ionic bond, creating a stable compound. Ionic compounds have distinctive properties that arise from their bond types:
- High melting and boiling points due to strong bonds.
- Ability to conduct electricity when dissolved in water.
- Form crystalline structures in solid form.
Other exercises in this chapter
Problem 105
Name the compounds in parts a-d and write the formulas for the compounds in parts e-h. a. \(\mathrm{NaBr}\) b. \(\mathrm{Rb}_{2} \mathrm{O}\) c. CaS d. \(\mathr
View solution Problem 106
Name the compounds in parts a-d and write the formulas for the compounds in parts e-h. a. \(\mathrm{Hg}_{2} \mathrm{O}\) b. \(\operatorname{FeBr}_{3}\) c. CoS d
View solution Problem 108
Write the formula for each of the following compounds: a. zinc chloride b. \(\operatorname{tin}(1 \mathrm{V})\) fluoride c. calcium nitride d. aluminum sulfide
View solution Problem 109
Name each of the following compounds: a. \(\mathrm{BaSO}_{3}\) b. \(\mathrm{NaNO}_{2}\) c. \(\mathrm{KMnO}_{4}\) \(\mathbf{d .} \mathbf{K}_{2} \mathrm{Cr}_{2} \
View solution