Problem 107
Question
In April 2010, a research team reported that it had made Element 117. This discovery was confirmed in 2012 by additional experiments. Write the ground- state electron configuration for Element 117 and estimate values for its first ionization energy, electron afnity, atomic size, and common oxidation state based on its position in the periodic table.
Step-by-Step Solution
Verified Answer
Element 117, Tennessine (Ts), has a ground-state electron configuration of \([Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{5}\). Its first ionization energy is expected to be high, slightly lower than Astatine. Tennessine's electron affinity should be high, also similar to that of other halogens. Its atomic size is likely larger than Astatine, and Ts's common oxidation state is predicted to be -1.
1Step 1: Ground-state electron configuration
To determine the ground-state electron configuration of Tennessine, follow the periodic table and fill the electron orbitals as per the Aufbau principle until you reach Element 117. The electron configuration will be:
\[ [Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{5} \]
This configuration shows that Element 117 has filled 5f and 6d orbitals, two electrons in the 7s orbital, and five electrons in the 7p orbital.
2Step 2: Estimate the first ionization energy
The first ionization energy is the energy required to remove one electron from an atom to form a positive ion. As we move across a period, the ionization energy generally increases due to the increased effective nuclear charge. Since Tennessine is in Group 17, it should have a higher ionization energy compared to the elements to its left, but lower than that of the noble gases in Group 18. We can estimate that the first ionization energy of Tennessine will be slightly less than that of Astatine (At), the halogen in Period 6.
3Step 3: Estimate the electron affinity
Electron affinity is the energy change when an electron is added to an atom to form a negative ion. Electron affinity generally increases across a period due to the increased effective nuclear charge. Halogens have high electron affinity since their addition of an electron results in a complete outer energy level. We can expect Tennessine to have a high electron affinity, similar to other halogens, and possibly slightly lower than Astatine's electron affinity.
4Step 4: Estimate the atomic size
The atomic size generally increases as we move down a group due to the addition of electron shells, leading to increased shielding and a larger atomic radius. Tennessine is the heaviest halogen, and we can expect that its atomic size will be larger than that of Astatine, the halogen in Period 6.
5Step 5: Determine the common oxidation state
The common oxidation state for an element can be predicted based on its group number and the number of valence electrons it possesses. Halogens, including Tennessine, typically have an oxidation state of -1 due to their high affinity for electrons. They can gain one electron in chemical reactions to achieve a complete outer energy level resembling the noble gases.
In summary, Element 117 (Tennessine) has the ground-state electron configuration of [Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{5}, high ionization energy, high electron affinity, a large atomic size compared to the other halogens, and a common oxidation state of -1.
Key Concepts
Ground-state electron configurationFirst ionization energyElectron affinityAtomic sizeOxidation state
Ground-state electron configuration
The ground-state electron configuration is crucial to understanding how electrons are arranged in an atom. For Tennessine (Element 117), it follows the order in the periodic table, adding electrons into the appropriate orbitals based on energy level. According to the Aufbau principle, electrons fill the lowest energy orbitals available before moving to higher ones. So, the electron configuration for Tennessine is:\[ [Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{5} \]This notation tells us a few important things:
- The "[Rn]" part denotes that it has the same inner core electron configuration as Radon, which is a noble gas.
- The numbers and letters indicate the distribution of electrons across various shells and subshells.
- "5f^{14}", "6d^{10}", "7s^{2}", and "7p^{5}" represent electrons in different subshells, showing a completely filled 5f and 6d shell, a fully paired 7s orbital, and 5 electrons in the 7p shell.
First ionization energy
Ionization energy is the amount of energy needed to remove an electron from an atom, changing it to a positive ion. This energy is affected by:
Estimating the first ionization energy of Tennessine places it slightly below Astatine, another Group 17 halogen from Period 6. This depends on it having similar but slightly weaker nuclear effects than Astatine due to the addition of another electron shell.
- Electron shielding
- Atomic size
- Nuclear charge
Estimating the first ionization energy of Tennessine places it slightly below Astatine, another Group 17 halogen from Period 6. This depends on it having similar but slightly weaker nuclear effects than Astatine due to the addition of another electron shell.
Electron affinity
Electron affinity measures the energy change when an electron is added to a neutral atom, turning it into a negative ion. Elements with high electron affinity values efficiently attract additional electrons.
Tennessine, as a halogen, is expected to have a high electron affinity. This arises because adding an electron results in a nearly complete outer shell similar to those of noble gases. The effective nuclear charge increases across a period which typically raises electron affinity in Group 17.
Yet, its electron affinity will likely be somewhat lower than Astatine's due to increased shielding from filled subshells, which counteracts the nuclear charge's effect.
Tennessine, as a halogen, is expected to have a high electron affinity. This arises because adding an electron results in a nearly complete outer shell similar to those of noble gases. The effective nuclear charge increases across a period which typically raises electron affinity in Group 17.
Yet, its electron affinity will likely be somewhat lower than Astatine's due to increased shielding from filled subshells, which counteracts the nuclear charge's effect.
Atomic size
Atomic size or atomic radius is influenced by electron arrangement and nuclear charge. As you proceed down a group in the periodic table, atomic size typically increases. For Tennessine, this means it should be larger than Astatine, the halogen just above it in Group 17.
This increase in size is due to the following factors:
This increase in size is due to the following factors:
- New energy levels (or shells) that are added with each period increase.
- Increased shielding effect from the inner layers of electrons.
- A decrease in the effective nuclear charge felt by the outermost electrons.
Oxidation state
The oxidation state of an element tells us about the number of electrons it can gain or lose during a chemical reaction. For halogens like Tennessine, the common oxidation state is
-1.
This state results from:
This state results from:
- Their tendency to gain one electron to fill their outermost p orbital.
- High electron affinity factor due to the half-full outer electron shell which seeks completion.
Other exercises in this chapter
Problem 104
(a) One of the alkali metals reacts with oxygen to form a solid white substance. When this substance is dissolved in water, the solution gives a positive test f
View solution Problem 105
Zincin its \(2+\) oxidation state is an essential metal ion for life. \(\mathrm{Zn}^{2+}\) is found bound to many proteins that are involved in biological proce
View solution Problem 108
We will see in Chapter 12 that semiconductors are materials that conduct electricity better than nonmetals but not as well as metals. The only two elements in t
View solution Problem 111
One way to measure ionization energies is ultraviolet photoelectron spectroscopy (PES), a technique based on the photoelectric efect. (Section 6.2) In PES, mono
View solution